Please can somebody help me out on this? Find x, 8x^-2=2/25

Please can somebody help me out on this? Find x, 8x^-2=2/25

tuwayz:
Please can somebody help me out on this? Find x, 8x^-2=2/25

8x^-2 = 2/25 (Note that the power(-2) is meant for x alone since there's no bracket)
==> 8/x² = 2/25
So by cross multiplication,
==> 2x² = 25*8
==> 2x² = 200
Divide both sides by 2
==>x² = 100
Find the square root of both sides
==> x = 10

mathefaro:

8x^-2 = 2/25 (Note that the power(-2) is meant for x alone since there's no bracket)
==> 8/x² = 2/25
So by cross multiplication,
==> 2x² = 25*8
==> 2x² = 200
Divide both sides by 2
==>x² = 100
Find the square root of both sides
==> x = 10

. Thanks bro, I was kind of confuse on how to go about It, I took the reciprocal of the left hand side because of the negative power but got it wrong, thanks a lot

tuwayz:
. Thanks bro, I was kind of confuse on how to go about It, I took the reciprocal of the left hand side because of the negative power but got it wrong, thanks a lot

you're welcome

Benjaminbest:
displaying corrupted file on my fone

ok, download directly from here

http://campusportal.com.ng/files/JAMB-Syllabus/Biology.pdf

Good morning roomie... Sir Benjaminbest, Sir mathefaro and/or any one in the hux pls help me solve these physics questions:

A car moves with a velocity of 72 km/hr. It is brought to rest in 10 s. Find:
(i) the velocity in m/s
(ii) the retardation

The sped of a bus increases uniformly from 15m/s to 60m/s in 20 seconds. Calculate:
(a) the average speed
(b) the acceleration
(c) the distance travelled during the entire period.

*abstracted from New School Physics textbook*

Many thanks!

A body of mass 25kg, moving at 3m/s on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. Calculate the coefficient of sliding friction [g=10.0m/s^2)

alryt still wondering were to start from

pls because of d little time dat i have i will not b able to write everytin out i wil jst drop d answers later

smartdave1:
A body of mass 25kg, moving at 3m/s on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. Calculate the coefficient of sliding friction [g=10.0m/s^2)

S=2.5m m=25kg v=3m/s but F X S=1/2mv^2.
1/2 x 25 x (3)^2 =112.5
F X 2.5=112.5 F=112.5/2.5=45N
u=F/mg =45/25 x10 =45/250
u=0.18

smartdave1:
Good morning roomie... Sir Benjaminbest, Sir mathefaro and/or any one in the hux pls help me solve these physics questions:

A car moves with a velocity of 72 km/hr. It is brought to rest in 10 s. Find:
(i) the velocity in m/s
(ii) the retardation

1a.to convert km/hr to m/s multiply by 10/36.
72 X10/36 =20m/s....daz d velocity
1b. V=u-at but v=0 0=20-10a 10a=20. a=2m/s

smartdave1:
Good morning roomie... Sir Benjaminbest, Sir mathefaro and/or any one in the hux pls help me solve these physics questions:



The sped of a bus increases uniformly from 15m/s to 60m/s in 20 seconds. Calculate:
(a) the average speed
(b) the acceleration
(c) the distance travelled during the entire period.

*abstracted from New School Physics textbook*

Many thanks!

permit me to find acceleration ist
v=u+at, v=60m/s u=15m/s a=? t=20sec
60=15+20a, 45=20a, a=2.25m/s^2
c. Distance travelled: S= Ut+1/2at^2
S=15 X20 + 1/2 X 2.25 X (20)^2
S=300+450
S=750m....daz distance travelled
a. The average speed =distance/time taken
A.v=750/20
A.V=37.5m/s

Segipaul:
permit me to find acceleration ist
v=u+at, v=60m/s u=15m/s a=? t=20sec
60=15+20a, 45=20a, a=2.25m/s^2
c. Distance travelled: S= Ut+1/2at^2
S=15 X20 + 1/2 X 2.25 X (20)^2
S=300+450
S=750m....daz distance travelled
a. The average speed =distance/time taken
A.v=750/20
A.V=37.5m/s

Thanks for filling in for me, i've been busy since mawnin

Segipaul:
permit me to find acceleration ist
v=u+at, v=60m/s u=15m/s a=? t=20sec
60=15+20a, 45=20a, a=2.25m/s^2
c. Distance travelled: S= Ut+1/2at^2
S=15 X20 + 1/2 X 2.25 X (20)^2
S=300+450
S=750m....daz distance travelled
a. The average speed =distance/time taken
A.v=750/20
A.V=37.5m/s

Although, you can also get the average speed by using the formula (v + u)/2, it will save more time


NB: There's a difference between knowing the solution to a question and knowing the fastest method to use. so please always look for the fastest method. Also, i'll advice you guys to start practicing questions with timing

heys guys how are u all have being very busy since mawnin even till now am still in my working place wen am suppose to b at home. Oga mathefaro i tried accesing d site dat u pasted but i was unable to download it

Someone should pls explain with examples addition, subtraction, multiplication & division of number bases. thanks
tag: mathefaro, benjaminbest and everyone else.

deb6:
Someone should pls explain with examples addition, subtraction, multiplication & division of number bases. thanks
tag: mathefaro, benjaminbest and everyone else.

