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Nairaland Mathematics Clinic - Education (10) - Nairaland

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Re: Nairaland Mathematics Clinic by Krucifax(m): 12:22am On Jan 04, 2013
Okay i see that was a bit tough so here are the answers anyone with the structure path wil get a WESTERN union gift from me.

a) {-5 , 5}

b) {-5 , 9}

c) No solutions (absolute value is not negative)

d) {-9/11}

e) {0 , -10}

f) given equation is equivalent to | -9 x - 7 | = 5 , solutions: {-4/3 , -2/9}

g) given equation is equivalent to | -x + 2 | = 4 , solutions: {-2 , 6}

h) given equation is equivalent to | -3 x - 2 | = 21 , solutions: {-23/3 , 19/3}

i) given equation is equivalent to | x - 5 | = 24, solutions: {-19 , 29}

j) {1/6 , 1}

k) given equation is equivalent to 2| x + 3 | = 0 , solution: {-3}
Re: Nairaland Mathematics Clinic by sam2323(m): 1:40am On Jan 04, 2013
make t subject of the formula in the third equation of motion. S=UT + 1/2AT^2
Re: Nairaland Mathematics Clinic by phy: 2:52am On Jan 04, 2013
sam2323: make t subject of the formula in the third equation of motion. S=UT + 1/2AT^2

The equation should be S= UT + (1/2)AT^2 or S= UT + (AT^2)/2 for clarity. Pls find my solution below:

NB: Remember that t = time, it can not be negative, so you can play with the eqn.

[img][/img]

Re: Nairaland Mathematics Clinic by Obinoscopy(m): 5:04am On Jan 04, 2013
Youngsage:
x + y =5 -------- eqn i.
x^x + y^y=31 ----- eqn ii.
From equatns i & ii, take the log of both sides
(xlog^x + ylog^y) = log 31------ eqn iii.
log(x+y) = log 5 ------------ eqn iv.
xylogxy= log 31 -------- eqn v.
log xy = log 5 --------- eqn vi.
(Using elimination method);
xylog5 = log31
xy = log 31/log 5 =6.2 approx. 6.

Recall, from eqn i, x + y = 5.
So x = 6/y or y = 6/x.
Therefore x=2 when y=3.
ans: x=2, and y=3.

Hi youngsage,

Nice try! U got the answer right! But I'm sorry, your step is just SO WRONG!

First of, your derivation of eqn iii from eqn ii is wrong. This because log(A+B) is never equal to logA+logB

Also your eqn v is wrong as well. xlogx+ylogy cannot be added directly cos they've got no common factor. Thus it would be wrong to just multiply x with y and logx with logy to give xylogxy

Finally the answers x and y are pure integers and not decimals as u got. You only had to approximate cos u knew it will lead u to d answer u so desire grin

I'm sorry I had to criticise u work. Nice attempt though.

Try this: x^x+y^y=46912, x+y=2 cheesy

1 Like

Re: Nairaland Mathematics Clinic by tolutweety(m): 6:58am On Jan 04, 2013
Fully subscribed ! . Lovin ds thread soooo much. Nw lets solve d unsolvables ....
Re: Nairaland Mathematics Clinic by ositadima1(m): 7:04am On Jan 04, 2013
Truman155: man ps can u use ya calculator and tell me what u will get as values of a,b and c if u change the last equation to a^3+b^3+c^3=32 ps just the answers

a=2-2i
b=2+2i
c=4
Re: Nairaland Mathematics Clinic by layday2005: 7:07am On Jan 04, 2013
If a pig can give birth to 1,2,3,4,5,6 piglets. What is prob of 2 pigs giving birt to 4,9 and 15 piglets if 2 pigs give birth at the same time?
Re: Nairaland Mathematics Clinic by ositadima1(m): 7:10am On Jan 04, 2013
Obinoscopy:

Hi youngsage,

Nice try! U got the answer right! But I'm sorry, your step is just SO WRONG!

First of, your derivation of eqn iii from eqn ii is wrong. This because log(A+B) is never equal to logA+logB

Also your eqn v is wrong as well. xlogx+ylogy cannot be added directly cos they've got no common factor. Thus it would be wrong to just multiply x with y and logx with logy to give xylogxy

Finally the answers x and y are pure integers and not decimals as u got. You only had to approximate cos u knew it will lead u to d answer u so desire grin

I'm sorry I had to criticise u work. Nice attempt though.

Try this: x^x+y^y=46912, x+y=2 cheesy

Lol, no answer for dat, if u plot both equations the never meet each other. In other words u fabricated it tongue
Re: Nairaland Mathematics Clinic by coolexy2: 7:41am On Jan 04, 2013
](1)what is the real application of mathematics in our live?

