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Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Nobody: 11:18am On Apr 16, 2013 |
Adex097: 1)If y=√x^2 + 1 , then dy/dx at X=-1 is1.B 2.A 3.D |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Ortarico(m): 11:22am On Apr 16, 2013 |
Adex097: 1)If y=√x^2 + 1 , then dy/dx at X=-1 is 1. B 2. B 3. D correction needed ASAP |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Adex097: 8:02pm On Apr 16, 2013 |
Ortarico:lol..shine ur eye well well |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Adex097: 9:57pm On Apr 16, 2013 |
Ortarico:score: 2/3 Sir Bussy: 1.B 2.A 3.Dscore: 3/3 tshabalala: b/a/dscore: 3/3 Edis4christ:score; 2/3 papindinho: the way the number one is composed is nt that clearscore; 2/3 |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Adex097: 12:12am On Apr 17, 2013 |
1) The Sine, cosine and tangent of 240' are, respectively A. √3/2, -1/2 and √3 B. -√3/2 , -1/2 and √3 C. -√3/2 , 1/2 and -√3 D. √3/2 , 1/2 and √3 2)Which of the following have the same values as sin 15' ? (I) Sin 165' (ii) Sin 285' (Iii)Sin (-15') (iv)Sin(-195') A. I and ii only B. Iii and iv only C. I and iii only D. I and iv only 3). Two of the angles of a triangle are 120' ans 45' . If the side facing the angle 45' is 10cm long , then the side facing the angle 120' is A. 5√3 cm B. 5√6 cm C. 10√2 cm D. 20 cm |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Ortarico(m): 7:58am On Apr 17, 2013 |
Adex097: 1) The Sine, cosine and tangent of 240' are, respectively 1. B 2. D 3. B oga Adex post the former correction nah |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Adex097: 9:11am On Apr 17, 2013 |
^^^^ sorry...I don forget |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by papindinho(m): 11:37am On Apr 17, 2013 |
Adex097: 1) The Sine, cosine and tangent of 240' are, respectively1*b 2*d 3*b |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by nkenta(m): 12:25pm On Apr 17, 2013 |
JAMB ASSIST 2013
|
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by tboy08: 1:43pm On Apr 17, 2013 |
Wao it has been a while looking forward to seeing a maths thread like this.....hmm infact,i've missed alot |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by tboy08: 1:45pm On Apr 17, 2013 |
My first question on this thread: write the two's compliment of the binary 11001? |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by tboy08: 2:14pm On Apr 17, 2013 |
Integrate 2x + 4/ x^2 + 4x + dx a)log x + 4 + c b)in x^2 + 4x + c c) 2x/4 + c d) 2x + 4 /2 + c |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Ortarico(m): 5:11pm On Apr 17, 2013 |
t.boy007: two's complement of 11001= 00110 t.boy007: b |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Edis4christ(m): 11:22am On Apr 18, 2013 |
Adex097: 1) The Sine, cosine and tangent of 240' are, respectively1) B 2) D 3) B |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Adex097: 2:17pm On Apr 19, 2013 |
Ortarico:score:::::3/3 papindinho: 1*b 2*d 3*bscore:::::3/3 Edis4christ:score:::::3/3...... Kudos to you all |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Adex097: 2:19pm On Apr 19, 2013 |
I'm so so sorry guys...I've been busy. Lately |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Adex097: 2:34pm On Apr 19, 2013 |
Which of the following angles cannot be constructed with a ruler and a pair of compasses only? A. 105' B. 112 1/2' (one hundred nd twelve and half degree) C. 115' D. 120' |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by mathefaro(m): 6:56am On Apr 20, 2013 |
Adex097: Which of the following angles cannot be constructed with a ruler and a pair of compasses only?of coz, dat should be C-115° although you know what u've used there is not degrees but minutes, talking about (') |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by mathefaro(m): 7:03am On Apr 20, 2013 |
