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Tough Question For The Mathematical Genius - Education - Nairaland

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Tough Question For The Mathematical Genius by Nobody: 10:39pm On May 19, 2015
How many trials would you need to make to be 100% sure you can unlock a box with a 3-digit combination lock with each part of the lock having digits ranging from 0 to 9?
Re: Tough Question For The Mathematical Genius by HungerBAD: 10:40pm On May 19, 2015
Are you trying to break into your company's SAFE?

3 Likes

Re: Tough Question For The Mathematical Genius by Nobody: 10:42pm On May 19, 2015
HungerBAD:
Are you trying to break into your company's SAFE?
hahaha. no oh
Re: Tough Question For The Mathematical Genius by emekakelvin(m): 11:04pm On May 19, 2015
120 times

1 Like

Re: Tough Question For The Mathematical Genius by Nobody: 11:07pm On May 19, 2015
emekakelvin:
120 times
pls can you explain how you arrived at that answer. thanks
Re: Tough Question For The Mathematical Genius by Nobody: 11:25pm On May 19, 2015
1000
Re: Tough Question For The Mathematical Genius by emekakelvin(m): 11:25pm On May 19, 2015
justirich:
pls can you explain how you arrived at that answer. thanks
we were given the figure 0-9 which equal 10 different digit when counted. We were told to choose 3 d
iff number to unlock the box and this gives us a clue i.e we can use Combination to solve the queston.
Therefore, we have 10 Combination 3=n!/(n -r)! r!
where r=3 and n= 10
10!/(10-3)! 3!
10!/7! 3!
10. 9. 8. 7!/ 7! 3!
10.9.8/3.2.1
720/6= 120

!= factorial and (.) = multiplication

1 Like

Re: Tough Question For The Mathematical Genius by Nobody: 12:06am On May 20, 2015
emekakelvin:
we were given the figure 0-9 which equal 10 different digit when counted. We were told to choose 3 d
iff number to unlock the box and this gives us a clue i.e we can use Combination to solve the queston.
Therefore, we have 10 Combination 3=n!/(n -r)! r!
where r=3 and n= 10
10!/(10-3)! 3!
10!/7! 3!
10. 9. 8. 7!/ 7! 3!
10.9.8/3.2.1
720/6= 120

!= factorial and (.) = multiplication

yeah well done Sir

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