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EducationRe: Who Can Help Me With This Math Problem by rillchritty(m): 5:49am On Apr 19, 2024
MindHacker9009:
My solution is correct. That is the best way to simplify 4th root of x^6 using Radicals
You were taking square root!

Edit:
I just noticed you made the exact same mistake in evaluating the fourth root of 40x^2. Somehow , you seem to be mixing up fourth root (power of 1/4) and square root (power of 1/2). Why not try a bunch of numbers (apart from 0 and 1) on a calculator to see if your simplified expression matches the original?

Christianity EtcRe: Tinukevibes Slams 'Hausa' Muslims Offended By Her Dance Video In Saudi Arabia by rillchritty(m): 12:44am On Apr 19, 2024
Connoisseur:
Distance = speed * time
165 = (x-22) * 2 :from the question
165 = 2x - 44
2x = 165 + 44
x = 209/2
x = 104.5

That means the average speed on the return leg was 104.5km/h

The average speed on the first leg is therefore 104.5 + 22 = 126.5km/h

Time averaged on the first leg is;
165/126.5 = ~ 78mins
1hr 18 mins
You seem to have misinterpreted the information about the time taken for the return journey—it is not 2 hours; rather 2 hours more than the time taken for the forward journey.
EducationRe: Who Can Help Me With This Math Problem by rillchritty(m): 12:32am On Apr 19, 2024
MindHacker9009:
Madam turmacs we meet again. Here is the answer you need with workings from your super Software Engineer.
You made a mistake while evaluating the 4th root of x^6
EducationRe: Who Can Help Me With This Math Problem by rillchritty(m): 12:28am On Apr 19, 2024
rtdCivilservant:
Oya see the answer.
You can simplify it further. Also, a caveat needs to be added: the expression is only valid for non-zero values of x.

Christianity EtcRe: Tinukevibes Slams 'Hausa' Muslims Offended By Her Dance Video In Saudi Arabia by rillchritty(m): 11:49pm On Apr 18, 2024
SolarEngr:
Let's break down the problem step by step:

1. **Going to visit friends:**
- Distance: 165 miles
- Time: Let's call the time taken for this part of the trip: t_1
- Average Speed: s_1

2. **Returning from the visit:**
- Time: t_1 + 2hours (as it took 2 hours longer than the initial trip)
- Average Speed: s_1 - 22 mph (as the speed was reduced by 22 mph due to construction)

We can use the formula Distance = Speed×Time to find the average speed and time for each part of the trip.

For the first part of the trip:
165 = s_1 × t_1

For the return trip:
165 = (s_1 - 22) × (t_1 + 2)

Now we have a system of equations to solve for ( s_1 ) and ( t_1 ). Let's start by solving for ( t_1 ) in the first equation:
t_1 = 165/s_1

Substitute this expression for t_1 into the second equation:
165 = (s_1 - 22) × (165/s_1 + 2)

Now, let's simplify and solve for s_1:

165s_1 = (s_1 - 22) × (165 + 2s_1)

0 = 3276 - 22s_1
22s_1 = 3276
s_1 = 3276/22
s_1 = 148.91mph

Now that we have the average speed for the first part of the trip, we can find t_1 :
t_1 = 165/148.91
= 1.11 hours

For the return trip: t_1 + 2 = 1.11 + 2 = 3.11 hours
s_1 - 22 = 148.91 - 22 = 126.91mph

So, the time and average speed for each part of the trip are approximately:
- Going to visit friends: 1.11 hours at 148.91 mph
- Returning from the visit: 3.11 hours at 126.91 mph
Hi. You forgot the quadratic term when multiplying the terms in the brackets.

EducationRe: Who Can Solve This Maths? by rillchritty(m): 7:35am On Mar 28, 2024
Thabothabo101:
Please share the steps for displaying this the way it is. I imagine you use latex.
Yeah, I used latex with the Verbtex app, a latex editor for Android (https://play.google.com/store/apps/details?id=verbosus.verbtex). This is the latex source file:

\documentclass{article}
% Allow the usage of UTF-8 characters
\usepackage[utf8]{inputenc}
% Allow the usage of graphics (.png, .jpg)
\usepackage{graphicx}

\newcommand{\num}{8\times 10^{67}}

% Start the document
\begin{document}

% Create a new 1st level heading
\section*{}

The main idea is to observe that $\num$ is a large number and then use limit. It is known that $\lim\limits_{x\to \infty} \left(1-\frac{1}{x}\right)^x = \frac{1}{e}$. Hence, the expression $1 - \left(1-\frac{1}{\num}\right)^{\num} \approx 1-\frac{1}{e} \approx 0.632$.

