Tolzeal: Thatx the solun at ma picx..jus us what popular kald almyty 4mula..andu gewd to go..i wil pwt ma fnal anx sn..

nice one dear...I can see we have inteligent ppl on Nairaland...I actualy enjoy dis vry tread,brain exercise....thumbs up

State the Lami's law and parallelogram law of forces?

BrutusOj: Waoo..nice tread.my gurus in d house,kindly make t d subject of d formular in d expresion below" s=ut+1/2at^2" I.e d second equation of motion(s=ut+half atsquare).am waitin

To solve this one I am going to use the completing the square method...

D parallelogram law of vectors states dat if two forces are represented by d base and height of a parallelogram den their resultant is d diagonal drawn 4rm a common point.

ositadima1:

This question is funny, if we assume a, b, c to be whole numbers then question is wrong. Why?
a^2+b^2+c^2=16
a, b, c can either be -1, -2, -3 or 1, 2, 3 given dat 4 go be fu.ckup. I am still solving oooooo......... a, b, c have to be fractions...

lemme Try

@OP and my great maths gurus in the house. I luv maths and even tho I never applied to study it in skul, I must say it was a rily nice and intruiging experience. My problem is dat I had some lecturers who simply had no idea wat dey were doing. For example, up till now - almost 14 months after graduating- my knowledge of PDE's and Lebesque measure/integral is a mess.
Suffice to say for now dat I wud just like a quick overview of Fibonachi Sequences. Tanks and God bless.

BrutusOj: Waoo..nice tread.my gurus in d house,kindly make t d subject of d formular in d expresion below" s=ut+1/2at^2" I.e d second equation of motion(s=ut+half atsquare).am waitin

To solve this one I am going to use the completing the square method...

s=ut+(0.5)at^2
Multiply by 2/a
2s/a=(2u/a)t+t^2

t^2+(2u/a)t+....=2s/a+....
Now, to make our equation a perfect square we add (u/a)^2 to both sides.

t^2+(2u/a)t+(u/a)^2=2s/a+(u/a)^2
Lets factor this baby...

(t+u/a)^2=2s/a+(u/a)^2

t+u/a=(2s/a+(u/a)^2)^0.5

note its plus minus, meaning u have two answers

t=(2s/a+(u/a)^2)^0.5-u/a

t=-(2s/a+(u/a)^2)^0.5-u/a

Odelola01: State the Lami's law and parallelogram law of forces?

to state it mathematically since we re mor interested in mathematics.it states that" F1/sin(teta)=F2/sin(beta)=F3/sin(gama)I.e if three forces F1,F2 n F3 are in equilibruim,den d magnitude of each force is proportional to d sine of d angle btwn d other two forces.teta is d angle btw F2 n F3,beta is d angle btwn F1 n F3 n gama is d angle btwn F1 n F2.Lami' theorem is what we have as sine rule in math.Parallelogram law of vectors(forces) is d popular cosine rule or pythagoras theorem..if two forces are represented in magnitute n direction by d adjacent sides of a parallelogram,dn dia resultant is d diagonal from d comon point R=A^2+B^2-2ABcos(180-teta) where teta is d angle btwn A n B

Odelola01: State the Lami's law and parallelogram law of forces?

to state it mathematically since we re mor interested in mathematics.it states that" F1/sin(teta)=F2/sin(beta)=F3/sin(gama)I.e if three forces F1,F2 n F3 are in equilibruim,den d magnitude of each force is proportional to d sine of d angle btwn d other two forces.teta is d angle btw F2 n F3,beta is d angle btwn F1 n F3 n gama is d angle btwn F1 n F2.Lami' theorem is what we have as sine rule in math.Parallelogram law of vectors(forces) is d popular cosine rule or pythagoras theorem..if two forces are represented in magnitute n direction by d adjacent sides of a parallelogram,dn dia resultant is d diagonal from d comon point R^2=A^2+B^2-2ABcos(180-teta) where teta is d angle btwn A n B

biolabee: truman u are a demon

a + b + c = 8
(a+b+c) ^2 = 64
====> a2 + b2 + c2 + 2(ab+ac+bc) = 64
====> hence ab+ac+bc = 48/2 = 24 ------------(1)


(a+b+c)^3 = 512
a3+b3+c3+ 3a(b2+c2+ + 3b(a2+c2) + 3c(a2+b2) + 6abc = 512

I only need one more equation
product of abc

I don tire

i continued from here, solved another 2 pages
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And I arrived at equation 1(a + b + c) = 8.


E neva happen before

double post

dabrake: i continued from here, solved another 2 pages
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And I arrived at equation 1(a + b + c) = 8.


E neva happen before

Hahahaha, what d dude did was wrong sha

(a+b+c) ^2 = 64 this makes no sense

dabrake: i continued from here, solved another 2 pages
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.
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And I arrived at equation 1(a + b + c) = 8.


E neva happen before

it a fogd questn I think...am n ma 5th page solvn stil no ansa...

Tolzeal: it a fogd questn I think...am n ma 5th page solvn stil no ansa...

Men, we have three variables and third power here, this ish is too complex to be solved by hand

dabrake: i continued from here, solved another 2 pages
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And I arrived at equation 1(a b c) = 8.


E neva happen before

it a fogd questn I think...am n ma 5th page solvn stil no ansa...

