₦airaland Forum

taiocol: WAEC 2013:
(x-2)(x²+3x+2)+2(x+2)(x-1)=(x+2)M
FIND M

Using the equation provided by....from the equation...we can break x^2 + 3x + 2 into/equal to (x+1)(x+2)....so it bcoms

(x-2)(x+1)(x+2) + 2(x+2)(x-1)=M(x+2).....Looking the equation..u will observe that x+2 is common..so it cancels out...it bcoms
(x-2)(x+1) + 2(x-1)=M
x^2 + x -2x - 2 + 2x - 2 = M
x^2 + x - 4 = M
x^2 + x -( 4 + M)=0.......If we were to solve for the root using trial error rule......we shall find to our surprise that

M=2!

[quote
author=taiocol]WAEC 2013x-2)(x²+3x+2)+2(x+2)(x-1)=(x+c)M
FIND M[/quote]I have problem with your question for some reasons
1)waec don't set problems of equation great than power degree 2 in
ordinary pure mathematics.So,i guess...it may be a further
mathematics(as u guys may put it)
2) I got problem with the smiley's in ur question too!

However,this may set-out to be way for the solution!...after the
expansion i got

x^3 + x^2 - 2x - 8=Mx + Mc.......

The next thing would be to work by coefficient of x....which we can accept as

-2x=Mx.....
thus,M=-2

Mr Calculus: RECHECK UR QUES@LAZ

The two questions are very correct!.......

[quote author=Dibu_Ojerinde]F = m x a,
F = ^{m x v}/_t
V = 20ms^-1
so we have to find mass and time
density = 1mgm^-3
area = 0.0005m²
from the denstity, if mass = 1mg, volume = 1m³
so length = ^volume/_area
= 2000m
if length = 2000m,
20 x time = 2000
time = 100s
Mass = 1mg = 1 x 10⁶kg

F = (1 x 10^-6) x 20 / ₁₀₀
= 0.2 x 10^-6N

....please correct me sir [/quote]Very wrong!

Let me give you guys some of my tipsy questions...to grind u guys up

1)45cm^3 of a mixture of carbon( II ) and carbon ( IV ) oxide were mixed
with 45cm^3 of oxygen,and exploded.The volume of the resulting
gas,measured at the same temperature and pressure,was 70cm^3.Calculate
the volume of the carbon monoxide in the original mixture?

2)A hose directs a horizontal jet of water,moving with a velocity of 20m/s,on to a vertical wall.The cross-sectional area of the jet is 0.0005m^2.If the density of the water is 1Mg/m^3,calculate the force on the wall assuming the water is brought to rest there.

[quote
author=Dibu_Ojerinde]who send this one




this step contradicts the formula:

^left/_right = ^X/_100-X


was supposed to be 2 (100 - X) = 3X ..
.





Goodmorning boss [/quote]Step was okay!.......the difference was that in yours you got your
values straight....but in mine....u got to have it by subtracting the
60cm from the 100cm to get the 40cm....this is because i use the other
side....not the side you used!

So i calculated knownly for the 3-ohm....i thought it was for the 2-ohm.....the subtraction...makes mine den correct!

[quote author=Dibu_Ojerinde]Following [/quote]Follow wella

[quote

author=FrancisTony]u're writing jamb what course?
Oya take this cheap question
1) In a metre bridge experiment, two resistors 2ohm and 3ohm occupy the
left and right gaps respectively. Find the balance point from the left
side of the bridge. [/quote]Let's have it that in between the gaps is a high resistant
load(GALVANOMETER) separating the 2-ohm and 3-ohm resistors.Let's have
it that they are connected to a potentiometer of 100metre.From the
zero-mark to the gap,the left be xmetre....then the other side will be
(100-x)metre.Using the above formular may help out

Resistance(1) * Lenght(2) = Resistance(2) * Length(1)

Resistance(1)=2,Resistance(2)=3,Lenght(1)=x,Length(2)=(100-x)

2 * x=3( 100 - x)
2x=300-3x
5x=300
thus,x=60metre.........

[quote

author=aysuccess99]Let's continue with the question and answer series.
someone should answer this physics question:
1. The magnification of the image of an object placed in front of a
convex mirror is 1/3. If the radius of curvature of the mirror is 24cm,
what is the distance between the object and its image......
A8cmB16cmC24cmD32cm
2. when a yellow card is observed through a blue glass, the card would
appear:
A. black B green Cred D white.
3. Three resistors with resistance 250n,500n,1kn are connected in series
A 6v battery is connected to either end of the combination. Calculate
the potential difference between the ends of the 250n resistor.
A.0.20vB 0.86v C1.71v D3.43v[/quote]1st QUESTION from my calculation is 32cm

Mirror's formula is 1/f = (1/u) + (1/v).......if u divide both sides by v
u will get

(v/f) = M + 1......where M is magnification...
v=f(M + 1).....where f=0.5r n r=24cm.....so f=-12
v=-12(-.3333 + 1)=-8cm.......
where M=-1/3......U= -3 * -8=24cm

thus,distance between image and object is= 24-(- 8 )=24+8
=32cm

2nd QST.....The answer is GREEN....it is green because,green will be
reflected and because it is SUBRACTIVE and not ADDITIVE colours!