Note that commonly available calculators cannot accurately evaluate the given expression. Due to their limited numerical precision, they evaluate $\frac{1}{\num}$ as zero, thus incorrectly giving the final answer as 0.

To correctly evaluate the expression numerically, one may use MATLAB, Octave, or any other computational software that supports variable-precision arithmetic. The one-line code in MATLAB or Octave is: \\
\\
vpa(1 - (1-1/sym(8e67))\^{}sym(8e67), 64)
\\

The second argument (\textbf{64}) passed to the \textbf{vpa} function is the number of significant digits in the final answer. Setting it too low will result in inaccurate evaluation.

% Uncomment the following two lines if you want to have a bibliography
%\bibliographystyle{alpha}
%\bibliography{document}

\end{document}
EducationRe: Who Can Solve This Maths? by rillchritty(m): 11:22pm On Mar 27, 2024
GABRIEL6036:
This is another method for you dummy 🤣
Given expression:
1

(
1

1
8
×
1
0
67
)
8
×
1
0
67
1−(1−
8×10
67

1

)
8×10
67



Simplify the inner expression first:
1

1
8
×
1
0
67
1−
8×10
67

1



To simplify the fraction, we can rewrite
8
8 as
2
3
2
3
:
1

1
2
3
×
1
0
67
1−
2
3
×10
67

1



This can be further simplified to
1

1
2
3
×
1
1
0
67
1−
2
3

1

×
10
67

1



Which simplifies to
1

1
8
×
1
1
0
67
1−
8
1

×
10
67

1



Further simplifying, we get
1

1
8
×
1
0
67
1−
8×10
67

1



So, the inner expression simplifies to
1

1
8
×
1
0
67
1−
8×10
67

1



Now, raise this to the power of
8
×
1
0
67
8×10
67
:
(
1

1
8
×
1
0
67
)
8
×
1
0
67
(1−
8×10
67

1

)
8×10
67



Since
8
×
1
0
67
8×10
67
is a very large number, this term approaches


1
e
−1
as the exponent approaches infinity. So, this term simplifies to


1
e
−1
(where

e is Euler's number, approximately
2.71828
2.71828).

Finally,
1



1
1−e
−1
is approximately
0.63212
0.63212.

Therefore, the result of the expression is approximately
0.63212
0.63212
That's exactly the answer I already gave in my original reply! And for goodness sake, format your post properly; it is hardly readable.
EducationRe: Who Can Solve This Maths? by rillchritty(m): 11:20pm On Mar 27, 2024
sunsweet33:
Well…in the modern world it’s more sensible to use a calculators and AI robots…in consequence you can see the whole page littered with wrong answers…never mind.. 🤷🏾‍♀️
It depends on the level of precision required in the application. If your application involves computation with numbers as large as 8*10^67, then surely, the precision offered by common calculators is going to be inadequate.
EducationRe: Who Can Solve This Maths? by rillchritty(m):
Light78:
Okay

I just used my project computer
The approximation in your second step is not precise enough. Check my reply to @GABRIEL6036's post above.
EducationRe: Who Can Solve This Maths? by rillchritty(m):
GABRIEL6036:
Me wey be guru in math... Let's solve and brake it down...


8
×
1
0
67
8×10
67
is a very large number, so
1

(
8
×
1
0
67
)

1
1−(8×10
67
)
−1
is essentially
1

0
1−0, which equals 1.

So, the expression becomes
1

1
8
×
1
0
67
1−1
8×10
67

.

1

1
n
is always 1 for any value of

n, so
1
8
×
1
0
67
1
8×10
67

is also 1.

Finally,
1

1
1−1 equals 0.

Therefore, the result of the expression is 0.
Careful with your assumptions! For a large number x, although 1/x is close to zero, the expression (1 - 1/x)^x is NOT close to 1. Its value is approximately 1/e, where e is Euler's number (e = 2.71828). To understand why that is so, read about limits in any introductory calculus textbook.

If you are not convinced, try to evaluate (1 - 1/x)^x for a set of increasingly large numbers that your calculator can handle, say, x = 8*10^16, 8*10^17, 8*10^18,... What you will notice is that the answer keeps getting closer and closer to 0.36787944117144, and when you get to about 8*10^31, you suddenly start getting 0 (showing that the numerical precision of the calculator is no longer enough for accurate evaluation of the expression). To avoid this, one must use variable precision arithmetic instead (MATLAB and Octave support that functionality).
EducationRe: Who Can Solve This Maths? by rillchritty(m): 10:49pm On Mar 27, 2024
sunsweet33:
Everybody is saying it’s 0, does it mean all their calculators are faulty…
Yes, I can authoritatively say that they are all wrong! I explained in my original reply why a calculator that does not have capacity for variable precision arithmetic CANNOT correctly evaluate the expression.
EducationRe: Who Can Solve This Maths? by rillchritty(m):
Winterhaven:
Good one. I'm expecting the workings.
I have modified my reply above to include the logic of the solution.
EducationRe: Who Can Solve This Maths? by rillchritty(m):
The answer is approximately 1-1/e = 0.632. I will upload the workings when I get to my laptop.

