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Mathematics Clinic / 2015 Cowbell Mathematics Champion, Akinkuowo Honoured By School. / Lead City University Clinic Welcomes First Ever Baby Since 10 Years Of Opening (2) (3) (4)
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Re: Nairaland Mathematics Clinic by pauljustina(f): 4:47pm On May 16, 2017 |
thank you very much 1 million kisses for you @ icosahedron |
Re: Nairaland Mathematics Clinic by pauljustina(f): 9:38pm On May 16, 2017 |
1.Msquared-9/Msquared-m-6 multiplied by m+2m/Msquared 2.Asquared-Bsquared/ab+Asquaredmultiplied by 2Acubed/ab-Asquared 3.Asquared-ab-6Bsquared/Asquared+ab-6Bsquared multiplied by Asquared-ab-2Asquared/Asquared-2ab-3Bsquared 4.Asquared+ab-2Bsquared/Asquared-2ab-3Bsquared multiplied by Asquared-Bsquared/ab+2Bsquared divide by Asquared-2ab+Bsquared/A squared-3ab |
Re: Nairaland Mathematics Clinic by Engrcharlesid(m): 10:11pm On May 16, 2017 |
pauljustina: just refer us to new general mathematics for ss 2 |
Re: Nairaland Mathematics Clinic by CACAWA(m): 9:55am On May 17, 2017 |
Re: Nairaland Mathematics Clinic by CACAWA(m): 9:56am On May 17, 2017 |
inschool: Can I see your workings or you just tested numbers like those guys? |
Re: Nairaland Mathematics Clinic by inschool(m): 10:51am On May 17, 2017 |
CACAWA:my working is on the screnshot |
Re: Nairaland Mathematics Clinic by CACAWA(m): 10:52am On May 17, 2017 |
inschool:no it only shows you testing those numbers to confirm they are right. How did you arrive at 2 and 3 |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 10:57am On May 17, 2017 |
pauljustina:y not post an image instead . |
Re: Nairaland Mathematics Clinic by inschool(m): 11:13am On May 17, 2017 |
CACAWA: How did you arrive at 2 and 3[/quote] X^y +Y^x =17.................(1) X +Y =5..........................(2) Now, 17 =2^3 +3^2 hence, X^y +y^x =2^3 +3^2............(3) comparing both sides of (3), we found: x=2, y=3 or y=3, x=2(ans) |
Re: Nairaland Mathematics Clinic by CACAWA(m): 11:18am On May 17, 2017 |
inschool:i said.....How did you get to 2 and 3. Did you use any analytical methods like logarithms or did you use trial and error as follows: Let x and y be 2 and 3, Hence, replacing them in both equations, we can agree that x and y are actually 2 and 3. Which approach did you use? |
Re: Nairaland Mathematics Clinic by inschool(m): 11:35am On May 17, 2017 |
CACAWA:because 17 can be expressed as the sum of two powers |
Re: Nairaland Mathematics Clinic by inschool(m): 11:35am On May 17, 2017 |
CACAWA:not analytical method though |
Re: Nairaland Mathematics Clinic by CACAWA(m): 11:39am On May 17, 2017 |
inschool: I see...So kindly send me the original analytical workings via WhatsApp. Thnx It's not that difficult |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 4:04pm On May 17, 2017 |
Re: Nairaland Mathematics Clinic by Adeboyefa(f): 12:02am On May 18, 2017 |
Richiez: If you test y=2, (5 - y) ^(5 - y) + y^y = 3^3 + 2²= 27 +4 = 31. So y = 2 or 3. If y = 2, x + y =5 ➡ x + 2 = 5 ➡ x = 3. So we have 2 answers: x=2 when y=3, and x =3 when y = 2. |
Re: Nairaland Mathematics Clinic by Icosahedron(m): 8:14pm On May 19, 2017 |
Hmm |
Re: Nairaland Mathematics Clinic by Icosahedron(m): 9:09pm On May 19, 2017 |
Point P lies inside triangle ABC.Lines AP,BP,CP meet the circumcircle of ABC again at points K, L,M,respectively.The tangent to the circumcircle at C meets line AB at S. Prove that SC = SP if and only if MK = ML |
Re: Nairaland Mathematics Clinic by DrinkWater10: 4:02pm On May 20, 2017 |
Please I need urgent solution to this math problem. Using first principle derive ex |
Re: Nairaland Mathematics Clinic by NNAMDIII(m): 12:53am On May 21, 2017 |
agentofchange1:Is there any whatsapp group? |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 3:06pm On May 21, 2017 |
NNAMDIII: Yes |
Re: Nairaland Mathematics Clinic by NNAMDIII(m): 3:08pm On May 21, 2017 |
agentofchange1:. |
Re: Nairaland Mathematics Clinic by agentofchange1(m): 10:34am On May 22, 2017 |
NNAMDIII:done |
Re: Nairaland Mathematics Clinic by NNAMDIII(m): 10:35am On May 22, 2017 |
agentofchange1:Thanks! please modify your post......i mean remove my number from your post |
Re: Nairaland Mathematics Clinic by Icosahedron(m): 2:37pm On May 22, 2017 |
Given that sinA + sinB = x and cosA + cosB = y To solve this systems of equations. Sqaure both systems to obtain sin²A + 2sinAsinB sin²B = x² (*) cos²A + 2cosAcosB + cos²B = y² (**) adding we obtain 2 + 2(sinAsinB + cosAcosB) = x² + y² or 2 +2(cos(A-B)) = x² + y² *** cos(A-B) = (x² + y² - 2)/2 Complete the solution thankyoujesus and you shall obtain similar argument for tan(A-B) and use the half-angle identity to obtain the value of tan(A-B)/2 and then proceed to solve the original problem. |
Re: Nairaland Mathematics Clinic by Icosahedron(m): 4:49pm On May 22, 2017 |
Prove that (cosA + cosB)² + (sinA - sinB)² = 4cos²(A+B)/2 |
Re: Nairaland Mathematics Clinic by Icosahedron(m): 12:12am On May 23, 2017 |
Prove also that (1−cot23°)(1−cot22°) = 2 Come on, where are the trigonometry warlords? |
Re: Nairaland Mathematics Clinic by UTILITYMAY(m): 11:31am On May 30, 2017 |
Please I need help for this Quantitative Reasoning questions... Thank you all...
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Re: Nairaland Mathematics Clinic by thankyouJesus(m): 9:55am On Jun 01, 2017 |
Icosahedron: use sin A + sin B = 2sin((A+B)/2) cos((A-B)/2)) = x cosa + cosb = 2cos((a+b)/2) cos((a-b)/2) = y divide x/y = tan((a+b)/2) use knowledge of right angled triangle and Pythagora's to complete it. |
Re: Nairaland Mathematics Clinic by thankyouJesus(m): 9:59am On Jun 01, 2017 |
DrinkWater10:y = e^x dy = e(x+dx) - ex dy = e^x (e^dx - 1) dy/dx = e^x ( e^dx - 1)/ dx take limit as dx approaches zero dy/dx = e^x please pay no attention to wrong use of letter. |
Re: Nairaland Mathematics Clinic by thankyouJesus(m): 10:01am On Jun 01, 2017 |
Icosahedron: I stated the one for cos above. sina - sinb = 2cos((a+b)/2) sin((a-b)/2) continue from here |
Re: Nairaland Mathematics Clinic by holuwajobar(m): 11:02am On Jun 01, 2017 |
Chop this simple math 4^x=8x...... Show workings....am nt interested in ur guess... |
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