thankyouJesus:
DOZEN(S)

Yh Bro!

tolaxin:
myschool.com is kinda real.. Just got my original jamb result slip from them

Cool.. Good for you.

Vcojuro:
u need to be in ui science academic subgroup for academic discussion

Then u will know its not boring

if that's the way it is, kindly subtract me from the main group and add me to the science subgroup. My number is 08181984233 and my username is Oba HighBee Obanla..

lemme join Yu guys in smoking some weed

Pr0ton:


Lol.. I thought as much

you knw boss,, no origin, weed and the likes.. Such is paradise!

Pr0ton:


I called a cafe guy about it, and he told me to call him back on the 1st/2nd of April..


And also, some sites have started doing the COC stuff online for #4, 000. But be careful. Most of them are scammers.


Sure.. Always smoke weed everywhere, everytime.

jah bless

tolaxin:
you knw boss,, no origin, weed and the likes.. Such is paradise!

100 Thumb-ups for you Boss. Vcojuro had better provide bags of weed there, else I no go reach there. Ion like paradise.

thankyouJesus:
It seems everybody is on UI Whats-app messenger, due to that effect, I regret to inform you that "our" class has been terminated, but if you have "any" mathematics questions, do not hesitate to ask and I will do justice to them.

bros thankgod, terminating d class z nt d best. Wot of pipu dat didnt use whatsapp. Moreover sum1 lyk me z gaining a lot frm ur lectures. Pls i wil plead wit u dat u continue d lecture n God bless u. Amen.

Everybody is just talking of COC, POST UME and ELECTION that no one seem to noticed that the thickness of VIJU MILK has reduced.

dupre:


bros thankyouJesus, terminating d class z nt d best. Wot of pipu dat didnt use whatsapp. Moreover sum1 lyk me z gaining a lot frm ur lectures. Pls i wil plead wit u dat u continue d lecture n God bless u. Amen.

Amen and you too. I am sorry for any inconveniences, class resume tomorrow by special grace of Jehovah. Good night and sweet dream.

Khan1993:
Everybody is just talking of COC, POST UME and ELECTION that no one seem to noticed that the thickness of VIJU MILK has reduced.

lol.......pour some pap into it to make it thick

thankyouJesus:
Amen and you too. I am sorry for any inconveniences, class resume tomorrow by special grace of Jehovah. Good night and sweet dream.

. This one that you are putting Jehovah in your post, are you are Jehovah witness?

thankyouJesus:
Amen and you too. I am sorry for any inconveniences, class resume tomorrow by special grace of Jehovah. Good night and sweet dream.

:-), thank u xo much 4 changing ur mind

Ron9ja:
Pls Help What Course Can I Do Wit This,jamb Combo-eng,math,geo,econ & Olevel Eng,math,chem,phy,bio,econ,geo,yor,agric,wich Has 1b 6c Or Do Ui Offer Urban & Regional Planny

FUTA accept ur Combo For URP

Dunsin89:
. This one that you are putting Jehovah in your post, are you a member of Jehovah witness denomination?

very funny? I am not.

dupre:


:-), thank God xo much 4 changing ur mind

fixed.
All thanks should be unto God, I am just a vessel for His works.

Ayo081:

FUTA accept ur Combo For URP

Where have you been?

Beamborla:

Where have you been?

long time frnd, School nah

Ayo081:

long time frnd, School nah

All these students self

You just went AWOL... not cool.
Hope school and everything is going well sha.