Edit:
See the attached image for the evaluation

EducationRe: Different Words With The Same Pronunciation by rillchritty(m): 4:12am On Mar 06, 2024
Jewessgratitud3:
Seen and sin are homophones because they have the same pronunciation. We are not talking about contrast between the long and short forms of the /I/ vowel nor the place of articulation here. We are talking about words that sound the same basically.
As I already said, the long 'I' and the short 'i' are NOT variants of the same sound. Being termed 'long' and 'short' does not mean that they are distinguished by duration only. They sound completely different when correctly pronounced. Listen carefully to the British (and American) pronunciation of 'seen' (https://dictionary.cambridge.org/pronunciation/english/seen) and 'sin' (https://dictionary.cambridge.org/pronunciation/english/sin).
EducationRe: Different Words With The Same Pronunciation by rillchritty(m): 9:02pm On Mar 05, 2024
Rexymania:
Come
Cum

Fan
Fan

Sheet❌
Shit❌

Fvck❌
Fork❌

Dick
Dick

grin
EducationRe: Different Words With The Same Pronunciation by rillchritty(m): 9:00pm On Mar 05, 2024
KanielOutis92:
Porn/Pun❌


Boo Harry/ Beau Harry / Buhari
The words 'porn' and 'pun' are not homophones; their phonetic representations are /pɔːn/ and /pʌn/. Most Nigerians incorrectly pronounce the short vowel /ʌ/ either as short 'o' (as in 'lot') or as the long vowel sound /ɔ:/ (as in 'lord'). Actually, it is closer to the schwa sound than any of these two. My post assumes British English.
EducationRe: Different Words With The Same Pronunciation by rillchritty(m): 8:44pm On Mar 05, 2024
poshestmina:
Thought/Taught.
Of/off
Seen/sin ❌
Steal/steel
Bye/buy
Know/No
New/knew
Fare/fair
Heir/Air.
Loose/lose
Save/safe ❌
In addition to what others have highlighted, 'seen' and 'sin' are not homophones; they do NOT sound the same at all. The former has the long 'I' sound, whereas the latter has the short 'i' sound. Note that these two vowel sounds are phonetically distinct and require different lip opening and tongue positions to pronounce. Unfortunately, Nigerian students are not taught to properly distinguish them. Another example is 'sheep' and 'ship'.
The words 'save' and 'safe' feature two different consonants: 'v' and 'f', respectively.
EducationRe: Only A Genius Can Answer This! by rillchritty(m): 9:30pm On Mar 01, 2024
Verbtips:
on point
good one see this
logic question
oasis is to desert,
..........is to ocean
Island, perhaps?
The former is surrounded by the latter.
EducationRe: Only A Genius Can Answer This! by rillchritty(m): 9:24pm On Mar 01, 2024
Verbtips:
dis one no concern quadratic equation na just small reasoning
Of course, the exercise is not intended to test mathematical prowess. However, ability to understand the different possible patterns in which valid answers could be constructed is a good 'small reasoning' skill. After all, innovative solutions to real-world problems are sometimes inspired by trivial questions like this one.
EducationRe: Only A Genius Can Answer This! by rillchritty(m):
Assuming each expression is independent of the preceding expressions, the general rule is a + b = a * (b+1). Hence, 5 + 11 = 5 * (11+1) = 60.

Conversely, if an expression depends on the one immediately preceding it, then the answer by @snowball11 is also correct. The general rule in this case is c(n) = a+b = c(n-1)+a+b, so c(4) = 5+11 = c(3)+5+11 = 24+5+11 = 40.

(edit)
It turns out there is another possible answer (see @Panda7's post below). The structure of each expression is c(n) = a(n+2) + b(n+2), where a(n+2) is the (n+2)th Fibonacci number, and b(n+2) is the (n+2)th arithmetic integer. The Fibonacci sequence is 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, .... [1], while the arithmetic integer sequence is 1, 3, 5, 6, 7, 11, 13, 14, 15, 17, 19, 20, 21, 22,... [2]. The general rule is c(n) = a(n+2) + b(n+2) = a(n+2) + n*b(n+2). Hence, c(4) = a(6)+b(6) = 5+4*11 = 49.
This last approach, inspired by @Panda7's answer, perhaps overcomplicates the solution, but it explicitly shows how the terms of the expressions are constructed. It is more general and mathematically sound than the other two approaches already listed. In fact, one may construct subsequent expressions independent of preceding expressions, for example, the next expression is c(5) = 8 + 13.

