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Mathematics obj
1EBDCAACBAD
11DEAECBECBD
21DDB

(3a)
P=100I/RT=100*30,000/4*3
P=N250,000
(3b)
#7000 T0 FRANCS
8FRANS= #1
?FRANCS =7000
CROSS MULTIPLY
=#56,000 FRANCS
SPENDING 49,400 FRANCS
56,000-49,400 = 6600
CONVERTING 6,600 FRANCS TO # AT 10 FRANCS TO 1#
10 FRANCS—– 1#
6600 FRANCS—?#
=6,600/10 X1
========================
(4i)
difference in latitude=36degree + 36 degree =72degree
distance travelled=@/360*2pir
=72/360*2*22/77*64
=20275200/2520
=8045.71
=8050km(35.f)
(4ii)
given that speed =800km/hr
distance travelled =804571km
time=distance travelled/speed
=8045.71/800
=10.057
=10hrs(to the nearest hour)
CLICK HERE FOR THE IMAGE
================
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(5)
Put In tabular Form:
Mark- 21-25,26-30,31-35,36-40,41-45,46-50
F- 6,8,12,4,6,4=40
X- 23,28,33,38,43,48
FX- 138,224,396,152,258,192=1360
Class Boundaries- 20.5-20.5, 25.5-30.5,35.5-40.50,40.5-45.5
(5i)
MEAN
(X)=EFX/EF=1360/40=34
MODE
L1+[Fm-Fa/2fm-fa-fb]c
=30.5+[12-8/2(12)-8-4]5
=30.5+[4/12]5
=30.5+1.67
=32.17and===========================
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