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Nairaland Forum / Nairaland / General / Education / Tutor Partners In Senior Secondary Schools Needed For Serious Business (375 Views)
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Tutor Partners In Senior Secondary Schools Needed For Serious Business by Julivas(m): 4:54pm On Mar 21, 2017 |
Good day to you all. My able tutors, you are welcome to this thread. Without beating around the bush, the business is all about organising "preparatory examination" on Mathematics for students that are about to write waec amd neco exams. As we all know, most student find it difficult in passing this subject with ease. Due to this, up to standard questions have been carefully crafted out and solved one by one to serve as quick and comprehensive revision for students. How it works: All interested students will write the preparatory exam after which their scripts will be marked amd be given to them back. Then, then solutions to the examination will be given to each students for proper correction and revision. Your responsibilities as a tutor: * Inform the prospective students about this * Enrolment of all interested students. * Supervision of students during the examination * Scripts marking * Giving out the solutions to the students which shall be sent to the teacher. Cost implication to the students Each student is to pay #500, this will cover all logistics Benefit of the teacher Each teacher will be given #100 per student. The more the students the higher the income Contact me on whatsapp 08033052962 Write Mathematics when you contact me on whatsapp Please serious fellow only Thanks. This is a sample of what to expect: Question If 2x -y = 5 and 3x + y = 10. Find the value of 4x + 3y? A)14 B)12 C)21 D)15 E)16 Solution 2x - y = 5 3x + y = 10 Solve simultaneously 2x - y = 5.........eq 1 3x + y = 10......eq 2 Add eq 1 and 2 together 2x - y = 5.........eq 1 3x + y = 10......eq 2 ....................... 5x + 0 = 15 5x = 15 Divide both sides by the coefficient of x 5x/5 = 15/5 x = 3 To find y, put x = 3 in any of the equations Using equation 2 3x + y = 10.......eq 2 3(3) + y = 10 3×3 + y = 10 9 + y = 10 Collect the like terms y = 10 - 9 y = 1 Therefore, x =3 and y = 1 To find the value of 4x + 3y, put the value of x and y in the expression 4x + 3y = 4(3) + 3(1) = 4×3 + 3×1 = 12 + 3 = 15. |
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