References:
[1] https://en.m.wikipedia.org/wiki/Fibonacci_sequence
[2] https://en.m.wikipedia.org/wiki/Arithmetic_number
EducationRe: Help Solve This Mathematics Question by rillchritty(m): 9:42am On Feb 09, 2024
The radius of the smaller ball is 2 times cube root of 3 (i.e., cube root of 24). See the attached image.

EducationRe: Mathematicians In The House, Please Help! by rillchritty(m): 3:27am On Jan 18, 2022
ntrukpum:
Please help me solve this further mathematics problem. Question Number 20
Find the solution in the attached images. The first method uses substitution to solve the two simultaneous equations resulting from the matrix and vector multiplication, while the second method approaches the problem as an eigenvalue decomposition problem (you can read about eigenvalue decomposition in any introductory textbook on linear algebra).

TravelRe: Need Help With Direction by rillchritty(m): 7:21am On Oct 05, 2021
Hi. Please, at what bus stop or place do I need to alight when travelling to Shasha Road Akowonjo (either De Santos Hotel or GIGM terminal) from Oshodi? I know that buses go directly from Oshodi to Egbeda-Akowonjo area, but I don't know where to alight. Please help. Thank you in advance.
EducationRe: Cost Of Writing The TOEFL Exams by rillchritty(m): 5:03pm On May 22, 2019
It costs about 60k naira at B.Y. Mafit (https://www.gregmattoeflnigeria.com/toeflcentresinnigeria/). The official cost is $195 (https://www.ets.org/toefl/ibt/about/fees/).
EducationRe: Can You Solve This? (Pics) by rillchritty(m): 11:31pm On Feb 04, 2019
Kylekent59:
I won't solve it all, you have to finish it up.

It's very very simple.


In the End you will use this technique

Such as this

1/( 1 - 1/a) = a / ( a - 1)

Something like this will be done but not this oo.

To make the answer look like what's given
Your expansion of the right-hand term is wrong!!

EducationRe: Can You Solve This? (Pics) by rillchritty(m): 11:15pm On Feb 04, 2019

EducationRe: Apply For 2018/2019 PTDF PHD And Msc Overseas Scholarsip At The United Kingdom by rillchritty(m): 8:56pm On Jun 19, 2018
Only two per state, apart from Benue and Kano States. No special treatment for oil producing states. I was expecting up to five from each state.
Jobs/VacanciesRe: Unicane Industries Limited Invitation For Interview by rillchritty(op): 2:02pm On Aug 10, 2017
Lekzen:
Rillchritty, pls did u evenyually make it for this interview, and if so how did it go by, pls if u wouldn't mind i will like to have a one on one chat with u, thanks
Hi, unfortunately, I didn't make it to the interview then. However, they just rescheduled me again for next week. According to them, it is going to be a practical interview, in which you show them what you can do.
EducationRe: Where Are The CSI Experts??? Abeg, Help Us Catch This Murderer. by rillchritty(m): 8:49pm On Aug 09, 2017
The woman (No 3) is the culprit. Reasons - 1. it is women's toilet (a man entering a ladies room would certainly raise suspicions). 2. the surprise on the waiter's face on seeing another woman at the table (the now deceased woman must have been sitting there before). 3. the woman was stabbed in the back (implying her back was turned towards the culprit, while she was using the washroom; were a man the killer, the victim would probably be facing him, possibly screaming too, the moment he enters).

Of course there's a little case against No 4 (missing table knife, stain (blood??) on the neck). However, the case against No 3 is stronger.
EducationResearch topics in photonics (closed) by rillchritty(op):
Hi. What are the subfields of photonics (applied or fundamental), which are currently the subject of active academic research? I have long been inclined towards optical fiber sensing, toyed a little with the idea of researching multiplexing techniques. However, the more I read research papers, the more I feel that there is no gap left. Quite frustrating! Semiconductor photonics seems to be an interesting research subfield, but I cannot come up with any original research ideas. Please, if anyone could point me in a good direction, I would very much appreciate it. Thanks
Jobs/VacanciesRe: Process Engineer Wanted At Procter & Gamble Nigeria. Apply Now by rillchritty(m): 3:02pm On Jul 24, 2017
josefayo:
When did you get a feedback? How long did it take to get a feedback from them?
I got rejection email on 4th July

1 2 (of 2 pages)