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Nairaland Forum / Nairaland / General / Education / University Of Ibadan 2015/16 Applicants (1113714 Views)
University Of Ibadan 2015/16 Applicants Call 07037300634 / Federal University Of Petroleum Resources {fupre} 2015/16 Applicants / University Of Ibadan 2014/15 Admission Process.... (2) (3) (4)
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Re: University Of Ibadan 2015/16 Applicants by Pr0ton: 6:30pm On Mar 26, 2015 |
thankyouJesus: Yh Bro! 1 Like |
Re: University Of Ibadan 2015/16 Applicants by Pr0ton: 6:32pm On Mar 26, 2015 |
tolaxin: Cool.. Good for you. |
Re: University Of Ibadan 2015/16 Applicants by Pr0ton: 6:34pm On Mar 26, 2015 |
Re: University Of Ibadan 2015/16 Applicants by thankyouJesus(m): 6:44pm On Mar 26, 2015 |
tolaxin: |
Re: University Of Ibadan 2015/16 Applicants by tolaxin(m): 7:56pm On Mar 26, 2015 |
Vcojuro:if that's the way it is, kindly subtract me from the main group and add me to the science subgroup. My number is 08181984233 and my username is Oba HighBee Obanla.. lemme join Yu guys in smoking some weed |
Re: University Of Ibadan 2015/16 Applicants by tolaxin(m): 7:58pm On Mar 26, 2015 |
Pr0ton:you knw boss,, no origin, weed and the likes.. Such is paradise! |
Re: University Of Ibadan 2015/16 Applicants by Holamarncy: 8:00pm On Mar 26, 2015 |
Pr0ton:jah bless |
Re: University Of Ibadan 2015/16 Applicants by Pr0ton: 8:30pm On Mar 26, 2015 |
tolaxin: 100 Thumb-ups for you Boss. Vcojuro had better provide bags of weed there, else I no go reach there. Ion like paradise. |
Re: University Of Ibadan 2015/16 Applicants by dupre: 9:22pm On Mar 26, 2015 |
thankyouJesus: bros thankgod, terminating d class z nt d best. Wot of pipu dat didnt use whatsapp. Moreover sum1 lyk me z gaining a lot frm ur lectures. Pls i wil plead wit u dat u continue d lecture n God bless u. Amen. |
Re: University Of Ibadan 2015/16 Applicants by Khan1993: 9:44pm On Mar 26, 2015 |
Everybody is just talking of COC, POST UME and ELECTION that no one seem to noticed that the thickness of VIJU MILK has reduced. 3 Likes |
Re: University Of Ibadan 2015/16 Applicants by thankyouJesus(m): 9:48pm On Mar 26, 2015 |
dupre:Amen and you too. I am sorry for any inconveniences, class resume tomorrow by special grace of Jehovah. Good night and sweet dream. |
Re: University Of Ibadan 2015/16 Applicants by Nobody: 10:04pm On Mar 26, 2015 |
Khan1993:lol.......pour some pap into it to make it thick 1 Like |
Re: University Of Ibadan 2015/16 Applicants by Dunsin89(m): 11:12pm On Mar 26, 2015 |
thankyouJesus:. This one that you are putting Jehovah in your post, are you are Jehovah witness? |
Re: University Of Ibadan 2015/16 Applicants by dupre: 12:10am On Mar 27, 2015 |
thankyouJesus: :-), thank u xo much 4 changing ur mind |
Re: University Of Ibadan 2015/16 Applicants by Ayo081(m): 12:42am On Mar 27, 2015 |
Ron9ja:FUTA accept ur Combo For URP |
Re: University Of Ibadan 2015/16 Applicants by thankyouJesus(m): 3:57am On Mar 27, 2015 |
Dunsin89:very funny? I am not. |
Re: University Of Ibadan 2015/16 Applicants by thankyouJesus(m): 3:58am On Mar 27, 2015 |
dupre: |