(2) prove that:
a. Sin^3 x = 1/4(3sinx - sin3x)
b. Find 2nd derivative of:
y = cos^3 x
Re: Nairaland Mathematics Clinic by mouyoursawre: 7:46am On Jan 04, 2013
Can u do me a favour by helping me to find the square root of -3.
Re: Nairaland Mathematics Clinic by sam2323(m): 8:11am On Jan 04, 2013
@phy. pls the solution is not clear, make it biger
Re: Nairaland Mathematics Clinic by ositadima1(m): 8:19am On Jan 04, 2013
mouyoursawre: Can u do me a favour by helping me to find the square root of -3.

Let's try
Assuming x^2=-3

X=sqrt(-3)=(-3)^0.5

X=(3 * -1)^0.5

X=(3)^0.5 * (-1)^0.5

X=1.73205 * i

X=1.73205i
A complex number

1 Like

Re: Nairaland Mathematics Clinic by Mathano(m): 9:10am On Jan 04, 2013
An element p is said to be ireducible if p=ab such that either a or b is a unit.what is a unit.Two elements are said to be unit when their product is 1.D units in d set of integers are 1 nd-1.All positive and negative primes are irreducible in the set of integers.2 and 5 are irreducible in the set of integers but are reducible in d set z(i),cos 2=(1+i)(1-i), 5=(1+2i)(1-2i).
Re: Nairaland Mathematics Clinic by ositadima1(m): 9:30am On Jan 04, 2013
Krucifax: Okay here's one for the board. Solve below using equations of absolute value


a) | x | = 5

b) | x - 2 | = 7

c) | 89 x + 4 | = -2

d) | -11 x - 9 | = 0

e) 2 | x + 5 | = 10

f) 3 | -9 x - 7 | - 2 = 13

g) -5 | -x + 2 | + 8 = -12

h) | -3 x - 2 | / 3 = 7

i) | (x - 5) / 4 | = 6

j) | x + 1 | = |-4 x + 3|

k) | x + 3 | = - |-x - 3 |

I am going to answer a few selected question, not easy to type this stuff on a phone.

(a) |x|=5

x=5 or -x=5
Two possible cases as absolute values are either positive or negative

x=5 or x=-5
(b) |x-2|=7

x-2=7 or -(x-2)=7
x=9 or x-2=-7
x=9 or x=-5
(c) |89x+4|=-2
No need solving ..

(d) |-11x-9|=0
-11x-9=0
x=-9/11
Now this big motherfu.cker
(j) |x+1|=|-4x+3|

x+1=|-4x+3|

x+1=-4x+3 or x+1=-(-4x+3)
5x=2 or x+1=4x-3
x=2/5 or 3x=4
x=2/5 or x=4/3

Ok, others are not as bad azz as this one^^^
NB: I left school with an excruciating 2 class lower.
Re: Nairaland Mathematics Clinic by indoorlove(m): 9:33am On Jan 04, 2013
awesome_benji: @OP especially, simultaneous eqn in 3unknowns.
Given that:
a1x + b1y + c1z + d1 = 0
a2x + b2y + c2z + d2 = 0
a3x + b3y + c3z + d3 = 0
find x, y & z and leave d answer in matrix form.
Please, please & please, help me 2 solve dis as d lecturer has promised 2 bring it in d exam. Thanks.
Re: Nairaland Mathematics Clinic by iamcourage(m): 10:27am On Jan 04, 2013
I tot I was really good at mathematics buh I hav Got to improve

1 Like

Re: Nairaland Mathematics Clinic by Nobody: 10:34am On Jan 04, 2013
Good Job Richiez. cheesy
Re: Nairaland Mathematics Clinic by jackpot(f): 10:35am On Jan 04, 2013
solomon111: I dread statistics.
That is one area of mathematics,i have not mastered.
As far as am concerned,statisticians are the real mathematicians.
R U B B I S H ! ! ! angry angryo
Re: Nairaland Mathematics Clinic by ositadima1(m): 10:37am On Jan 04, 2013
awesome_benji: awesome_benji: @OP especially, simultaneous eqn in 3unknowns.
Given that:
a1x + b1y + c1z + d1 = 0
a2x + b2y + c2z + d2 = 0
a3x + b3y + c3z + d3 = 0
find x, y & z and leave d answer in matrix form. Please, please & please, help me 2 solve dis as d
lecturer has promised 2 bring it in d exam. Thanks.

[a1 b1 c1][x]=[-d1]
[a2 b2 c2][x]=[-d2]
[a3 b3 c3][x]=[-d3]

| a1 b1 c1 : -d1|
| a2 b2 c2 : -d2|
| a3 b3 c3 : -d3|

Now u can solve ur three variables by manipulating matrix(adding and subtracting lines)
e.g 2x+y-3z=-4
4x-2y+z=9
3x+5y-2z=5
Solution: substituting data in ur matrix

| 2 1 -3 : -4|
| 4 -2 1 : 9 |
| 3 5 -2 : 5 |

For row(2): add -2 times row(1) plus 1 times row(2)
For row(3): add -3 times row(1) plus 2 times row(3)

| 2 1 -3 : -4 |
| 0 -4 7 : 17|
| 0 7 5 : 22|

Now,
For row(3): add 7 times row(2) plus 4 times row(3)

| 2 1 -3 : -4 |
| 0 -4 7 : 17|
| 0 0 5 :207|

Back to algibraic eq.

