Good evening nairaland please I need help with this math assignment
1.A bag contains 36 coins.the coins are a mixture of one dollar coin and 50 cents coins.the total value of the coins in the bag is $26.50.how many one dollar coin are there in the bag.
2.5 times a certain number take away 2 times another number gives 15.the sum of the two numbers is 6 and half.find the two numbers

on It

emmysolo2001:
Good evening nairaland please I need help with this math assignment
1.A bag contains 36 coins.the coins are a mixture of one dollar coin and 50 cents coins.the total value of the coins in the bag is $26.50.how many one dollar coin are there in the bag.
2.5 times a certain number take away 2 times another number gives 15.the sum of the two numbers is 6 and half.find the two numbers

1. There are 17 one dollar coins and 19 fifty cents coins

2. This is a simultaneous equation:
5x-2y=15.......eqn (1)
x+y = 6½ .......eqn (2)

Solving this, x=4 and y=2½

Solution to question 1

100cents = 1 dollar.

Let x represent the number of 50cent coins
Let y represent the number of 1 dollar (100cent) coins
Total coins = 36
x + y = 36............................ equation (1)
Total value of coins = $26.50
$26.50 = 26 dollars + 0.50 dollar
Convert$ 26.50 to cent = 26.50dollars * 100cents = 2650cents

100x + 50y = 2650 total value of 1 dollar coins plus 50 cent coins…............ equation (2)
Using elimination method multiple equation (1) by 100

100x + 100y = 3600...................... equation (3)

equation (3) minus equation (1)

Taking it term by term from both equations (3) and (1)

For x:
100x - 100x = 0

For y:
100y - 50y = 50y

For the constant terms on the Right Hand Side of both equations:

3600 - 2650 = 950

Therefore 50y = 950

Divide both sides by 50 to get y

(50y/50) = (950/50)
y = 19

The number of 1 dollar coins is 19

Plug 19 into equation (I) to get x:

x + 19 = 36

Subtract 19 from both sides of the equals sign to get x,

x + 19 - 19 = 36 - 19 NB: +19 - 19 = 0

x = 17

Solution to question 2.

5 times a certain number. Let that certain number be u so 5*u = 5u.
2 times another number. Let that another number be v so 2*v = 2v.
So take away 2v from 5u = 5u -2v gives 15

Therefore 5u - 2v = 15............ equation (1)

The sum of the two numbers ( u and v) is 6(1/2).

Thus u + v = 6(1/2)................... equation (2)

Convert 6(1/2) to a proper fraction = 13/2

Plug it back to equation (2)

u + v = 13/2............ equation (3)

Clear fraction in equation (3) by multiplying all the terms on both sides of the equals sign by 2.
2u + 2v = 13................. equation (4)


Now we have

5u - 2v = 15…....... equation (I)
2u + 2v = 13............ equation (4)


By method of elimination, add equation (I) and equation (4)


For u terms:
5u + 2u = 7 u

For v terms:
-2v + 2v = 0 ( v is eliminated).

For constant terms:
13 + 15 = 28


Thus, 7u = 28
Divide both sides by 7 to get u
(7u/7) = 28/7

u = 4

Plug the value of u into equation (I) to get the value of v

5*4 - 2v = 15
20 - 2v = 15

Subtract 20 from both sides of the equals sign to get v, thus
20 - 2v - 20 = 15 - 20

20 - 20 - 2v = 15 - 20

-2v = -5
Divide both sides of the equals sign by (-2)

(-2v/-2) = -5/-2

(-)at the numerator will cancel (-)at the denominator
v = 5/2 or 2(1/2)

OutOfTheAshes:
Solution to question 2.

5 times a certain number. Let that certain number be u so 5*u = 5u.
2 times another number. Let that another number be v so 2*v = 2v.
So take away 2v from 5u = 5u -2v gives 15

Therefore 5u - 2v = 15............ equation (1)

The sum of the two numbers ( u and v) is 6(1/2).

