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Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)
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Re: Nairaland Mathematics Clinic by yBNL1(m): 5:16pm On Jun 27, 2014 |
chai....when I was compiling all the questions on this thread. But at least my username has been changed back from ybnl11....stupid nl |
Re: Nairaland Mathematics Clinic by efficiencie(m): 10:05pm On Jun 27, 2014 |
mehn it filz gud 2 b bak! |
Re: Nairaland Mathematics Clinic by jackpot(f): 11:09am On Jun 28, 2014 |
How can we spend all those time preparing for the Mathematics quiz and all the efforts of the Quiz Masters and the participants go down the drain just like that? 1 Like |
Re: Nairaland Mathematics Clinic by Nobody: 11:40am On Jun 28, 2014 |
let 's try this welcome back question compute the anti-derivative of [arcsin(lnx) ] dx A,b,c is a geometric progression (a,b,c are positive integer) such that a+b+c=26 and a^2+b^2+c^2=364 find the value of a,b,c asap . |
Re: Nairaland Mathematics Clinic by killsmith(f): 3:27pm On Jun 28, 2014 |
Pls I'd need recommendations on books to buy....on algebra(linear and abstract)....and analysis(real,vector,complex,numerical).....thanks in anticipation... |
Re: Nairaland Mathematics Clinic by Nobody: 7:29pm On Jun 28, 2014 |
killsmith: Pls I'd need recommendations on books to buy....on algebra(linear and abstract)....and analysis(real,vector,complex,numerical).....thanks in anticipation...schum's outline |
Re: Nairaland Mathematics Clinic by 2nioshine(m): 12:58pm On Jun 29, 2014 |
hmmmmmmmmmmm............if only seun had agree to purchase my new software......this data loss wouldn't av been a case.....*sob*.......re-booking my corner 1 Like |
Re: Nairaland Mathematics Clinic by Nobody: 11:09am On Jul 01, 2014 |
hmmmm. |
Re: Nairaland Mathematics Clinic by Nobody: 11:31am On Jul 01, 2014 |
It's a pity, almost 50 pages plus our NMQC II thread gone! Let's build it up again gurus.... don't be discouraged! |
Re: Nairaland Mathematics Clinic by Nobody: 11:35am On Jul 01, 2014 |
2nioshine: hmmmmmmmmmmm............if only seun had agree to purchase my new software......this data loss wouldn't av been a case.....*sob*.......re-booking my corner General 2nioshine, good to be back...you're a software engineer or something? Seun was careless about backing up, that was the problem...I hope he learns from what happened! 1 Like |
Re: Nairaland Mathematics Clinic by Nobody: 11:37am On Jul 01, 2014 |
Ben the general...I will give your problems a try later in the day! Top of the morning to you sir! |
Re: Nairaland Mathematics Clinic by Nobody: 11:49am On Jul 01, 2014 |
doubleDx: Ben the general...I will give your problems a try later in the day! Top of the morning to you sir! ok boss ...thanks .. |
Re: Nairaland Mathematics Clinic by Nobody: 11:54am On Jul 01, 2014 |
mathematicians could be crazy sometimes . |
Re: Nairaland Mathematics Clinic by Nobody: 11:56am On Jul 01, 2014 |
1 ..$[arcsin√(2x) /√(1-2x) ] dx 2..$ [ xlnx/(1+x^2)^2 ] dx |
Re: Nairaland Mathematics Clinic by SirChides(m): 11:58am On Jul 01, 2014 |
Solve d equation::: 3x+y-z=0....* -2x+y+4z=0...* 4x+y-2z=0....*. Pls show full working s... |
Re: Nairaland Mathematics Clinic by Nobody: 12:01pm On Jul 01, 2014 |
ok |
Re: Nairaland Mathematics Clinic by Nobody: 6:55pm On Jul 01, 2014 |
doubleDx: It's pity, almost 50 pages plus our NMQC II thread gone! Let's build it up again gurus.... don't be discouraged! maybe we shall organize another one. 1 Like |
Re: Nairaland Mathematics Clinic by jaryeh(m): 10:35pm On Jul 01, 2014 |
Yea. Greetings to all my bosses on the thread. I think I should resume back now that I'm on a forced holiday. Nice questions @benbuks, I'll attempt them tomorrow. Errmmmm, where are dejt4u, Arithmetic, STENON, Amazing Angel, Alpha Maximus, Smurfy and others? Were they "tsunamised"? |
Re: Nairaland Mathematics Clinic by STENON(f): 11:54pm On Jul 01, 2014 |
[quote author=jaryeh] Yea. Greetings to all my bosses on the thread. I think I should resume back now that I'm on a forced holiday. Nice questions @benbuks, I'll attempt them tomorrow. Errmmmm, where are dejt4u, Arithmetic, STENON, Amazing Angel, Alpha Maximus, Smurfy and others? Were they "tsunamised"? [/quote] No ooo....Here is ur Girl o....Goodevening n I hope you are doing great?...... |
