I want to create a c/c++ program that accepts an unknown set of integers at runtime but I dont want to declare the size of the array or pointer in my program. I want the program to be dynamic enough to resize itself to the user inputs.

I don't want a declaration like a[100] or a = new int[100] or a*int=a*malloc[100], etc because of the lenght 100 (or any other number).

My question is if it is possible for a dataype like integer to read values at runtime with unknown lenght?

It is possible with dynamic array allocation. The array is stored in the heap.

So remember to free or delete it.

In c++ array is dynamically assigned using new which return a pointer. For example.
Int* myarray = new int[num];

In c u using malloc to dynamically assigned memory at run time.

You can google for more clarity.

Or Just use a Linked List.

Marsatto:
I want to create a c/c++ program that accepts an unknown set of integers at runtime but I dont want to declare the size of the array or pointer in my program. I want the program to be dynamic enough to resize itself to the user inputs.

I don't want a declaration like a[100] or a = new int[100] or a*int=a*malloc[100], etc because of the lenght 100 (or any other number).

My question is if it is possible for a dataype like integer to read values at runtime with unknown lenght?

@tjones007 has given u the right answer.

tjones007:
It is possible with dynamic array allocation. The array is stored in the heap.

So remember to free or delete it.

In c++ array is dynamically assigned using new which return a pointer. For example.
Int* myarray = new int[num];

In c u using malloc to dynamically assigned memory at run time.

You can google for more clarity.

You don't seem to understand the question. Based on your answer I will still need to enter a "num" at runtime. I said I want the program to only stop when there is a delimiter (maybe -1). Based on your answer if my entry exceeds the num the program will not work. Your reply is almost same as my illustration only that I used "n".

Marsatto:


You don't seem to understand the question. Based on your answer I will still need to enter a "num" at runtime. I said I want the program to only stop when there is a delimiter (maybe -1). Based on your answer if my entry exceeds the num the program will not work. Your reply is almost same as my illustration only that I used "n".

Ooh I get you. Why not use linkedlist.

Or you can create your customize list with a that assign a static array then later change the size of the array when the value have exceed it.

Marsatto:
I want to create a c/c++ program that accepts an unknown set of integers at runtime but I dont want to declare the size of the array or pointer in my program. I want the program to be dynamic enough to resize itself to the user inputs.

I don't want a declaration like a[100] or a = new int[100] or a*int=a*malloc[100], etc because of the lenght 100 (or any other number).

My question is if it is possible for a dataype like integer to read values at runtime with unknown lenght?

am stil having the same problem. I also find it dificut to alocate memory to array of arbitrary set of elements. May b u shud gv ur number so we can discus it more in whatsap. Any way my num is 08036407597. Snd me a whatsap msg. Tnks

Marsatto:
I want to create a c/c++ program that accepts an unknown set of integers at runtime but I dont want to declare the size of the array or pointer in my program. I want the program to be dynamic enough to resize itself to the user inputs.

I don't want a declaration like a[100] or a = new int[100] or a*int=a*malloc[100], etc because of the lenght 100 (or any other number).

My question is if it is possible for a dataype like integer to read values at runtime with unknown lenght?

No. Just leave it vacant. Ie. A[ ]

Marsatto:


You don't seem to understand the question. Based on your answer I will still need to enter a "num" at runtime. I said I want the program to only stop when there is a delimiter (maybe -1). Based on your answer if my entry exceeds the num the program will not work. Your reply is almost same as my illustration only that I used "n".

my friend why make life difficult for urself.

u have two simple options;

1. use a vector

2. Write ur own dynamic array.( view my old post u will see an example u can adapt.

note:a vector is a dynamic array.

tjones007:
It is possible with dynamic array allocation. The array is stored in the heap.

So remember to free or delete it.

In c++ array is dynamically assigned using new which return a pointer. For example.
Int* myarray = new int[num];

In c u using malloc to dynamically assigned memory at run time.

You can google for more clarity.

you can do as quoted above. but instead of allocating the entire array, you can use realloc to dynamically resize the array after every n data input. say 10 or more. you have another variable tracking how much data has been entered. when you get your delimiter, you can now use to realloc to fit the array perfectly.

////////////////////////////////////////////////////////////////
int counter, arraysize;
unsigned char *dataArray, temp;

counter = arraysize = 0;
dataArray = malloc(10);

while((temp = get_data_routine()) != -1) //continue loop until delimiter found
{
if(counter == arraysize) //if counter catches up with arraysize, increase array by 10 bytes
{
arraysize += 10; //new array size
dataArray = realloc(arraysize);
}

*(dataArray + counter) = temp;
counter += 1;
}

*dataArray = realloc(counter); //finally resize array to fit

................................

Op Check mnairaland answer. Use a Vector of ints. You can Push_back till mummy calls !