Thus u + v = 6(1/2)................... equation (2)

Convert 6(1/2) to a proper fraction = 13/2

Plug it back to equation (2)

u + v = 13/2............ equation (3)

Clear fraction in equation (3) by multiplying all the terms on both sides of the equals sign by 2.
2u + 2v = 13................. equation (4)


Now we have

5u - 2v = 15…....... equation (I)
2u + 2v = 13............ equation (4)


By method of elimination, add equation (I) and equation (4)


For u terms:
5u + 2u = 7 u

For v terms:
-2v + 2v = 0 ( v is eliminated).

For constant terms:
13 + 15 = 28


Thus, 7u = 28
Divide both sides by 7 to get u
(7u/7) = 28/7

u = 4

Plug the value of u into equation (I) to get the value of v

5*4 - 2v = 15
20 - 2v = 15

Subtract 20 from both sides of the equals sign to get v, thus
20 - 2v - 20 = 15 - 20

20 - 20 - 2v = 15 - 20

-2v = -5
Divide both sides of the equals sign by (-2)

(-2v/-2) = -5/-2

(-)at the numerator will cancel (-)at the denominator
v = 5/2 or 2(1/2)

sir please can you reduce to a simpler term
I got lost in the first solution
From taking it term by term from both eqn 3 and 1 where did 100x
I got lost at that point
And for the second I don't understand at all

emmysolo2001:
sir please can you reduce to a simpler term
I got lost in the first solution
From taking it term by term from both eqn 3 and 1 where did 100x
I got lost at that point
And for the second I don't understand at all

Can u read it in ur native language? slow learners do that and its a sure banker to help them. How else will he explain again

emmysolo2001:
sir please can you reduce to a simpler term
I got lost in the first solution
From taking it term by term from both eqn 3 and 1 where did 100x
I got lost at that point
And for the second I don't understand at all

it's well explained. Meet any of your course mate. You guys should put head together

FromZeroToHero:
it's well explained. Meet any of your course mate. You guys should put head together

OK thanks

Intelligent people dey NL but clowns plenty pass

OutOfTheAshes:
Solution to question 1

100cents = 1 dollar.

Let x represent the number of 50cent coins
Let y represent the number of 1 dollar (100cent) coins
Total coins = 36
x + y = 36............................ equation (1)
Total value of coins = $26.50
$26.50 = 26 dollars + 0.50 dollar
Convert$ 26.50 to cent = 26.50dollars * 100cents = 2650cents

100x + 50y = 2650 total value of 1 dollar coins plus 50 cent coins…............ equation (2)
Using elimination method multiple equation (1) by 100

100x + 100y = 3600...................... equation (3)

equation (3) minus equation (1)

Taking it term by term from both equations (3) and (1)

For x:
100x - 100x = 0

For y:
100y - 50y = 50y

For the constant terms on the Right Hand Side of both equations:

3600 - 2650 = 950

Therefore 50y = 950

Divide both sides by 50 to get y

(50y/50) = (950/50)
y = 19

The number of 1 dollar coins is 19

Plug 19 into equation (I) to get x:

x + 19 = 36

Subtract 19 from both sides of the equals sign to get x,

x + 19 - 19 = 36 - 19 NB: +19 - 19 = 0

x = 17

Nice job you did there Sir, but you made a mistake while drafting out equation (2). According to you, x=50cents and y=100cents=1dollar. But you represented 50cents with y in eqn(2) and 100cents with x meanwhile it should have been the other way round.

lilachiever:


Nice job you did there Sir, but you made a mistake while drafting out equation (2). According to you, x=50cents and y=100cents=1dollar. But you represented 50cents with y in eqn(2) and 100cents with x meanwhile it should have been the other way round.

Thanks for the correction. It's a mistake.

The number of cent 50cent coins is x = 19
While the number of 1 dollar coins is y = 17


To whom it may concern take note and make the necessary corrections.

I am not destined to pertake in this thread make i enter romance section