x²+(x²-1)^1/2=1
best of luck

dggh

Hi Poster,

your question shoulde be simplify the expression

@ EHIDO, It is not an expression,the poster is right.It is an equation because of the equality sign.
To start with, square both sides to get polynomials in X^4+, =1 and solve the polynomials for different values of x by examination

check this out
x^2+ ( x^2 - 1)^1/2 = 1
(x^2+(x^2-1)^1/2)^1/2 = 1^1/2
x + ( X^2 - 1 ) = 1
x + x^2 - 1 = 1
x^2 + x - 2 = 0
.
, (x+2) = 0
(x - 1) = 0
X = -2 or 1.

The equality sign was not there yesterday, trust me I know an equation when I see one

The equality sign was not there yesterday, trust me I know an equation when I see one

but i just solved it today and i got 1 to be my final answer.

I put Logx to both sides
Remember LogxX = 1
X^2 + ( X^2 - 1 ) ^ 1/2 = 1
logx X^2 +( logx( X^2 - 1 ) ^ 1/2) = logx X^1
2logx X + 1/2( logx( X^2 - 1 )) = 1logx X
2logx X + (1/2(logx X^2) - (1/2 logx 1 )) = 1logx X
2logx X + ((1logx X) - (1/2(logx1) ) = 1logx X
2logx X  - (1/2(logx 1) ) = 1logx X - 1logx X
2logx X  - (1/2(logx 1) ) = 0
2logx X = (1/2(logx 1) )
logx X^2 = logx 1^(1/2)
Divide both sides by Logx
u are left with
X^2 = 1^(1/2)
X^2 = Sq rt(1)
X^2 = 1
X = Sq rt(1)
X = 1

@napolie, use logarithm to simplify

olayhincar:

The equality sign was not there yesterday, trust me I know an equation when I see one

but i just solved it today and i got 1 to be my final answer.

I put Logx to both sides
Remember LogxX = 1
X^2 + ( X^2 - 1 ) ^ 1/2 = 1
logx X^2 +( logx( X^2 - 1 ) ^ 1/2) = logx X^1
2logx X + 1/2( logx( X^2 - 1 )) = 1logx X
2logx X + (1/2(logx X^2) - (1/2 logx 1 )) = 1logx X
2logx X + ((1logx X) - (1/2(logx1) ) = 1logx X
2logx X  - (1/2(logx 1) ) = 1logx X - 1logx X
2logx X  - (1/2(logx 1) ) = 0
2logx X = (1/2(logx 1) )
logx X^2 = logx 1^(1/2)
Divide both sides by Logx
u are left with
X^2 = 1^(1/2)
X^2 = Sq rt(1)
X^2 = 1
X = Sq rt(1)
X = 1

i never read the question carefully before attempting it . i just went ahead and differentiate it. you're right olayhincar

Now the question
x² + (x² - 1)^1/2= 1
(x² - 1)^1/2 = 1 - x²
Squaring both sides and expanding we get
x² - 1 = x⁴ - 2x² + 1
Collecting like terms and simplifying we get
x⁴ - 3x² + 2 = 0
Now this is a polynomial of the 4th degree in even consecutive indices to solve this we divide with a quadrant,
so using the trial method lets take x² - 1
Dividing with this we get,
x² - 2 as the answer
therefore,
(x² - 1)(x² - 2)
In which case

x = +/-1 or the square root of 2

Check:
x² + (x² - 1) = 1
Substituting x = 2^1/2
(2^1/2)² + ({2^1/2}² - 1)^1/2
Gives,
2 +/- 1^1/2
which gives,
2 +/- 1
2-1=1
You can also check the other value yourself for confirmation

different efiko nd ò je wè with different method nd answer.

gen2dan:

Now the question
x² + (x² - 1)^1/2= 1
(x² - 1)^1/2 = 1 - x²
Squaring both sides and expanding we get
x² - 1 = x⁴ - 2x² + 1
Collecting like terms and simplifying we get
x⁴ - 3x² + 2 = 0
Now this is a polynomial of the 4th degree in even consecutive indices to solve this we divide with a quadrant,
so using the trial method lets take x² - 1
Dividing with this we get,
x² - 2 as the answer
therefore,
(x² - 1)(x² - 2)
In which case

x = +/-1 or the square root of 2

Check:
x² + (x² - 1) = 1
Substituting x = 2^1/2
(2^1/2)² + ({2^1/2}² - 1)^1/2
Gives,
2 +/- 1^1/2
which gives,
2 +/- 1
2-1=1
You can also check the other value yourself for confirmation

you are the only one getting it but x4 - 3x2 + 2 = 0 , it has to be x4 - 3x2 - 2 = 0

@gen2dan
igi iwe

you are too good!!!!!!!!

omo la toro iwe la bi

bata re a dun ko ko ka

@ronnykay, uhmmmnmm!!! Lol.[color=][/color]

@gen2dan
U are blessed!!!

Na wa o! Pastor. God go bless us jare. Lol.

Solve thie:
3^x + 4^x = 5^x


** Double dare you guys

bayedero:

Solve thie:
3^x + 4^x = 5^x


** Double dare you guys

Professor of Maths, Na u Know Maths Pass Everybody, A1 Perpendicular na e u get for secondary school.

these are secondary school mathematics. Boys

Free_rhyme:

Professor of Maths, Na u Know Maths Pass Everybody, A1 Perpendicular na e u get for secondary school.

i will really appreciate it if the poster of this question could give the solution with workings since no efiko online has been able to solve for x in the eqn. looking forward to hear from you POSTER.

what's the shit? X= -2 or x=1.

x^2 + (x^2 - 1)^1/2 = 1
squaring both sides of d eqn
we have : x^4 + x^2 - 1 = 1
x^4 + x^2 = 1+1
x^2(x^2+1) = 2
i.e x^2 = 2 or x^2+1 = 2
x=sqrt(2) or x^2=2-1
x=1.414 or x^2=1
x=1.414 or x=sqrt(1)
x=1.414 or x=1

pls u pple shld include ur schools when solving problems so we kno d quality of ur lecturers and school as well

bayedero:

Solve thie:
3^x + 4^x = 5^x


** Double dare you guys

this is high school math. just looking at the problem will tell you that X =2


can any body solve this simple Differential Equation

y^'' - 4y^' + 13y = 0. obtain the value of y

y^'' = d²y/dx²

y^' = dy/dx