2x+y-3z=-4
-4y+7z=17
69z=207
If u fiddle with it now u should get
x=2
y=1
z=3

3 Likes

Re: Nairaland Mathematics Clinic by Nobody: 10:37am On Jan 04, 2013
jackpot: R U B B I S H ! ! ! angry angryo
Are you a Mathematician? Just asking.
Re: Nairaland Mathematics Clinic by Nobody: 10:39am On Jan 04, 2013
Is the ring of invariants of an algebraic group acting on a polynomial ring always finitely generated? Give axioms for your workings
Re: Nairaland Mathematics Clinic by ositadima1(m): 10:40am On Jan 04, 2013
wink
Re: Nairaland Mathematics Clinic by jackpot(f): 10:48am On Jan 04, 2013
solomon111: I dread statistics.
That is one area of mathematics,i have not mastered.
As far as am concerned,statisticians are the real mathematicians.
Re: Nairaland Mathematics Clinic by Danielwalt: 10:56am On Jan 04, 2013
cryGod if only u wil give me d mathematical intelligence. . . Bcoz i never had a strong foundation in mathematics

3 Likes

Re: Nairaland Mathematics Clinic by Nobody: 11:03am On Jan 04, 2013
Danielwalt: cryGod if only u wil give me d mathematical intelligence. . . Bcoz i never had a strong foundation in mathematics
Hehehe... Funny you. grin
Re: Nairaland Mathematics Clinic by 2good(m): 11:16am On Jan 04, 2013
Danielwalt: cryGod if only u wil give me d mathematical intelligence. . . Bcoz i never had a strong foundation in mathematics

You have to teach yourself mathematics and not wait for any body to come teach you. There are numerous text books you can buy and read starting from general mathematics SS1, then you move to SS2 and then SS3. If you read those books page by page and attempt all the examples and exercises at the end of each chapters, you will make an A1 in mathematics. I never had teachers for up to half my time in secondary school but I made A1 every time I wrote WAEC in mathematics years back because that is what I did(although all this happened about 15 to 18 years ago).
Then you can graduate to reading Further Mathematics text books starting from SS1, then move to SS2 then finally SS3. If you can do that, you will be fine with tackling almost all O' level problems and some A Level problems. But you need to do A level mathematics in the University to really be very good in mathematics. But no matter the level of mathematics you study, there are somethings you can't always remember like some of the rules of integration and Differential equations.

1 Like

Re: Nairaland Mathematics Clinic by TheKingsQueen: 11:22am On Jan 04, 2013
I can see Mathematics Teachers in the making here. Kudos to you all
Re: Nairaland Mathematics Clinic by 1stknight(m): 11:33am On Jan 04, 2013
ositadima1:

I am going to answer a few selected question, not easy to type this stuff on a phone.

(a) |x|=5

x=5 or -x=5
Two possible cases as absolute values are either positive or negative

x=5 or x=-5
(b) |x-2|=7

x-2=7 or -(x-2)=7
x=9 or x-2=-7
x=9 or x=-5
(c) |89x+4|=-2
No need solving ..

(d) |-11x-9|=0
-11x-9=0
x=-9/11
Now this big motherfu.cker
(j) |x+1|=|-4x+3|

x+1=|-4x+3|

x+1=-4x+3 or x+1=-(-4x+3)
5x=2 or x+1=4x-3
x=2/5 or 3x=4
x=2/5 or x=4/3

Ok, others are not as bad azz as this one^^^
NB: I left school with an excruciating 2 class lower.

Shey modulus come hard ni? You be graduate sef, I dey 100l dey complain say I no know maths.

Btw Kudos
Re: Nairaland Mathematics Clinic by Nobody: 11:41am On Jan 04, 2013
[quote author=pryzlez][/quote] eqn 2 wud only be correct if a=b. eqn 3 shud be log x - log y= log(x/y). I'v been away 4rm math 4 quite sometime nw.dis thread hs motivated me 2 get my groove back on.
Re: Nairaland Mathematics Clinic by ositadima1(m): 11:43am On Jan 04, 2013
1stknight:

Shey modulus come hard ni? You be graduate sef, I dey 100l dey complain say I no know maths.

Btw Kudos

No fall hand ooo, like moi. You have the greatest study aid this days, yeah, the INTERNET. Brother everything is there. Even if u cant afford all required school books, with the internet in ur hands ur are king.
Re: Nairaland Mathematics Clinic by 2good(m): 11:50am On Jan 04, 2013
ositadima1:

No fall hand ooo, like moi. You have the greatest study aid this days, yeah, the INTERNET. Brother everything is there. Even if u cant afford all required school books, with the internet in ur hands ur are king.

Very true. I remember using kerosene lantern to study every night when I was in secondary school. I never used a computer or the Internet till I was in the university and it was still limited.

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