Its not a fodged question....... Its just complex.

olasesi: find the SUM of the nth term of the sequence.........4+44+444+4444+44444+444444+......

it was given as an assignment for us back then in pre-degree........
.......only me got the answer to it .......i felt fulfilled then.........
........I HOPE THERE ARE OTHER PERSONS WHO CAN SOLVE IT.......

Summation of (4*10^(n-1) + 4)
Abi?

2b sincere, dis' d most educative thread I've evr read. Guy, if u could help, I av a Postgraduate math questn whc am xpectd 2 prove. It's a simultaneous eqn with 3unknowns. I'll post it in d evening. Thanks 4 keeping warm 4d questn.

Truman155: Its not a fodged question....... Its just complex.

I think I'm getting closer to the answer

a sysytem of equations is said to be inconsistent if it has no definite solution.....

Pls can anybody solve dis qustn for mi
Fundamental frequency =50hz, fundamental current=960A, fundamental voltage= 1500V, calculate the 2nd to 15th harmonic current and voltage of the system.

x+cosx=2.154, find x

i'm sorry i went off, i'm back to answer some of your questions

einstein_e: Can any mathematician here solve this simple question:

You are about to play a dice game where you are paid 5 naira each time you roll an odd number. You are allowed to roll the dice five times. A friend tells you that the die used is biased such that even numbers are twice as likely to appear as odd numbers. Based on this information, what is the maximum amount you would pay to play this game?

SOLUTION
let p(even)=x and p(odd)=y
from the question, p(even)= 2*p(odd)
therefore; x=2y........(1)
now be careful because the ratio
p(even): p(odd)
= 2 : 1
summation of ratios= 2+1 =3
hence, p(even)= 2/3 and p(odd) = 1/3

no of time to roll dice = 5
therefore no of odd number outcomes(also known as expectation) = 1/3 * 5 = 2.67 (approx)

max. amt to be paid = 5naira * 2.67 =13.35 naira

Fibonacci was an italian mathematician,he developed d fibonacci series.d cci pronounced as shi.d series is just a series in which d nth term is gotten by d summation of d first two preceeding terms i.e T3=T1+T2.d series goes thus 1 1 2 3 5 8 13 till infinity.when writing a computer program 4 it.d first two terms are initialized as one.

Proflakes: x+cosx=2.154, find x

x+cosx=2.154

x+cosx=2.154+0.i

x+[e^(-ix)]/2+[e^(ix)]/2=2.154

x=3.15392 (appr.)

converted cosx to its hyperbolic form

lol, ok I cheated....

The realistic way to solve it is to plot y=x+cosx against y=2.154, if u are good at graphs u should get 3.1 something at there intrsection, mind u cosx is in radians.

Truman, your question eh.

Nice thread! I love Mathematics, but hate to solve any...

math-diva:
Thumbs up guys for the good job. I studied pure maths in unilag and I must say that my life has been the better for it. For all those who have the passion for maths I encourage you to study it in school and learn to make your passion work for you. Maths forms the base of all science and engineering courses so it's very easy to convert to other professions. A lot of my colleagues work in banks, audit firms, marketing firms, oil and gas, telecoms, food and beverages etc

I remember in 300 and final year I rarely used my calculator cos most of the courses we did were theoretical and used more of x, y and z rather than numbers. Then I was so sure Prof Olaleru was making up some of the stuff he taught us. So you can imagine how surprised I was to find all those pure maths principles embedded in stuff I do at work.

What am just trying to tell you all who want to know if it's worth their time to study maths or stats the answer is yes, especially if your a natural guru. All the maths gurus in my class spent more time playing games than reading, in maths once u know it you know it and unless your ecturer na witch, there is no way he wants to set his questions that u will not answer it and get method mark.

So Dr. Olaleru is now a Prof., congrats to him.

dabrake: Truman, your question eh.

Have you solved truman question?

Youngsage:
x + y =5 -------- eqn i.
x^x + y^y=31 ----- eqn ii.
From equatns i & ii, take the log of both sides
(xlog^x + ylog^y) = log 31------ eqn iii.
logx + logy = log 5 ------------ eqn iv.
xylogxy= log 31 -------- eqn v.
log xy = log 5 --------- eqn vi.
(Using elimination method);
xylog5 = log31
xy = log 31/log 5 =6.2 approx. 6.

Recall, from eqn i, x + y = 5.
So x = 6/y or y = 6/x.
Therefore x=2 when y=3.
ans: x=2, and y=3.

Log(x+y) = Log 5.. Is it the same as log x + log y = Log 5?? Cross check your solvings..

1stknight:

Have you solved truman question?

nooooh!


Though, the question isn't wrong. I proved it wasn't but to find that a, b or c na die. Hopefully, the answer will appear before the day runs out.

dabrake: nooooh!


Though, the question isn't wrong. I proved it wasn't but to find that a, b or c na die. Hopefully, the answer will appear before the day runs out.

Guy dont stress ur self, I used a programming calc. and I got this answer;
a=4.87119
b=1.5644-2.51229i
c=1.5644+2.51229i

This is one set of answers, they are like 3 set total and they are all complex numbers, I doubt anybody can solve this equations by hand.

If a+b+c=8, a^2+b^2+c^2=16 and a^3+ b^3+c^3=64 find a,b, and c