The Mathematics Game - Forum Games (7) - Nairaland
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What Is The Answer To This Simple Mathematics? / Can You Solve This Simple Mathematics / Solve This Simple Mathematics If You Can....try It, If You Think You Can (2) (3) (4)
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| Re: The Mathematics Game by Chykason(m): 7:37pm On Feb 22, 2010 |
What is d turning points of d equation Y = 5/3 X + 4 |
| Re: The Mathematics Game by Nobody: 8:30pm On Feb 22, 2010 |
Lol thats a straight line equation has no turning point we are not as dumb as u think! |
| Re: The Mathematics Game by Chykason(m): 8:53pm On Feb 22, 2010 |
Great! We're learnin' Next is a simultaneous equation. SHOW FULL WORKING Solve for X and Y if 2X +14Y =16 7Y + X = 9 |
| Re: The Mathematics Game by lalaboi(m): 8:55pm On Feb 22, 2010 |
Too many olodos mahn |
| Re: The Mathematics Game by lalaboi(m): 9:00pm On Feb 22, 2010 |
Stop wasting peeps time with these stupid equations man. . . |
| Re: The Mathematics Game by Chykason(m): 9:23pm On Feb 22, 2010 |
Chykason: |
| Re: The Mathematics Game by Chykason(m): 9:25pm On Feb 22, 2010 |
Chykason: |
| Re: The Mathematics Game by lalaboi(m): 9:27pm On Feb 22, 2010 |
Why change it? lol |
| Re: The Mathematics Game by lalaboi(m): 9:29pm On Feb 22, 2010 |
Its been answered already. . . . scroll back. . . Is that all you've got?  |
| Re: The Mathematics Game by InesQor(m): 5:19am On Feb 23, 2010 |
The product of two numbers is 1000 times as large as their sum. Give me ANY of the correct answers to this problem. |
| Re: The Mathematics Game by Chykason(m): 6:01am On Feb 23, 2010 |
Let the 2 numbers be ð and þ from the question ðþ=1000(ð+þ) ðþ-1000ð=1000þ ð(þ-1000)=1000þ .:. ð=(1000þ)/(þ-1000) this is what we call the solution space of the question. This spans the solution. Clearly, we have infinitely many solutions because for each value of þ, we'll have a corresponding value of ð. now, we see that þ!=1000(þ not equal to 1000) because ð will be undefined. Infinitely many solutions. One of them is þ=1001, ð=1001000 Q.E.D . . . . NEXT! |
| Re: The Mathematics Game by InesQor(m): 6:27am On Feb 23, 2010 |
@chykason: Guy, a simple answer like 2000, 2000 would have sufficed!  Feeling like a math rockstar, shey?  Ok, let me test your mettle against this HARD math problem: It's my 20th wedding anniversary party, and the youngest child likes me to pose a problem about their ages: ask guests to determine the ages of my three children, given the sum and product of their ages. But since Lalaboi missed the problem tonight and Adolfe bad missed it at the party two years ago, I won't bother telling you the sum and product. I need you to tell me my three children's ages. Cheers. |
| Re: The Mathematics Game by Chykason(m): 7:00am On Feb 23, 2010 |
Insufficient data to execute the problem. Certainly, the 3 children may have been born out of wedlock!. Even, 2 of them may be twins or all triplets! Now assuming they are born after marriage, none of them'll be more than 20 yrs & assuming also 1 child per birth: Let the 1st, 2nd & 3rd sons age be X, Y & Z respectively, then 20=<X<Y<Z. Can't go further! Reason: [size=40pt]insufficient data[/size] |
| Re: The Mathematics Game by InesQor(m): 7:03am On Feb 23, 2010 |
^^^ Don't be a lazy mathematician!! You are right in assuming that they are all younger than 20 years (that is a fundamental assumption, and it's the reason you are told it's a 20th anniversary). I said YOUNGEST child, so obviously they are all different ages; and they are three, so there are no multiple births. What did you do with ALL of this data? The part outlined in green has not been used in your incomplete attempt above. It's my 20th wedding anniversary party, and the youngest child likes me to pose a problem about their ages: ask guests to determine the ages of my three children, given the sum and product of their ages. But since Lalaboi missed the problem tonight and Adolfe bad missed it at the party two years ago, I won't bother telling you the sum and product. I need you to tell me my three children's ages. Cheers. And yet you claim insufficient data?! LOL. Who wants to try? |
