Oxide65:
Very well. Thanks alot. Im very sorry i could have been more specific. Could you try using the €-N argument? I'm sure you must be familiar with it because from what I've seen, I must confess all my mathematical problems died when I found this link.

ok...uwc.man...whats €-N...?. sir ...
i probably don't know it.

Arithmetic: @boss, (b), can be solved also by DE MOIVRE'S Theorem... My opinion.

yes...my guy....

use it lets see.

benbuks:

ok...uwc.man...whats €-N...?. sir ...
i probably don't know it.

it's d epsilon -N argument of proving convergence.

find the values for which the following are TRUE
(a)tan^2¢+2ec¢=5 ........0<=¢<=180
(b)sin¢-cos2¢+3=0........-180<=¢<=180

pls gurus in the house come to my rescue

pls help solve this WAEC question
make q subject of formula;
a/p - b/q = c

I've tried, bt my answer doesn't correspond with the one at the back of the textbook

Preboy: pls help solve this WAEC question
make q subject of formula;
a/p - b/q = c

I've tried, bt my answer doesn't correspond with the one at the back of the textbook

q = bp/(a-pc)

[quote author=Preboy]pls help solve this WAEC question
make q subject of formula;
a/p - b/q = c

I've tried, bt my answer doesn't correspond with the one at the back of the textbook[/quote

[quote author=Preboy]pls help solve this WAEC question
make q subject of formula;
a/p - b/q = c

I've tried, bt my answer doesn't correspond with the one at the back of the textbook
very difficult question.

.

Preboy: pls help solve this WAEC question
make q subject of formula;
a/p - b/q = c

I've tried, bt my answer doesn't correspond with the one at the back of the textbook

Cheap.
Step1----add b/q to both sides and subtract c from both sides
U will have--- a/p - c = b/q

Step2------ take LCM of left hand side
U will have--- (a-cp)/p = b/q

Step 3------ take inverse of both sides
U will have--- p/(a-cp) =q/b

Step 4--- multiply both sides by b
Final ans----- q = bp/(a-cp)

Preboy the workings are here. Initially missunderstood the question

dejt4u:
q = bp/(a-pc)

your answer is correct, plz the workings

Preboy:
your answer is correct, plz the workings

a/p - b/q = c,
a/p - c = b/q,
(a-pc)/p = b/q,
q(a-pc) =bp,
q= bp/(a-pc)

dejt4u:
a/p - b/q = c,
a/p - c = b/q,
(a-pc)/p = b/q,
q(a-pc) =bp,
q= bp/(a-pc)

wow kul method, just solved it though my method is way longer and different

a/p - b/q = c
qa - bp/pq = c
qa - bp = cpq
qa - cpq = bp
q(a - cp) = bp
q = bp/a- cp

guys i'm bad @ maths, can you gurus pls recommend any maths textbook/ebook that'll help.

hnm..

Khoded: guys i'm bad @ maths, can you gurus pls recommend any maths textbook/ebook that'll help.

what level .?

I am thinking of a 6-digit number. The sum of the digits is 43 and only two of the following three statements about the number are true:

1.It is a square number
2. It is a cube number and
3. The number is under 500000

Also tell me which of the statements are true and give ur answer!

benbuks:


_>>>>>>_____SOLUTION_________<<<<<<<<_

By roots of cubic equations of the form

px³ +qx² +rx + s = 0 , for a=/= 0

sum of roots (a +b+c) = -q/p

sum of product of roots (ab + ac + bc ) = r/ p

product of roots ( abc) = - s/a

thus we have

a+b+c = -2/√2 =-2√2/2 = -√2

ab+ac+bc= 3√2/√2 =3


abc =5/√2 = 5√2/ 2

that's it sir.

Correct!

What about this?

Obinoscopy: Dear Maths Guru,

Cauchy Integral Test: Can someone discuss with examples?

Obinoscopy: Correct!

What about this?

sorry sir , idea currently unavailable .

maybe when i study it , I'll be able to decipher something .