Re: Nairaland Mathematics Clinic by jaryeh(m): 6:51am On Jul 02, 2014 |
STENON: No ooo....Here is ur Girl o....Goodevening n I hope you are doing great?......Sure. How about you? |
Re: Nairaland Mathematics Clinic by STENON(f): 7:39am On Jul 02, 2014 |
jaryeh:Yes, Same.......Hope u'r enjoyin ur forced brk? |
Re: Nairaland Mathematics Clinic by Nobody: 11:25am On Jul 02, 2014 |
efficiencie: mehn it filz gud 2 b bak!try my question$ boss. tnx |
Re: Nairaland Mathematics Clinic by AlphaMaximus(m): 12:51pm On Jul 02, 2014 |
jaryeh: Yea. Greetings to all my bosses on the thread. Tsunamised? I thinketh not. |
Re: Nairaland Mathematics Clinic by jaryeh(m): 1:44pm On Jul 02, 2014 |
STENON: Yes, Same.......Hope u'r enjoyin ur forced brk?Forced break! Mehn, it has not been funny at all. House sweet sha, na chores spoil am. You're at school right? |
Re: Nairaland Mathematics Clinic by jaryeh(m): 1:45pm On Jul 02, 2014 |
Alpha Maximus:Boss, long time. How and where have you been? |
Re: Nairaland Mathematics Clinic by dejt4u(m): 4:07pm On Jul 02, 2014 |
jaryeh: Yea. Greetings to all my bosses on the thread.present sir..what it do! |
Re: Nairaland Mathematics Clinic by oladistinct(m): 5:41pm On Jul 02, 2014 |
benbuks: let 's try this welcome back questionIntegral [arcsin(lnx)]dx=? Now, applying the method of integration by part. Let arcsin(lnx)=u and dx=dv. Integrating both dv and dx will yield v=x. To differentiate arcsin(lnx) let lnx=w, therefore arcsin(lnx)=arcsinw. Since arcsin(lnx)=arcsinw=u; >> du/dw =1/[sqr(1-w^2)]. From w=lnx, >> dw/dx =1/x. Therefore du/dx =[1/[sqr(1-w^2)]] * 1/x. Since w=lnx, >>> du/dx = [1/1-sqr(lnx^2)] * 1/x. We can now say that du=dx/[xsqr(1-lnx^2]. Now integral udv=uv- integral vdu >> integral arcsin(lnx) = xarcsin(lnx) - integral xdx/xsqr(1-lnx)^2)+c. To integrate dx/sqr(1-lnx^2) let lnx=sinu Therefore dx/x = cosudu >> dx=xcosudu. Now integral 1/sqr(1-lnx^2)=integral [1/sqr(1-sin^2 u)]*xcosudu. Which equal to integral xcosudu/sqr(1-sin^2 u). From sin^2 u + cos^2 u = 1 >>> 1-sin^2 u=cos^2 u. We now have integral xcosu/sqrcos^2 u = xcosu/cosudu. Therefore integral dx/sqr(1-lnx^2) = integral xdu. Since lnx=sinu >> x=e^sinu. Integral dx/sqr(1-lnx^2)= integral e^sinudu From maclaurin series e^x=1+x+x^2/2+....... >>e^sinu=1+u+u^2u/2!+...... Integral e^sinudu=u+u^2/2+u^3/6+... Now lnx=sinu >>u=arcsin(lnx) Integral e^sinudu= arcsin(lnx)+1/2[arcsinlnx]^2+1/6[arcsinlnx]^3+...... Combining the results Integral arcsin(lnx)dx= xarcsin(lnx)+arcsinlnx+1/2[arcsinlnx]^2+1/6[arcsinlnx]^3 I hope I'm not wrong |
Re: Nairaland Mathematics Clinic by oladistinct(m): 6:34pm On Jul 02, 2014 |
Sir Chides: Solve d equation::: 3x+y-z=0................(i) -2x+y+4z=0............(ii) 4x+y-2z=0................(iii) (i)-(ii) 5x-5z=0 5x=5z X=z......................(iv) Sub eqn (iv) into (iii) 4z+y-2z=0 2z+y=0 Y=-2z Choosing an arbitrary solution for z Let z=1 >>>x=1 and y=-2(1)=-2 Therefore x=1,y=-2,z=1. |
Re: Nairaland Mathematics Clinic by oladistinct(m): 7:39pm On Jul 02, 2014 |
benbuks: 1 ..$[arcsin√(2x) /√(1-2x) ] dx I want to believe $ means integral. Integral arcsin(sqr2x)/sqr(1-2x) Using the method of integration by parts. Let u=arcsin(sqr2x) and dv=1/sqr(1-2x)dx Now du=dx/sqr(1-(sqr2x)^2) and v=arcsin(sqr2x) It now implies that du=dx/sqr(1-2x) Integral udv =uv- integral vdu >> integral [arcsin(sqr2x)/sqr(1-2x)]= arcsin(sqr2x)*arcsin(sqr2x) - integral [arcsin(sqr2x)dx/sqr(1-2x)] Collecting like terms 2[Integral arcsin(sqr2x)/sqr(1-2x)]= sin^-2(sqr2x) Therefore integral [arcsin(sqr2x)/sqr(1-2x)]= [Sin^-2sqr(2x)]/2 + c |
Re: Nairaland Mathematics Clinic by layez: 10:59am On Jul 03, 2014 |
See works ere wey i no fit solve... Chaii,i don suffer ooo.... Ehen abeg make una elp me solve dis palasa quest Integal Sec(X)dx |
Re: Nairaland Mathematics Clinic by layez: 12:02pm On Jul 03, 2014 |
oladistinct: bozz i tried solving dis qwest by follown ur steps bt i dint gt it.... If dv= 1/sqr(1-2x)?? Den V can nv be arcsin sqr(2x)... |
Re: Nairaland Mathematics Clinic by oladistinct(m): 12:52pm On Jul 03, 2014 |
layez:If dv=1/sqr(1-2x)dx Integrating both sides Integral dv= integral 1/sqr(1-(sqr2x)^2)dx This is identical to the standard integral 1/sqr(1-x^2)dx which will give arcsinx Therefore integral 1/sqr(1-(sqr2x)^2) will yield arcsin(sqr2x). Hope that helps 1 Like |
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