| Re: The Mathematics Game by lalaboi(m): 11:23pm On Feb 24, 2010 |
My question is still coming. . .waitn for the gurus to land! |
| Re: The Mathematics Game by KennyG6(m): 11:25pm On Feb 24, 2010 |
gurus are here, fire the question |
| Re: The Mathematics Game by nike4luv(f): 11:26pm On Feb 24, 2010 |
lolage |
| Re: The Mathematics Game by KennyG6(m): 11:27pm On Feb 24, 2010 |
nike4luv:uhn? why r u speaking in welsh? |
| Re: The Mathematics Game by lalaboi(m): 11:28pm On Feb 24, 2010 |
Kenny G, .are u sure? If you lose. . .u get to pay kishi |
| Re: The Mathematics Game by KennyG6(m): 11:30pm On Feb 24, 2010 |
bring it on, by the wat wetin be kishi? |
| Re: The Mathematics Game by lalaboi(m): 11:33pm On Feb 24, 2010 |
3 guyz went to an hotel. . .They booked a triple bedroom apartment for £30 pounds.They all contributed £10 and paid the money but the hotel assistant was instructed by his manager to give them back £5. Instead, he kept £2 for himslef and gave the guyz £1 each . . How much each did the guyz pay? and add that to the one the assistant kept!. . . why is result different from the initial amount paid? Kishi na owo oh. . |
| Re: The Mathematics Game by KennyG6(m): 11:36pm On Feb 24, 2010 |
£9 |
| Re: The Mathematics Game by lalaboi(m): 11:39pm On Feb 24, 2010 |
Edit tot the question. . .check it |
| Re: The Mathematics Game by Chykason(m): 4:50am On Feb 25, 2010 |
This question just tastes lyk tom-tom in ma mouf. . :-P They paid £30, they got £5 change, meaning they actually paid £25, and they contributed £81/3 each  *The question actually confuses if you neglect the £1* |
| Re: The Mathematics Game by Chykason(m): 4:51am On Feb 25, 2010 |
Ok here comes my question . . . ASSUME THAT THERE IS THIS WALL CLOCK THAT HAS STOPPED MOVING. HOW MANY TIMES WOULD IT BE CORRECT IN A DAY? |
| Re: The Mathematics Game by lalaboi(m): 12:02pm On Feb 25, 2010 |
Chykason: Are u blind or what? lol They didnt get £5 back. . . they got £3 back and the assistant pocketed the £2. . . . Afll i want ya to do is sum everything up after the whole transaction Hotel room money + Assistance £2 + How much each they paid(*3) = ?? |
| Re: The Mathematics Game by Obinoscopy(m): 1:24pm On Feb 25, 2010 |
Chykason: It will be correct two times in a day |
| Re: The Mathematics Game by InesQor(m): 2:29pm On Feb 25, 2010 |
Anybody wants to tell me the answer to my question above? |
| Re: The Mathematics Game by Obinoscopy(m): 5:44pm On Feb 26, 2010 |
Your question has no answer |
| Re: The Mathematics Game by Chykason(m): 6:02pm On Feb 26, 2010 |
Obinoscopy:period!!! |
| Re: The Mathematics Game by InesQor(m): 6:05pm On Feb 26, 2010 |
@Obinoscopy and Chykason: You guys did not even make an effort:Okay let me help out a little We look for cases where (1) the oldest child is under 20, (2) the younger two children have different ages, and (3) there is a product and sum that give rise to ambiguity for the ages both this year and two years ago Trust me, this is an advanced math problem. I am just throwing the challenge 'cos I guess this is a group of Math Lovers, right? |
| Re: The Mathematics Game by InesQor(m): 6:15pm On Feb 26, 2010 |
Or maybe I should just post the answer so we can move on. I will not show my calculations here, but you will solve the problem using inequalities, most easily done on graph paper but I calculated by hand. My children's ages are 5 years, 6 years, 16 years. It's the ONLY solution to this complex set of inequalities. Check: I would have told Lalaboi tonight that the product is 480 and the sum is 27 The product of their ages is 480 = 5 * 6 * 16, which was guessed wrongly by Lalaboi as 480 = 4 * 8 * 15 and the sum is 27 = 5 + 6 + 16, which he confirmed (wrongly) as 27 = 4 + 8 + 15 and so Lalaboi announced (wrongly) that their ages were 4, 8, 15 years Two years ago, their ages were 3 years, 4 years, 14 years I would have told Adolfe bad that night that the product is 168 and the sum is 26 Product = 168 = 3 * 4 *14, wrongly guessed by Adolfe Bad as 168 = 2 * 7 * 12 Sum = 26 = 3 + 4 + 14, which he confirmed (wrongly) as 26 = 2 + 7 + 12 and so Adolfe Bad announced (wrongly) that their ages were 2, 7, 12 years Voila. |
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