₦airaland Forum

vincent561: I dnt think so. He's already n d field.

vincent561: Nice one sir,bh i stl dnt think d question was asked in d ryt way.

vincent561: Defficiency of thiamin leads do which disease?

Influence01: The opening and closing of the stoma are regulated by
A.transpiration
B.respiration
C.diffusion
D.osmosis

Influence01: The opening and closing of the stoma are regulated by
A.transpiration
B.respiration
C.diffusion
D.osmosis

labodinho: Here we
go..

1)Sulhur(iv)oxide is a strong reducing agent in the presence of water
due to the formation of
A)trioxosulphate(iv) ion
B)hydroxide ion
C)sulphur(vi)oxide
D)hydrogen sulhide


2)A metal that forms soluble trioxosulphate(iv) salt is
A)Aluminium
B)Barium
C)Potassium
D)Manganese


3)Which of the following substances is not a salt?
A)Zinc chloride
B)Aluminium oxide
C)Sodium hydrogentrioxosulphate(iv)
D)Sodium trioxocarbonate(iv)

4)If 24.4g of Lead(ii)trioxonitrate(v) were dissolved in 42g of
distilled water at 20DCelcius,calculate the solubility of solute in
gdm^-3
A)58.100
B)581.000
C)0.581
D)5.810











I did not see it properly....pardon my error...this the proper answer
1)A 2)B 3)B 4)B

Prince adebayo: The living
part of a phloem tissue is

What is Tubectomy and vascetomy

What is Osteoporosis

The shortest and longest bones in the body are

The types of joints in between the ear ossicles are

Swagalord18: [color=cyan]
these questions have no solution yet
I think the questions are wrong,

prove me wrong by providing the solution please[/color]

Swagalord18: [color=cyan]
these questions have no solution yet
I think the questions are wrong,

prove me wrong by providing the solution please[/color]

aysuccess99: though i don't know it wella but i would try it according to my best of knowlege. i would use alkaline medium.
[ClO(3)]^(-1)+Zn--->Cl^(-1)+Zn^(+2)
Half Cell Equation.
[Cl(O)3]^(-1)---->Cl^(-1).....eqn 1
Zn--->Zn^(2+)
[Cl(O)3]^(-1)+H20---> Cl^(-1)+OH^(-1)
Zn--->Zn^(2+)+2e^(-1)........eqn2 (*3)
[Cl(O)3]^(-1)+3H20+6e^(-1)---> Cl^(-1)+6OH^(-1)
3Zn--->3Zn^(2+)+6e^(-1)
We then add the two equations up. we now have:
[Cl(O)3]^(-1)+3Zn+3H20+6e^/(-1)--->3Zn^(2+)+6e^/(-1)+ Cl^(-1)+6OH^(-1)
Then we have our final answer as:
[Cl(O)3]^(-1)+3Zn+3H20--->3Zn^(2+)+Cl^(-1)+6OH^(-1).
please bosses, my answer is subjected to correction. If I am wrong, please do correct me. thanks.

aysuccess99: the remaining equation is y^2-9y+21, but it is impossible to get the value of y here.
so all the values of y is now 2,7 and y^2-9y+21
i hope i am correct dr. lezdevitan

aysuccess99: solution
This question would need the application of polynomial.
We would first, expand the two equations i.e, (y^2-9y+15)(y^2-9y+20)=6
when we expand we have:
y^4-9y^3+20y^2-9y^3+81y^2-180y+15y^2-135y+300=6
then we collect like terms, we now have:
y^4-18y^3+116y^2-315y+300=6
we would now conclude our equation by bringing 6 to the RHS, we have.
y^4-18y^3+116y^2-315y+300-6=0
we then have:
y^4-18y^3+116y^2-315y+294=0
this is where the application of polynomial sets in.
so the first value that can divide and give us 0 in the equation is 2.
f(x)=y^4-18y^3+116y^2-315y+294.
when x=2, we have 0 as remainder.
f(2)=(2)^4-18(2)^3+116(2)^2-315(2)+294
f(2)=16-18(+116(4)-630+294
f(2)=16-144+464-630+294
f(2)=0
therefore, the first value of y=2

Kunlexic: screening effect of d nucleous on the electrons

kenshin17: state d 3 ways thru which radiation can b detected?

Odilop: Light from any ordinary source (such as a flame) is usually:
A. unpolarized
B. plane polarized
C. circularly polarized
D. elliptically polarized
E. monochromatic
An electron in an L shell of an atom has the principal quantum number:
A. n = 0
B. n = 1
C. n = 2
D. n = 3
E. n = ∞

taiocol: i got same ansa
nd frnd said i failed. He refused 2 solve it.