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Your Age By Creepy Math by lilvonz(m): 9:44am On Apr 09, 2007
It takes less than a minute. Work this out as you read. Be sure you don't read the bottom until you've worked it out! This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to have chocolate (more than once but less than 10).

2. Multiply this number by 2 (Just to be bold)

3. Add 5 (for Sunday).

4. Multiply it by 50 I'll wait while you get the calculator,

5. If you have already had your birthday this year add 1755,
If you haven't, add 1754,

6. Now subtract the four digit year that you were born,

You should have a three digit number.

The first digit of this was your original number (i.e., how many times you want to have chocolate each week).

The next two numbers are,

YOUR AGE!!! (OH YES, IT IS!!!)

THIS IS THE ONLY YEAR (2005) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS.
Re: Your Age By Creepy Math by fatliar(m): 11:24am On Apr 09, 2007
am so sorry you got it wrong hhahahahahahah i got a different age
but u tried cos i almost got there
Re: Your Age By Creepy Math by iice(f): 3:05pm On Apr 09, 2007
lilvonz:

THIS IS THE ONLY YEAR (2005) IT WILL EVER WORK, SO SPREAD IT AROUND WHILE IT LASTS.

undecided undecided Remind me again why the earth spins?
Re: Your Age By Creepy Math by busygirl(f): 4:11pm On Apr 09, 2007
I tried it, although i didn't get the number of my age *QUITE CLOSE*but i did get the number of times i would love to have chocolates
Re: Your Age By Creepy Math by lilvonz(m): 4:52pm On Apr 11, 2007
Notice that the stuff work for only your age in 2005
Re: Your Age By Creepy Math by snazzydawn(f): 1:09pm On Apr 12, 2007
this is tres correct. Gave me my age precisely.Really creepy.
Re: Your Age By Creepy Math by dtwsola(m): 12:37am On Apr 15, 2007
Of course it won't work in 2007. If you follow the instructions, using the numbers given, you should get your age at this time in 2005. There are three ways that you won't get your age in 2005

1. If you choose a non-integer (decimal) amount of times to eat chocolate e.g. 2.5
2. If you were older than 100 in 2005
3. If you are retarded and can not do basic math

This is not creepy. When it asked for the birthyear I already knew what was going on.
Think about it: Let x be the no of times you want chocolate where 1<x<=10, and y be your birth year

For those whose birthdays have passed, the formula becomes
(2X+5)*50 + 1755 - y
= 100x + 250 +1755 -y
= 100x + (250 + 1755) - y
= 100x + (2005 - y)


for those whose birthdays have yet to come, the formula becomes
(2x +5)* 50 + 1754 -y
=100x + (250 + 1754) -y
= 100x + (2004-y)

Note: Since y is your birth year, then (2005 -y) will be your age in 2005 if you were born in '05, and your bithdate has passed. Otherwise, (2004 -y) will be your age. And note that 100x can only be either 200, 300, 400,, , 900, because of the restrictions on x. That means you are adding your birthday to a number divisible by 100, hence the first digit will be whatever x number you chose, and the last two digits will be your 2005 age.


Of course this whole thing can be modified for the year 2007, but you have to use 1757 if your birthday has passed already, and 1756 if you have yet to celebrate your birthday.

Sorry to piss on the parade.
Re: Your Age By Creepy Math by Nella(f): 6:42pm On Aug 17, 2007
dtw_sola:

Of course it won't work in 2007. If you follow the instructions, using the numbers given, you should get your age at this time in 2005. There are three ways that you won't get your age in 2005

1. If you choose a non-integer (decimal) amount of times to eat chocolate e.g. 2.5
2. If you were older than 100 in 2005
3. If you are retarded and can not do basic math

This is not creepy. When it asked for the birthyear I already knew what was going on.
Think about it: Let x be the no of times you want chocolate where 1<x<=10, and y be your birth year

For those whose birthdays have passed, the formula becomes
(2X+5)*50 + 1755 - y
= 100x + 250 +1755 -y
= 100x + (250 + 1755) - y
= 100x + (2005 - y)


for those whose birthdays have yet to come, the formula becomes
(2x +5)* 50 + 1754 -y
=100x + (250 + 1754) -y
= 100x + (2004-y)

Note: Since y is your birth year, then (2005 -y) will be your age in 2005 if you were born in '05, and your bithdate has passed. Otherwise, (2004 -y) will be your age. And note that 100x can only be either 200, 300, 400,, , 900, because of the restrictions on x. That means you are adding your birthday to a number divisible by 100, hence the first digit will be whatever x number you chose, and the last two digits will be your 2005 age.


Of course this whole thing can be modified for the year 2007, but you have to use 1757 if your birthday has passed already, and 1756 if you have yet to celebrate your birthday.

Sorry to piss on the parade.

na mathematics lesson be this or what
Re: Your Age By Creepy Math by Scopium: 8:53pm On Oct 25, 2007
iice:

undecided undecided Remind me again why the earth spins?
It spins because you have too much liquor in your system
Re: Your Age By Creepy Math by iice(f): 3:05am On Oct 26, 2007
Wow wow wow. . .ol' li'l me is da bomb! grin grin grin
Notoriety rocks!! grin grin bwahahahhaha

and in droves they descend grin grin grin
Re: Your Age By Creepy Math by chychy(f): 5:30pm On Nov 19, 2007
[list]
[li]c'est tres creepy

i did it n it gave me my age in 2005, some stuffz
[/li]
[li][/li]
[/list]

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