₦airaland Forum

please those that have used london used laptops should share their experience because i am planning on buying a laptop but my budget cannot afford a new laptop with the specification i want so i have decided to opt for the london used types just that i am doubting their durability

[quote author=Saaog post=29173232]Ten (10) outstanding students of the University of Lagos have received the 2014 Etisalat Merit Scholarship Awards of One Hundred Thousand Naira (N100, 000.00) each. Click here to see the names of the students

The ten awardees were presented with their certificates of awards at the Etisalat Merit Award Ceremony which was held on Wednesday, December 17, 2014 at the Oriental Hotel, Victoria Island, Lagos.

During the ceremony, five (5) tertiary institutions selected for the 2014 Etisalat Merit Award exercise also received One Hundred Thousand Naira (N100, 000.00) each. The five institutions are: University of Lagos, Lagos; Obafemi Awolowo University, Osun State; Ladoke Akintola University of Technology, Osun State; Adekunle Ajasin University, Ondo State and University of Benin, Edo State.

As part of the programme of events at the awards ceremony, selected scholars of the five institutions made five (5) minutes presentations on innovations of their choice. Tagged “The Etisalat Innovation Moment”, presentations were judged based on Adaptability, Value, Social Impact, Environmental Impact and Rate of Feasibility. The presentation by team UNILAG: “PROJECT SMC (Social Media Centre) got the third position while the first and second positions went to University of Benin and Obafemi
Awolowo University, respectively.
do the recipients of this scholarship undergo any form of test or screening or do they just use the names given to them by the school

The awardees from the University attended the award ceremony along with the Hall Mistress of Moremi Hall, Dr. Virgy Onyene (who represented the Vice-Chancellor, Professor Rahamon A. Bello, FAEng on behalf of the Dean, Students’ Affairs Division, Professor G.O. Babawale) and a 3-man team of Office of Advancement: Mrs. M.I. Enuoyibo, Mr. T.O. Akeju and Mr. B.E. Oreyomi.

The UNILAG delegation to the event presented the dummy-cheque of the total amount of the cash awards won by the University and ten students (One million, one hundred thousand naira: N1, 100,000.00), to the Vice-Chancellor, Professor Rahamon A. Bello, FAEng on Tuesday, December 23, 2014. The presentation was done by the Dean, Students’ Affairs Division, Professor G.O. Babawale; Hall Mistress of Moremi Hall, Dr. Virgy Onyene and Acting Head, Office of Advancement, Mrs. M.I. Enuoyibo.

The Etisalat Merit Award is a Scholarship Scheme designed to fulfil the company’s goal of empowering the society through knowledge acquisition and promoting education within Nigeria. The Scheme focuses on awarding grants to second and third year students attending Nigerian universities.

Students of the University of Lagos have been selected for the award for three (3) years: 2009, 2010 and 2014. Each year, a total of ten (10) students drawn from the Computer Sciences, Electrical/Electronics Engineering and Management Science fields of study are selected for the awards.

» Do you have an urgent Info, Article, Publication, or Notice to broadcast? We will do it free for you. Inform students by Clicking here[/quote
did recipients of the scholarship undergo any form of screening asides the one done by their respecive schools before their names got fowarded

FunnyDude:
Taaar! If I hear.

Taar talk ur own if u think say i dey lie

DID OP FORGET PHYSICS? THE MOTHER OF SCIENCE

maiduguri should be his PPA

wetin dem wan use my sperm do

hacking olmpics?abeg na when them go begin yahoo yahoo olmpics make i apply

this op can lie ,i have seen this particular picture but that snake has only three heads ,op decided to add four more heads just to suit his purpose

if you believe these guys are lying click like

ENGLISH HARD

I PRAY THIS PROMISE IS FULFILLED I CAN'T JUST IMAGINE SPENDING FOURTEEN HOURS JUST TO TRAVEL FROM JOS TO CAL DUE TO THE BAD ROAD ,ONE OF THE MAJOR REASONS I HATE GOING HOME FOR HOLDAYS

why do you guys keep shouting the last sixteen yrs as if nigeria was better than it is today in the last sixteen , hope you can alll remember that nigeria got independent in 1960 between that period and now ur saint buhari was also a president and a minister if our past leaders should be blamed for our predicament buhari should also take part of the blame

the old mallam is confused

i'm trying not to take sides here but how did kare know the money he was given was $50000 when he did not colllect or may be he saw that in a vision just the way he saw buhari winning the 2011 election

counted 33

should we really be apologising ,i think biafra owes us some gratitude for surrendering instead of allowing the hausas and yorubas succeed in their genocide

can anyone advice me on how to invest this little money i have saved up and pls take cognizance of time cos i'm a student

naturalwaves:
Let me help you....

thanks .if you don't mind can u pls help with the explanation to this

3. Prove that the equation mx(x2 + 2x + 3) = x2 – 2x – 3 has exactly one real root if m = 1 and exactly 3 real roots if m= -2/3



For this question, you can use Descartes's rule of signs. You should actually use the more detailed Sturm's extension of this rule, but i think the former could be okay here.
Descartes's rule of signs says if v is the variation of sign in a polynomial p(x) and the number of positive real zeros (roots) is n, then
n<=v and v-n is even.

Same applies to number of negative real zeros with p(-x)

With m=1, you get
x3 + x2 + 5x + 3 = 0

p(x) = x3 + x2 + 5x + 3
No sign variation, so v=0.
n will also be 0 so there are no positive real roots.

p(-x) = -x3 + x2 - 5x + 3

Number of sign variation is 3 (- to + to - to +)
n will be 1, so that 3-1 is even. So there's a negative real root.

