0^0= prove it

Donmichaelz: if Sango is gay,and Spits out 200cm fire wat is d probability dat is fire can kill Godzila take pie=2.9m.

hahahahaha pls dont turn my brains upside down oooh

dabrake: chei! Omo, . . .

He he, I don give up on the maths taytay.

Richiez:

if you check the R.H.S, u'l find out that the value of x cannot exceed 2.154, and this is a small number compared to the next term which is to be divided by 6!, so this makes other terms quite insignificant.
and for the factorization, if you have an eqn, say, x(x^2+ 4)= 0 , one of the values of x must be 0. same goes for x[x^3/24- x/2 + 1] = 1.154, one of the values of x shud be 1.154
okay lets check
x+cosx=2.154
when x=1.154, x+cosx= 1.154 + cos(1.154) = 1.154 + 0.999 = 2.154 (approx)

Now, u kind of cheated, because maclaurin's series is based on radians (x is in radians). but when u fed back the answer u calculated, u did ur cos in degrees. I am coming...

Pls am afraid of calculations... And my headache anytyme am solving, how do i go about it...

Richiez: x(x^2+ 4)= 0

what x(x^2+ 4)= 0 means is that (x+0)(x^2+ 4)= 0
therefore one of the x is x=0

now x[x^3/24- x/2 + 1] = 1.154 is a different situation.

actually: [x^3/24- x/2 + 1] = 1.154/x.

[quote author=solomon111]The fifth equation follows the principle/laws of logarithm.
E.g
1)logx +logy =logxy
2)alogx +blogy=ablogxy.
3)logx-logy=logx/logy [/quot

Eqns (2) nd (3) are wrong...correct yursef pls

ositadima1:

x+cosx=2.154

x+cosx=2.154+0.i

x+[e^(-ix)]/2+[e^(ix)]/2=2.154

x=3.15392 (appr.)

converted cosx to its hyperbolic form

lol, ok I cheated....

The realistic way to solve it is to plot y=x+cosx against y=2.154, if u are good at graphs u should get 3.1 something at there intrsection, mind u cosx is in radians.

I am quoting my self, not good ooo.
If u plot y=2.154 against y=x+cosx u get x=3.1 something pending on how nice u layed ur grid, again x is in radians.

Anyway, let's c what others will come up with

calculusx: [size=30pt]Hi all, a friend of mine went for an interview sometime ago and was asked to pronounce this simple equation mathematically. e^0 = 1. Can anyone in the house pronounce this mathematically?[/size]

e represents the euler constant which have a value of 2.718 so it has to be the euler constant raised to the power of zero.

ithm,since it involves exponential values.
If logarithm is applied in the first equation,then it would also be applied in the second equation to create uniformity.
X+Y=5,becomes
logx+logy=5.
x^x+y^y=31,becomes
xlogx+ylogy=log31. [/quote]

Mr solomon, pls stop misleading people
Its log(X+Y)=log5 and not logX + logY =log5...you are taking log of the LHS 'as a whole'

calculusx: [size=30pt]Hi all, a friend of mine went for an interview sometime ago and was asked to pronounce this simple equation mathematically. e^0 = 1. Can anyone in the house pronounce this mathematically?[/size]

Exponential of zero is equal to one

Funny thing is anything raised to power zero gives u one, osita raised to 0 is one, I am a little tipsy

2good:

e represents the euler constant which have a value of 2.718 so it has to be the euler constant raised to the power of zero.

You are almost there. There is a particular mathematics term the interviewer expected from my friend which he didn't use. Its as simple as anything raise to the power of zero equals 1 but as a mathematician, saying anything raise to the power of zero simply means nothing raise to the power of zero cos anything could be nothing. try again

calculusx:

You are almost there. There is a particular mathematics term the interviewer expected from my friend which he didn't use. Its as simple as anything raise to the power of zero equals 1 but as a mathematician, saying anything raise to the power of zero simply means nothing raise to the power of zero cos anything could be nothing. try again

THAT WOULD BE THE EXPONENT TERM.

ositadima1:


Exponential of zero is equal to one

Funny thing is anything raised to power zero gives u one, osita raised to 0 is one, I am a little tipsy

Any Quantity raised to the power of Zero is 1. That was exactly what the interviewer want to hear. Q.E.D

Maths...
Lets go to Abstract algebra.
Course: GROUPS AND RINGS

QUESTION: Let G be a group, then every subgroup of G and every homomorpic image of G are solvable.
PLS PROVE...