Soneh: find the values for which the following are TRUE
(a)tan^2¢+ 2ec¢=5 ........0<=¢<=180
(b)sin¢-cos2¢+3=0........-180<=¢<=180

pls gurus in the house come to my rescue

@ bolded is it sec.tita or 2 sec.tita ....?

benbuks: I am thinking of a 6-digit number. The sum of the digits is 43 and only two of the following three statements about the number are true:

1.It is a square number
2. It is a cube number and
3. The number is under 500000

Also tell me which of the statements are true and give ur answer!

only 1 nd 3 are true.. And the number is 499849

benbuks:

@ bolded is it sec.tita or 2 sec.tita ....?

oops its 2sec tita
thanks

Please help me solve these question with clarity

1. Find the total surface area of a solid hemisphere of diameter 6.6

2. A solid is made up of a cylinder with a hemisphere on top. Calculate its surface area.
3. Find the volume of a given triangular prism with a right-angled triangle 9cm by 12cm by 16cm and length 18cm
4.how many tiles each of side 8cm are needed to tile a floor 22m 40cm long by 12m 80cm wide
5.a rectangular pool 10m by 5m is surrounded by a path 1m wide. What is the area path ... Please show workings in all

Obinoscopy: Dear Maths Guru,

Cauchy Integral Test: Can someone discuss with examples?

Do u mean that Which ascertains convergence of series?

Oxide65:








Do u mean that Which ascertains convergence of series?

Yes!


I want to understand it from another mathematician's perspective.

Kovic08: Please help me solve these question with clarity

1. Find the total surface area of a solid hemisphere of diameter 6.6

...Please show workings in all

Total surface area of a sphere = 4Πr²@
An hemisphere contains half of d total surface of sphere + a circle
i.e surface area of hemisphere = [(4Πr²)/2] + Πr²
= 2Πr² + Πr² = 3Πr²
since diameter = 6.6 units
radius = 3.3 units
therefore, total surface area = 3×Π×3.3²
= 102.68 sq units

Kovic08:
2. A solid is made up of a cylinder with a hemisphere on top. Calculate its surface area.
... Please show workings in all

for a joined hemisphere nd cylinder,
curved surface area of hemisphere = 2Πr²
curved surface area of cylinder = 2Πrh (where h=height of d cylinder)
area of base circle of d cylinder = Πr²
therefore, total surface area = 2Πr² + 2Πrh + Πr²
= 3Πr² + 2Πrh
= Πr(3r + 2h)

Kovic08:
3. Find the volume of a given triangular prism with a right-angled triangle 9cm by 12cm by 16cm and length 18cm

are u sure of d dimension of triangle "9 by 12 by 16"? d combination can never form a right angled triangle, I guess d 16 should be 15. If so,
volume of a solid shape = base(triangular) area × height
= (½*9*12) × 18
=972cm²

Kovic08:
4.how many tiles each of side 8cm are needed to tile a floor 22m 40cm long by 12m 80cm wide
... Please show workings in all

N.B 100cm = 1m
I guess d tile is a square tile
To calculate d number of tiles, U'll calculate d area of d floor, then divide it by d area of d tile
In calculating d area of d floor, U'll make use of just a unit (I'll use cm)
length of floor = 22m40cm = 2240cm
breadth of floor = 12m80cm = 1280cm
Area of the floor = 2240 × 1280 cm²
Area of tiles = 8 × 8 cm²
Therefore number of tiles = (2240×1280)/(8×
=44800 tiles

Kovic08: 5.a rectangular pool 10m by 5m is surrounded by a path 1m wide. What is the area path ...

16m²

total dimension is 11m by 6m
total area = 66m²
area of the pool= 50m² (from d dimension 10m by 5m)..

Area of the lawn = 66m²-50m² =16m²

Kovic08:
5.a rectangular pool 10m by 5m is surrounded by a path 1m wide. What is the area path ... Please show workings in all

checking dat question properly, two rectangles are involved, one with dimension 10m by 5m, the other rectangle(considering the path) with dimension (10+1)m by (5+1)m

To calculate d area of d path, U'll subtract d area of d smaller rectangle from d larger one

Area of smaller rectangle = 10m × 5m = 50m²
Area of larger rectangle = 11m × 6m = 66m²
therefore, area of d path = 66 - 50m² = 16m²

Drniyi4u:
checking dat question properly, two rectangles are involved, one with dimension 10m by 5m, the other rectangle(considering the path) with dimension (10+1)m by (5+1)m

To calculate d area of d path, U'll subtract d area of d smaller rectangle from d larger one

Area of smaller rectangle = 10m × 5m = 50m²
Area of larger rectangle = 11m × 6m = 66m²
therefore, area of d path = 66 - 50m² = 16m²

IMO tho, I think the length and breath of the larger rectangle should be 12m and 7m respectively,since the path covers all the 4-sides,therefore it adds 2m to the length and the breath...