Re: University Of Ibadan 2015/16 Applicants by thankyouJesus(m): 4:00am On Mar 27, 2015 |
dupre:fixed. All thanks should be unto God, I am just a vessel for His works. |
Re: University Of Ibadan 2015/16 Applicants by Beamborla(f): 7:22am On Mar 27, 2015 |
Ayo081:Where have you been? |
Re: University Of Ibadan 2015/16 Applicants by Ayo081(m): 7:55am On Mar 27, 2015 |
Beamborla: long time frnd, School nah |
Re: University Of Ibadan 2015/16 Applicants by Beamborla(f): 8:01am On Mar 27, 2015 |
Ayo081:All these students self You just went AWOL... not cool. Hope school and everything is going well sha. |
Re: University Of Ibadan 2015/16 Applicants by thankyouJesus(m): 8:04am On Mar 27, 2015 |
[b]Good morning all, it is nice to be here again, how was the night? Let's quickly get down to the business of the day. DIFFERENTIATION OF PRODUCTS OF FUNCTIONS. Let y = uv, where u and v are functions of x. dy/dx = u[dv/dx] + v[du/dx]. To make things easier, let v' = dv/dx u' = du/dx. The new formular is given by: dy/dx = uv' + vu'. Short cut: To differentiate a product of two functions, put down the first (differentiate the second) + put down the second (differentiate the first). . . . . . . . . . . . . . . . . . . . . . . . . Example 1: find y' if y = x3 sinx Solution: y = x3 sinx since x3 and sinx are connected together by "multiplication-product", product rule is being use. y = x3 sinx let u = x3 u' = 3x2 let v = sinx v' = cosx. Therefore, dy/dx = uv' + vu' dy/dx = x3 cosx + sinx 3x2 dy/dx = x3 cosx + 3x2 sinx dy/dx = x2[x cosx + 3 sinx]. Short cut: y = x3 sinx y' = write the first which is x3, differentiate the second [cosx] + write the second which is sinx, differentiate the first [3x2] y' = x3 cosx + sinx 3x2 y' = x2[x cosx + 3 sinx] . . . . . . . . . . . . . . . . . . . . . . . . Example 2: y = x4 cosx, find y' Solution: y = x4 cosx. y' = x4 [-sinx] + cosx [4x3] y' = -x4 sinx + 4x3 cosx y' = 4x3 cosx - x4 sinx. . . . . . . . . . . . . . . . . . . . . . . . . Bonus: (a) y = sinx - cosx (b) y = 2x sinx + sinx cosx + 7. (c) y = (2x + 4)3 sin(3x + 6) Solution: (a) y = sinx - cosx, this question is polynomial, so we differentiate in turn y = sinx - cosx y' = cosx - (-sinx) y' = cosx + sinx. (b) y = 2x sinx + sinx cosx + 7. This question is combination of polynomial and product, therefore y = 2x sinx + sinx cosx + 7. y' = 2x (cosx) + sinx (2) + sinx (-sinx) + cosx (cosx) + 0. y' = 2x cosx + 2 sinx - sin2x + cos2x. (c) y = (2x + 4)3 sin(3x + 6). Very simple, lets go y' = [(2x + 4)3 (3) cos(3x + 6)] + [sin(3x + 6) [(3) (2x + 4)2 (2)]] y' = [3(2x + 4)3 cos(3x + 6)] + [6 (2x + 4)2 sin(3x+6)] . . . . . . . . . . . . . . . . . . . . . . . . Summary: 1. If y = uv, where u and v are functions of x. dy/dx = u[dv/dx] + v[du/dx]. 2. To differentiate a product of two functions, put down the first (differentiate the second) + put down the second (differentiate the first). . . . . . . . . . . . . . . . . . . . . . . . . Assignment: 1. No 39, 1997 d/dx cos (3x2 - 2x) is equal to. . . . 2. No 38, 1998 y = 243 (4x + 5)-2, find dy/dx when x = 1. 