hello guys and my fellow python gurus..
I wrote this simple guess game in python using a while loop and random module...
the game asks you to guess what it's thinking of then you enter the number,however when you make a wrong guess, it picks another random number..
the issue is, since I wrote it, Av won only about 3 times out of about 300 guesses..I want you guys to bring ideas on how to make the game more winnable because the chances of making a guess are only 20...

#-*-coding:utf8;-*-
#qpy:3
#qpy:console

import random
print (""
print("this is a guessing game,you have [ 20 ] attempts"
print("this is v.3 in attempt to make the game easy.. "
print(""
print(" LETS PLAY THE GAME"
print (""
number=random.choice(range(1,150))
Max = 150
minn =1
failed = 0
left = 20
while True:

guess=input("GUESS THE NUMBER AM THINKING OF/>> "
if guess.isalpha():
print (" sorry,you must enter a digit "
print(""
else:
if int(guess) == number:
print(""
print("###################################"
print("# CONGRATULATIONS #"
print("# YOU WON #"
print("###################################"

break

elif int(guess) > Max:
print ("your guess is a bit too high...."
print(""

elif int(guess) < minn:
print (" your guess is a little too low..."
print(""

elif failed == 20:
print (" you have exhausted your chances..."
print(""
print ("##################################"
print ("# GAME OVER #"
print("##################################"
print(""
print(" [ game by VITRIOL ] "
break

elif left==1:
print("wrong guess, try again .. "
failed+=1
left-=1
print("your last attempt... "
print(""

else:
print("wrong guess, try again .. "
failed+=1
left-=1
print (left," attempt(s) left.."
print (""

this is the python code..

reduce the range of the numbers. the probability of guessing a number between 1 and150 is quite low.(1- 30 should be fairly easy) then you should tell your players the range to guess from

I know, but I don't wanna reduce the range, am thinking about making 4 picks from behind the scenes so that each guess is checked against the picks for at least a win

emilykel:
I know, but I don't wanna reduce the range, am thinking about making 4 picks from behind the scenes so that each guess is checked against the picks for at least a win

you either reduce the range or you increase the no of failed attempts. Why did you use Random instead of importing randint from Random, since you are using random integers

Also i think you should have used
while guess != 0

randint() and random.choice(range()) are the same, besides Av used randint before...
I also see no reason to use
while guess!=0

You may try allowing the user enter more than one number and then check if any if them matches the guess.

I have also similar game written some months back but the guess is between 1 to 20.

I don't know how the [code] tag works here so i recommend uploading the file you need help on some other time. my opinion though

use a "for" loop and a list to get four or more random numbers from the Computer and then check the players answer to see if it matches any of those numbers in the list, if true then the player won

guess_list = []
for i in range(4):
guess = random.randrange(1,1150)
guess_list.append(guess)

answer = int(raw_input("Enter Guessed number")
if (answer in guess_list):
player won
else:
player lost

this is a thing I did while am new to python
solution....
decide random number outside the while loop
ex:
number = random.choice(range(200))
run = 0
while run !=0:
code ...
if choice > number :
print number is lower
if choice is < number :
print number is. higher

if choice == number:
print yes

run = 1