3rd QST....the answer is O.86v.....
When resistances are connected in series add them all...let A=500-ohms.....B=500-Ohms........C=1k-ohms=1000-ohms
Total resistance=A + B + C
=250 + 500 + 1000
=1750-Ohms......From Ohm's law.......p.d=IR....
current I=p.d/R......i.e. 6/1750
=0.00343Amps.....Current flowing through resistances in series is the same so.....
p.d across the 250-ohms= 250 * 0.00343
=0.8571
=0.86v!

aysuccess99: that's correct sir...you're very correct....thumbs up for you.

I did not see that question before..dis is the working....

The length between two nodes in a string is 0.5¥=L......Where ¥ Is LAMBDA(wavelength)..
Speed=wavelenght * Frequency.....so

¥=2 * 45=90cm=0.9m

speed(V)=¥ * F
= 0.9 * 60
= 54m/s

Thanks!

FrancisTony: you're correct but show working

This is the working: The frequency of a sonometer wire is inversely proportional to the length of the wire. So,

F=k/l.......where L is the length and K is the constant..
finally,it SHOULD BE
FREQ(1) * LENGTH(1)=FREQ(2) * LENGHT(2)....where * Means multiplication!

FREQ(2)=( FREQ(1) * LENGTH(1) )/( LENGTH(2) )

FREQ(2)=( 500 * 0.9) / (150)


ANS=3metre!

Aisha800: Projectile, light wave, sound wave , glass prism

Madam AISHA,let's be doing it this way,gather all the questions you have on PROJECTILE(1st week),I shall teach you how to personally handle dem,n using my ways in doing it u will get to understand that trully diz ar not problems!

Let's start with PROJECTILE!

LEGEND7466: BIOLOGICAL SCIENCES SIR......JUST A SCHOOL DAT I'LL AV A BETTER SHOT AT. THANKS SIR

Cant tell for such courses,i duely can be comprehensive about HEALTH and LIFE SCIENCES such as with NURSING/ANATOMY/PHYSIOLOY n others including MED LAB....but for BIOLOGICAL SCIENCES....i cant tell

Aisha800: i do have problems with calculation

Write your problems on this thread and i shall gratefully dealt with it in a more tentative and approachable manner!

Ensure to follow your READ-PLAN(RP) today!

It is enough that failure should succeed over you this year.If you can't beat over UTME EXAM this time,then no need writing it!

If you have any problem with CHEMISTRY/PHYSICS CALCULATION.....you can show it here so i help you over it!

LEGEND7466: PLS GUYS WHICH UNIVERSITY CAN I APPLY FOR DE WITH 3.20 FOR MBBS?

1)What course did u have 3.2 for?(it depends on the course 1st)

2)What school do u wish to put in?(Different school has different categories for their DE intakes).

[quote author=Dr. Laz'Devitan]As you may starting preparing for your UTME examination some strategic
textbooks are needful,these text are even suitable for any trials,they
do help for students whom may be targetting great upper marks.I do list
them as below:

CHEMISTRY: NEW SCHOOL CHEMISTY,SENIOR SECONDARY SCHOOL CHEMISTRY(1-3)
STAN,JAMB PAST QUESTION AND ANSWER ON CHEMISTRY,CALCULATION IN CHEMISTRY(EWELUKWA)

PHYSICS: SCIENCE-PHYSICS,NELKON & PARKER,NEW SCHOOL PHYSICS,PAST JAMB QUESTION & ANSWER ON PHYSICS.

BIOLOGY: COLLEGE BIOLOGY(IDODO UMEH),FOUNDATIONAL BIOLOGY,PAST QUESTION AND ANSWER ON BIOLOGY

ENGLISH: ONE-TIME SUCCESS IN JAMB,INVISIBLE TEACHER(DELE ASHADE),ORAL ENGLISH,

BIBLE: PRAY and FAST![/quote]AISHA

Do you think something could be wrong to have caused your not performing quite well in your exams?

How will you tackle them this year?

Any question on PHYSICS/CHEMISTRY/BIOLOGY.....i need to put some person through?!

taiocol: nt bad once

Yes Sir!