Let's start with base 10...
(I) 15 +15=30 (ii) 16+16=32
Normally, we start calculating from d right hand side..Dat is for (i), 5+5=10, we write down "0" carry "1"..Then we move to d left hand side...1+1=2, we then add that "1" we carried from "10" to the "2" making it "3"..So we write down "3"...Hence we have 30 as d final answer....This is d general method we use in solving right? It looks very simple and easy cos we are adding in base 10...This is d base we use in everyday life...But when adding in other bases, we try to apply this method but we look very confused...Now this is because we didn't understand d process "mathematically"...Now this is d explanation..Let's start afresh..
As usual, we start from d right hand side...5+5=10...Since 5+5 is 10, 10 cannot be written in the answer space as it is equal to its base..If it was to be 5+4 = 9 , then we can write d 9 in d answer space cos it's not equal to d base(base 10)
I hope u understand dix...So what we have to do now is divide 10(from 5+5) by 10 (which is d base)...We now have "1" remainder "0"...We write down d remainder "0" and "carry" d one...Then we move on to d left hand side...1+1=2 (+1 we carried) =3..We can write dix 3 in d answer space since it's not equal to or greater than d base(10)..Hence we have our final answer as 30..This same rule applies to any other base...It. can be used for addition, subtraction and multiplication....I haven't tried it for division b4...
I know my explanation looks vague...U will need a solid background knowledge of number bases b4 u will be able to understand dix explanation clearly...I would have given other examples using other bases but m tired of typing....Pls pardon me...U will understand it better if u get someone to explain to u "one on one".
Let me leave d rest to the ogas@mathefaro and Benjaminbest for them to correct any mistakes and add to it also....

In a D.C. circuit, a 10microfarad(mf) capacitor is placed in series with a 10 ohm resistor. The total resistance of the combination is:
A. 10 ohms
B. 1 ohm
C. zero
D. 20 ohms
E. infinite

Segipaul:

Thank you boss! You are really on point.

mathefaro:
Although, you can also get the average speed by using the formula (v + u)/2, it will save more time

Thanks anyways, i think the bolded is a typographical error.

smartdave1:

Thanks anyways, i think the bolded is a typographical error.

it isn't an error. It's actually the correct formula for average velocity. Use it in the question you posted earlier and compare the answer with the one you were given

Thewhizzkid1:

Let's start with base 10...
(I) 15 +15=30 (ii) 16+16=32
Normally, we start calculating from d right hand side..Dat is for (i), 5+5=10, we write down "0" carry "1"..Then we move to d left hand side...1+1=2, we then add that "1" we carried from "10" to the "2" making it "3"..So we write down "3"...Hence we have 30 as d final answer....This is d general method we use in solving right? It looks very simple and easy cos we are adding in base 10...This is d base we use in everyday life...But when adding in other bases, we try to apply this method but we look very confused...Now this is because we didn't understand d process "mathematically"...Now this is d explanation..Let's start afresh..
As usual, we start from d right hand side...5+5=10...Since 5+5 is 10, 10 cannot be written in the answer space as it is equal to its base..If it was to be 5+4 = 9 , then we can write d 9 in d answer space cos it's not equal to d base(base 10)
I hope u understand dix...So what we have to do now is divide 10(from 5+5) by 10 (which is d base)...We now have "1" remainder "0"...We write down d remainder "0" and "carry" d one...Then we move on to d left hand side...1+1=2 (+1 we carried) =3..We can write dix 3 in d answer space since it's not equal to or greater than d base(10)..Hence we have our final answer as 30..This same rule applies to any other base...It. can be used for addition, subtraction and multiplication....I haven't tried it for division b4...
I know my explanation looks vague...U will need a solid background knowledge of number bases b4 u will be able to understand dix explanation clearly...I would have given other examples using other bases but m tired of typing....Pls pardon me...U will understand it better if u get someone to explain to u "one on one".
Let me leave d rest to the ogas@mathefaro and Benjaminbest for them to correct any mistakes and add to it also....

hope u have being admitted to study medicine and surgery in uniben

Umartins1:



Guy, I didn't want to comment at first but I couldn't hold on to the frustration.

I is NEVER plural, it is rather a singular pronoun. In fact, it is a first person singular pronoun and therefore attracts a singular verb such as am, was etc.

Where did you school? It is quite absurd seeing that you can't differentiate between HAS and HAVE. HAS is a present tense, singular- it is the opposite of HAD. HAVE on the other hand is the past tense of both HAS and HAD.


NB: there are exceptions to the rule of concord though, as illustrated in the example you gave.

na night school you go?

Has is singular of Have

Had is the past tense of both Has and Have.

I is first person pronoun.

Benjaminbest:
hope u have being admitted to study medicine and surgery in uniben

I've been admitted for medicine and surgery but in AAU...

Thanks @thewhizzkid1, i now understand

guy will nid to talk i thought is uniiben dat admitted u pm me on my gmail

deb6:
Thanks @thewhizzkid1, i now understand

Please try it with other bases and give me feedback...

Benjaminbest:
guy will nid to talk i thought is uniiben dat admitted u pm me on my gmail

I've sent one..

mathefaro:
it isn't an error. It's actually the correct formula for average velocity. Use it in the question you posted earlier and compare the answer with the one you were given

its alright, i'll do it later

mathefaro:
Although, you can also get the average speed by using the formula (v + u)/2, it will save more time

ya! Its true... But, pls make me understand how you got the formula, since there is no '2' in the question.
Thanks

Thewhizzkid1:

Please try it with other bases and give me feedback...

I did this one: 321*25 in base six = 13305six. pls check if i'm right