1. A Gp of a positive terms and a Ap have same first term.the sum of their first terms is 3 the sum of their second term is 3/2, and the sum of their third term is 6.find the sum of their fifth terms 2. A trader bought 30articles.he sold 20 of them at a gain of 16% and sold the remainder at a loss of 4%.find the percentage profit/loss on the articles. 3. Find the value of x.if (x+3) ^3 + (x+4) ^3 = (2x+7) ^3 I'm sorry for my questions haven't got options. just show ur workinz |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by sazy(m): 6:53pm On Apr 20, 2013 |
1.B 2.D 3.B |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by emekakelvin(m): 1:35pm On May 05, 2013 |
Guy i just try my luck mathefaro: 1. A Gp of a positive terms and a Ap have same first term.the sum of their first terms is 3 the sum of their second term is 3/2, and the sum of their third term is 6.find the sum of their fifth terms(1)17 (2) no idea (3)7+square root of 241/4 and 7-squareroot of 241/4 |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Ortarico(m): 11:36am On May 16, 2013 |
mathefaro: 1. A Gp of a positive terms and a Ap have same first term.the sum of their first terms is 3 the sum of their second term is 3/2, and the sum of their third term is 6.find the sum of their fifth terms choi, Let's Go There (LGT)... 1 first term: a+a=3 a= 3/2 second term: ar+a+d= 3/2 ar+a= 3/2 - d multiplyn thru by 2: 2a (r+1)= 3-2d but a= 3/2; simplifyn gives: 3+3r= 3 - 2d 3r= -2d d= -3r/2..... 3rd term gives: a+2d+ar2= 6 simplifyn givs. . . a(1+r2)= 6-2d giving 3/2(1+r2)= 6-2d reduce by multiplyn thru by 2. . . 3r2= 9 - 4d but d= -3r/2 substitutn givs 3r2-6r-9=0 r2 - 2r - 3=0 r=3 or -1....but r=3 since term r is positive, hence a=3/2, r=3 and d=-9/2 hence d sum of their 5th term; ==> a+4d+ar4= 122 courtesy My Oga At The Top; Sir Onioshine 2 Likes |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Ortarico(m): 12:43pm On May 16, 2013 |
2. Sale of 20 articles at a gain of 16%= 116% : 20*116/100= 23.2% actual gain Sale of 10 articles at a loss of 6%= 96% :10*96/100= 9.6% actual gain p/l= 100-(23.2+9.6) p/l= 100-32.8 loss= 67.2%....in my own sha |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by mathefaro(m): 12:58pm On May 16, 2013 |
Ortarico:Good work. Welldone, but you made a slight mistake in your final answer. please check and make necessary corrections |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by mathefaro(m): 1:20pm On May 16, 2013 |
Ortarico: 2.Not convincing enough, you can do better. It's wrong,i'm sorry |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Ortarico(m): 1:29pm On May 16, 2013 |
3. a3+b3= (a+b)^3 - 3ab(a+b) sum of powers of 3 :let a= x+3 and b= x+4 substitutn gives: (x+3)^3 + (x+4)^3= (2x+7)^3 - 3(x+3)(x+4)(2x+7) ==> (2x+7)^3 - 3(x+3)(x+4)(2x+7) ==> (2x+7)^3 ==> 3(x+3)(x+4)(2x+7)=0 dividng both sides by 3 and solving the above gives: x= -3, -4 or -7/2 Courtesy; Oga At The Top, Sir Onioshine |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Nairalanda(m): 1:44pm On May 16, 2013 |
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Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by mathefaro(m): 1:57pm On May 16, 2013 |
Ortarico: 3.Bravo, absolutely correct |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Ortarico(m): 2:36pm On May 16, 2013 |
mathefaro: |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Nobody: 5:14pm On May 16, 2013 |
^ @Onioshine, solved it correctly! It's just that the answer is 105 and NOT 122==>> The common ratio of the GP, r = 3 since the GP is positive Since 2d = -3r, Then the corresponding common difference of the AP, d = -9/2. Sum of their 5th terms is => GP 5th term=> ar^4 AP 5th term=> a + 4d Sum of 5th terms of both series = ar^4 + a + 4d. Substituting r, d and a for =>> r = 3, d = -9/2 and a = 3/2, The sum of their 5th terms yields => = ar^4 + a + 4d = (3/2)(3)^4 + 3/2 + 4(-9/2) = 243/2 + 3/2 - 18 = 246/2 - 18 = 105 Hence the sum of the series 5th terms is 105. 1 Like |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by Ortarico(m): 6:47pm On May 16, 2013 |
doubleDx: ^ ok, thanks for making the correction |
Re: Mathematics Tutorial. For Utme, Post-utme & Other Related Examinations by mathefaro(m): 7:13pm On May 16, 2013 |
doubleDx: ^Wrong, check ur substitution, u made a slight error. d ans is 105 |
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