3. No 39, 1998 differentiate x wrt (x cosx) 4. No 34, 1999 What is the derivative of t2 sin(3t - 5) 5. No 40, 2000 if y = 2x cos2x - sin2x, find dy/dx when x = pi/4. (Hint pi = 22/7, but trig pi i.e sin(pi), cos(pi) e.t.c pi will assume 180¤ i.e sin(pi) = sin180¤, cos(pi) = cos180¤ e.t.c) 6. No 36, 2001 if y = x sinx, find dy/dx when x = pi/2 7. No 39, 2001 Differentiate (2x + 5)2(x - 4) wrt x 8. No 16, 2002 Find the derivative of y = sin2(5x). (Hint: sin2(5x) = sin(5x) sin(5x)) 9. No 36, 2003 if y = 3 sin(-4x), dy/dx is 10. No 35, 2004 find the derivative of (2 + 3x) (1 - x) wrt x 11. No 36, 2004 find the derivative of the function y = 2x2 (2x - 1) at the point x = -1 12. No 37, 2004 if y = 3 cos(x/3), find dy/dx when x = 3pi/2 (Hint: x/3 = 3-1x) 13. No 37, 2005 find the derivative of y = sin(2x3 + 3x - 4) 14. No 47, 2006 Differentiate (x2 - 1/x)2 wrt x 15. No 1, 2007 if y = (1 + x)2, find dy/dx 16. No 3, 2007 if y = x cosx, find dy/dx 17. No 37, 2008 differentiate sinx - x cosx 18. No 36, 2009 if y = 3 cos4x, dy/dx equals 19. No 37, 2009 if s = (2 + 3t) (5t - 4), find ds/dt when t = 4/5 sec. 20. No 40, 2010 If y = (2x +1)3, find dy/dx 21. No 41, 2010 if y = x sinx, find dy/dx . . . . . . . . . . . . . .. . . . . . . . . . . Any question? . . . . . . . . . . . . . . . . . . . . . . . . Have a splendid day. 27th March, 2015. 08:03:58.[/b] 2 Likes 1 Share |
Re: University Of Ibadan 2015/16 Applicants by ecaaychukwu: 8:34am On Mar 27, 2015 |
bukie26:can a jamb score of 250 get med and surg in UI? |
Re: University Of Ibadan 2015/16 Applicants by Ayo081(m): 9:25am On Mar 27, 2015 |
Beamborla:Huuh tanks ooo |
Re: University Of Ibadan 2015/16 Applicants by Dunsin89(m): 9:29am On Mar 27, 2015 |
ecaaychukwu:The answer to your ''mumu'' oriented question is NO. Go to OAU, Unilorin or Unilag. 1 Like |
Re: University Of Ibadan 2015/16 Applicants by Dunsin89(m): 9:30am On Mar 27, 2015 |
ecaaychukwu:The answer to your ''mumu'' oriented question is NO. Go to OAU, Unilorin or Unilag. #I hate show-off 3 Likes |
Re: University Of Ibadan 2015/16 Applicants by Beamborla(f): 9:41am On Mar 27, 2015 |
Ayo081:You welcome |
Re: University Of Ibadan 2015/16 Applicants by thankyouJesus(m): 10:17am On Mar 27, 2015 |
I was playing with differentiation when a thought hit me concerning quotient rule. I will keep you in the loop during the next class. Things to note: 1. Note the difference between (cosx)-1 and cos-1x, the same for all trig. functions. 2. The quotient rule is dy/dx = [vu' - uv']/ v2. Congratulatory message: If you understood all the previous classes, welcome to the last aspect of basic differentiation (quotient rule). At this juncture (after quotient rule), I promise that differentiation will be a walk in the park. Till next class. |
Re: University Of Ibadan 2015/16 Applicants by dupre: 10:21am On Mar 27, 2015 |
Ayo081: wil u.i accept dis subj combo 4 psychology. Maths, govt, english n econs. |
Re: University Of Ibadan 2015/16 Applicants by Dsurgeon: 10:28am On Mar 27, 2015 |
07069103793. . pls add me.. science group |
Re: University Of Ibadan 2015/16 Applicants by Ayo081(m): 10:34am On Mar 27, 2015 |
dupre:Where is ur bio. I think it should be maths, Eng, bio, gov/econ |
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