I want to use this opportunity to let you all knw that MED/SURG is
all dat easy to get.Though i pray such in your midst gives me no right
to knw how your strenght is.But i believe,the better you prepare the
more the challenge is easier to dealt with.However,the more we prepare
the less we certain to knw how best we have prepared.Our effort is
needed,the only price we can best pay! The common destroyer of our
effort are what we earnestly crave for and we honestly know they
actually do no better to our future goals.Try and

1) AVOID excess SOCIALNETWORKING(WHATAPP,2GO,BBM,and others)....they are
wasters of your effort,they don't add a common 1mark to your utme
result.If u are aiming more dan u can meet.Stop INCESSANT SOCIAL
NETWORKING.

2)ADAPT to reading as much as 9-12hours daily and yet untired!

3)PLAN a reading SCHEME and ensure to follow all day-long: everyday YOU must read something!

4)Stop talking about past failures.....Be happy about your present condition.......Be joyous because YOU knw that success is abreast with your daily effort

5)Never GIVE UP.....daz exactly wat MED/SURG meant for the winners


6)Always PRAY!

As you may starting preparing for your UTME examination some strategic
textbooks are needful,these text are even suitable for any trials,they
do help for students whom may be targetting great upper marks.I do list
them as below:

CHEMISTRY: NEW SCHOOL CHEMISTY,SENIOR SECONDARY SCHOOL CHEMISTRY(1-3)
STAN,JAMB PAST QUESTION AND ANSWER ON CHEMISTRY,CALCULATION IN CHEMISTRY(EWELUKWA)

PHYSICS: SCIENCE-PHYSICS,NELKON & PARKER,NEW SCHOOL PHYSICS,PAST JAMB QUESTION & ANSWER ON PHYSICS.

BIOLOGY: COLLEGE BIOLOGY(IDODO UMEH),FOUNDATIONAL BIOLOGY,PAST QUESTION AND ANSWER ON BIOLOGY

ENGLISH: ONE-TIME SUCCESS IN JAMB,INVISIBLE TEACHER(DELE ASHADE),ORAL ENGLISH,

BIBLE: PRAY and FAST!

1stUnique: u are welcome to d midst of upcoming medical practitioners. pls are u an aspirant or an undergraduate Sir.?

As a matter of fact am an ASPIRANT that has past so many experiences with the Nigerian universities and also got for my self concurrent 3-4 admission for different year examination from different UNI.But the problem is dat nor of the course given me was MEDIC/SURG....so am on the fight!....God helping me.....am in dis year!

UNILAG ASPIRANTS: Be prepared for CBT which is a profound test for both wise
and gullible aspirant....start past question as fast as u can!

UI aspirant: PLEASE UI Is not by mouth o!......You should ensure u av
done better in ur O'LEVEL to bookmark that school o!.The more the As and
Bs in ur O'LEVEL result the more u have chances to pass through UI hot
water.Should dnt just leap anyhow.....b wise.

UNIBEN ASPIRANT: UNIBEN'S putme is usually easily,it all requires ur
personnal effort.Atleast a mark of 70% Up should fetch u in....but if
less and 60 % up,u av chances for other department!

UNIPORT'S ASPIRANT: UNIPORT(UNIQUE PORTERS!) ASPIRANT should be prepared
for computer Base Test(CBT).The test is usually basic but
crucial,people alwys do fail it due to so many selfish reason like ''I
WANT TO SOLVE MATHEMATICS QST 1st'',Others like ''I HATE CBT'' bin
judgemental..........An available score of 280/400 upward should get u
into UNIPORT...brothers!

Just got so many to say.......I wish every one of you a happy newyear and an unperishable long-life full of exam success this year in JESUS NAME......

As a matter of fact i really love this thread.Please for the sake of expediency i humbly request that this humble thread allows me the opportunity to give all ANSWERS to both PHYSICS and CHEMISTRY questions.

Brinebryne: 16.4%

You wrong this time bro!..The answer is 20%


Should I show you how i got this answer?

If the cost of ELectricity required to deposit 1g of magnesium is 5.00-naira,how much would it cost to deposit 10g of Aluminium?




2 likely JAMB/WAEC/NECO questions for every one of us........cheers!

40cm^3 of air were mixed with 50cm^3 of hydrogen and was exploded.The total volume after the explosion was 66cm^3.

CALCULATE the percentage by volume of the oxygen in the air?.......wow!

Brinebryne: 1/4

Mehn!.....ye are CORRECT!

A mixture contains 20cm^3 of hydrogen,35cm^3 of oxygen,15cm^3 of carbon monoxide and 10cm^3 of nitrogen at S.T.P.What is the mole fraction of hydrogen in this mixture?


N.B ''^'' means RAISED-TO-POWER.

benny4wax: nice thread @ op.........



follow me and get followed back........

Alryt...broh!

[quote author=Dr. Laz'Devitan]Here is my question to start the THREAD.......


What are METAZOA organisms? List two METAZOA?[/quote]METAZOA are MULTICELLULAR ORGANISMS as diferentiated from UNICELLULAR organisms....examples of METAZOA could be FUNGI and MAMMALS...so many!.....