Audinowing: 3+3=y.find y

Y = 33

Though my discipline is way off maths. I can sense dt ositadima is indeed good.
So wats d present state of maths in Nigeria? Can we compete with d Asians?
This is wat our govt shd b encouraging nt giving money to som militants.
Educatn is loosin value

ositadima1:

what x(x^2+ 4)= 0 means is that (x+0)(x^2+ 4)= 0
therefore one of the x is x=0

now x[x^3/24- x/2 + 1] = 1.154 is a different situation.

actually: [x^3/24- x/2 + 1] = 1.154/x.

dats true bro, no one is perfect, let me resolve it

@ OP am doing my thesis on the root bases of complex number, becauses I found out that complex numbers when expanded ie if they are raised to power could have a possibility to becoming its root base thus when applied industrialy semi conductors could easily give off heat in electrical parts, but what I need is an algorithm that can divide odd numbers and even numbers without getting a remainder.U can mail me. . . thanks

calculusx:

Any Quantity raised to the power of Zero is 1. That was exactly what the interviewer want to hear. Q.E.D

Not really. Even a JSS 1 child knows that anything raised to the power of zero is 1.

Odelola01: State the Lami's law and parallelogram law of forces?

Lami's Law applies to a situation of 3 forces acting on a system, while parallelogram law of forces applies to 2 forces acting on a system. Parallelogram law states that if two forces acts on a system, the resultant of both forces is the diagonal of a parallelogram which can be solved using the cosine rule.

The diagram below represents Lami's law

@OP especially, simultaneous eqn in 3unknowns.
Given that:
a1x + b1y + c1z + d1 = 0
a2x + b2y + c2z + d2 = 0
a3x + b3y + c3z + d3 = 0
find x, y & z and leave d answer in matrix form.
Please, please & please, help me 2 solve dis as d lecturer has promised 2 bring it in d exam. Thanks.

x + cosx = 2.154

SOLUTION
x+cosx=2.154.....(1)
we have to apply maclaurin's series for cosx= 1- x^2/2! + x^4/4! - x^6/6! + x^8/8!......
hence, x+ 1- x^2/2! + x^4/4!- x^6/6! + x^8/8!........=2.154
x^8/40320 - x^6/720 + x^4/24- x^2/2 + x =2.154-1

x^8/40320 - x^6/720 + x^4/24- x^2/2 + x =1.154

well to save time, i used a prog calculator and got x = 3.15 (approx)

tnx osita for the correction, u must be a guru

nice thread

ositadima1:

Guy dont stress ur self, I used a programming calc. and I got this answer;
a=4.87119
b=1.5644-2.51229i
c=1.5644-2.51229i

This is one set of answers, they are like 3 set total and they are all complex numbers, I doubt anybody can solve this equations by hand.

If a+b+c=8, a^2+b^2+c^2=16 and a^3+ b^3+c^3=64 find a,b, and c

guy ps........ Can u just help me and check what you will get if u just change the 3rd equation to a^3+b^3+c^3=32 just the answers ps for a,b and c

ositadima1:

Guy dont stress ur self, I used a programming calc. and I got this answer;
a=4.87119
b=1.5644-2.51229i
c=1.5644+2.51229i

This is one set of answers, they are like 3 set total and they are all complex numbers, I doubt anybody can solve this equations by hand.

If a+b+c=8, a^2+b^2+c^2=16 and a^3+ b^3+c^3=64 find a,b, and c

man ps can u use ya calculator and tell me what u will get as values of a,b and c if u change the last equation to a^3+b^3+c^3=32 ps just the answers

wow..,an educative thread.

I am not a mathematician but i just have natural love for it.
How did u get d 8 pigeon?

Richiez:

you should note that most pigeon hole problems involves logical reasoning and not calculations.

SOLUTION
no of mail correspondents = 17
no of topics = 3
since the correspondents are in pairs, no of possible pairs = 8 (i.e only 8 pairs from 17)

let pigeons = no of pairs =8
and pigeonholes = no of topics = 3
if we assume that the letters wud be distributed evenly i.e pigeons wud be distributed evenly into the pigeon holes, then atleast all 3 pigeon holes will an extra pigeon
this implies that some pairs will have same topic as other pairs

2good:

Not really. Even a JSS 1 child knows that anything raised to the power is 1.

Everyone knows that for sure but as a mathematician,the interviewer was expecting to hear something different from "ANYTHING RAISE TO POWER ZERO". His point was,as a mathematician, you should speak mathematically.

@dabrake
Any number divided by zero is undefine

Okay here's one for the board. Solve below using equations of absolute value


a) | x | = 5

b) | x - 2 | = 7

c) | 89 x + 4 | = -2

d) | -11 x - 9 | = 0

e) 2 | x + 5 | = 10

f) 3 | -9 x - 7 | - 2 = 13

g) -5 | -x + 2 | + 8 = -12

h) | -3 x - 2 | / 3 = 7

i) | (x - 5) / 4 | = 6

j) | x + 1 | = |-4 x + 3|

k) | x + 3 | = - |-x - 3 |