Equation thus has one negative real root and two complex roots which will be conjugates.


With m= -2/3

p(x) = -(2/3)x3 - (7/3)x2 + 3

Number of sign variation is 1. n will be 1 so that 1-1=0 which is even.
Hence, one positive real root.

p(-x) = (2/3)x3 - (7/3)x2 + 3.

Number of sign variation here is 2. n cannot be 1, cos v-n should be even. So n is 2. And 2-2=0.
So we have two negative real roots.

Hence, three real roots (one positive and two negative)

goofyone:
If -i is a root, i will also be a root following the complex conjugate theorem. I can prove that if you want, but i don't think it's relevant to do that here.

Hence, two roots already, ± i

(x+i)(x-i) = x² -i.i = x² + 1

x⁴ + 4x³ + 6x² + 4x + 5 divided by x² + 1 to get the other factor.

Division produces x² + 4x + 5

Solving with quadratic equation: ¹/₂(-4 ± √(16 - 20))
x = -2 ± i

please boss check the division ,i have been trying to follow up the solution but couldn't come up with same answer as ur's don't knw if i'm doing the wrong thing

goofyone:
| 1 1 1 |
| x y z |
| x² y² z² |

= (y.z² - z.y²) - (x.z² - z.x²) + (x.y² - y.x²)
=zy(z-y)-zx(z-x)+xy(y-x)
=z(y(z-y) - x(z-x)) + xy(y-x)
=z(yz-xz + x² - y²) + xy(y-x)
=z(z(y-x)+(x-y)(x+y))+xy(y-x)
=z(z(y-x)-(y-x)(x+y))+xy(y-x)
=z(y-x).(z-(x+y))+xy(y-x)
=(y-x)(z.(z-(x+y)+xy)
=(y-x)(z²-zx-zy+xy)
=(y-x)(z²-zy+xy-zx)
=(y-x)(z(z-y)-x(z-y))
=(y-x)(z-x)(z-y)

i want to say a big thank you to all maths gurus who helped me out in solving my mathematical problem, i love you all and i really appreciate you all.....

naturalwaves:
Check the first question well, there are 2 functions there, which of them do we go with? I guess it is the second one but quickly review it or take a snapshot of the question....waiting....

modified

goofyone:
For this question, you can use Descartes's rule of signs. You should actually use the more detailed Sturm's extension of this rule, but i think the former could be okay here.
Descartes's rule of signs says if v is the variation of sign in a polynomial p(x) and the number of positive real zeros (roots) is n, then
n<=v and v-n is even.

Same applies to number of negative real zeros with p(-x)

With m=1, you get
x³ + x² + 5x + 3 = 0


p(x) = x³ + x² + 5x + 3
No sign variation, so v=0.
n will also be 0 so there are no positive real roots.

p(-x) = -x³ + x² - 5x + 3

Number of sign variation is 3 (- to + to - to +)
n will be 1, so that 3-1 is even. So there's a negative real root.

Equation thus has one negative real root and two complex roots which will be conjugates.


With m= -²/₃

p(x) = -(²/₃)x³ - (⁷/₃)x² + 3

Number of sign variation is 1. n will be 1 so that 1-1=0 which is even.
Hence, one positive real root.

p(-x) = (²/₃)x³ - (⁷/₃)x² + 3.

Number of sign variation here is 2. n cannot be 1, cos v-n should be even. So n is 2. And 2-2=0.
So we have two negative real roots.

Hence, three real roots (one positive and two negative)

i want to say a very big thank your to all of those gurus who helped me in solving the maths problem i pasted, i appreciate all of you with a million thanks. pls i still need you help on this other question>


1. let a function f be defined by
f(x)=x²-2x-3/x²+2x+3
a. determine the domain of f(x)
b. find the range of f(x)
c. find and expression for f(3x+1)

2. show that | 1 1 1 |
................... | x y z | = (y-x)(z-x)(z-y) ( its a matrix problem)
....................| x² y² z² |

waiting for your help gurus...........

Please guys I need help in the following question.
1. Find the roots of the polynomial p(x) = x⁴ + 4x³ + 6x² + 4x + 5=0 given that one of the roots is x = -i
2. Each of my 39 friends has either a dog, a cat or a rabbit. 24 of the have a dog, 17 have a cat and 16 have a rabbit. The number having both dog and cat is 1 more than the number having both cat and rabbit. There are 9 who have both dog and rabbit, while two of them have all three. How many of my friends have both rabbit and cat?
3. Prove that the equation mx(x² + 2x + 3) = x² – 2x – 3 has exactly one real root if m = 1 and exactly 3 real roots if m= -2/3

cc
Dejt4u
Benbuks
jackpot
Arithmetic
Naturalwaves
Richies
Amazing angel
Agentofchange1

frob0genius:
I do have it. How can I send it to you?
It's over 10mb

please i am also in need of it, you can send it to this

pls house come to my rescue :
1.express the scalar product of two vectors in term of their covariant and contravariant components.
2.write a condition for the point A,B and c to be collinear.
(I) show that(a ×b)+(b×c)+(c×a)=0
3.let f(x)=x³+2x²_kx+5. k is defined to be one third of the rank of the matrix below
A=|3 -4|
.. ..|1 -1|
compute f(A)
@benji93, akpos4uall,thankyoujesus,kendzyma et al please i need your help on this

[quote author=saaedlee post=32351661]They should replicate their behaviour but make sure APC gets majority of votes![/quote
U MUST BE DREAMING IF YOU THINK APC CAN WIN IN JOS]