[b]Good morning all, it is nice to be here again, how was the night?
Let's quickly get down to the business of the day.
DIFFERENTIATION OF PRODUCTS OF FUNCTIONS.
Let y = uv,
where u and v are functions of x.
dy/dx = u[dv/dx] + v[du/dx].
To make things easier, let
v' = dv/dx
u' = du/dx.
The new formular is given by:
dy/dx = uv' + vu'.
Short cut:
To differentiate a product of two functions,
put down the first (differentiate the second) + put down the second (differentiate the first).
. . . . . . . . . . . . . . . . . . . . . . . .
Example 1: find y' if y = x³ sinx
Solution:
y = x³ sinx
since x³ and sinx are connected together by "multiplication-product", product rule is being use.
y = x³ sinx
let u = x³
u' = 3x²
let v = sinx
v' = cosx.
Therefore,
dy/dx = uv' + vu'
dy/dx = x³ cosx + sinx 3x²
dy/dx = x³ cosx + 3x² sinx
dy/dx = x²[x cosx + 3 sinx].
Short cut:
y = x³ sinx
y' = write the first which is x³, differentiate the second [cosx] + write the second which is sinx, differentiate the first [3x²]
y' = x³ cosx + sinx 3x²
y' = x²[x cosx + 3 sinx]
. . . . . . . . . . . . . . . . . . . . . . . .
Example 2: y = x⁴ cosx, find y'
Solution:
y = x⁴ cosx.
y' = x⁴ [-sinx] + cosx [4x³]
y' = -x⁴ sinx + 4x³ cosx
y' = 4x³ cosx - x⁴ sinx.
. . . . . . . . . . . . . . . . . . . . . . . .
Bonus:
(a) y = sinx - cosx
(b) y = 2x sinx + sinx cosx + 7.
(c) y = (2x + 4)³ sin(3x + 6)
Solution:
(a) y = sinx - cosx,
this question is polynomial, so we differentiate in turn
y = sinx - cosx
y' = cosx - (-sinx)
y' = cosx + sinx.
(b) y = 2x sinx + sinx cosx + 7.
This question is combination of polynomial and product, therefore
y = 2x sinx + sinx cosx + 7.
y' = 2x (cosx) + sinx (2) + sinx (-sinx) + cosx (cosx) + 0.
y' = 2x cosx + 2 sinx - sin²x + cos²x.
(c) y = (2x + 4)³ sin(3x + 6).
Very simple, lets go
y' = [(2x + 4)³ (3) cos(3x + 6)] + [sin(3x + 6) [(3) (2x + 4)² (2)]]
y' = [3(2x + 4)³ cos(3x + 6)] + [6 (2x + 4)² sin(3x+6)]
. . . . . . . . . . . . . . . . . . . . . . . .
Summary:
1. If y = uv,
where u and v are functions of x.
dy/dx = u[dv/dx] + v[du/dx].
2. To differentiate a product of two functions,
put down the first (differentiate the second) + put down the second (differentiate the first).
. . . . . . . . . . . . . . . . . . . . . . . .
Assignment:
1. No 39, 1997
d/dx cos (3x² - 2x) is equal to. . . .
2. No 38, 1998
y = 243 (4x + 5)^-2, find dy/dx when x = 1.
3. No 39, 1998
differentiate x wrt (x cosx)
4. No 34, 1999
What is the derivative of t² sin(3t - 5)
5. No 40, 2000
if y = 2x cos2x - sin2x, find dy/dx when x = pi/4.
(Hint pi = 22/7, but trig pi i.e sin(pi), cos(pi) e.t.c pi will assume 180¤ i.e sin(pi) = sin180¤, cos(pi) = cos180¤ e.t.c)
6. No 36, 2001
if y = x sinx, find dy/dx when x = pi/2
7. No 39, 2001
Differentiate (2x + 5)²(x - 4) wrt x
8. No 16, 2002
Find the derivative of y = sin²(5x).
(Hint: sin²(5x) = sin(5x) sin(5x))
9. No 36, 2003
if y = 3 sin(-4x), dy/dx is
10. No 35, 2004
find the derivative of (2 + 3x) (1 - x) wrt x
11. No 36, 2004
find the derivative of the function y = 2x² (2x - 1) at the point x = -1
12. No 37, 2004
if y = 3 cos(x/3), find dy/dx when x = 3pi/2
(Hint: x/3 = 3^-1x)
13. No 37, 2005
find the derivative of y = sin(2x³ + 3x - 4)
14. No 47, 2006
Differentiate (x² - 1/x)² wrt x
15. No 1, 2007
if y = (1 + x)², find dy/dx
16. No 3, 2007
if y = x cosx, find dy/dx
17. No 37, 2008
differentiate sinx - x cosx
18. No 36, 2009
if y = 3 cos4x, dy/dx equals
19. No 37, 2009
if s = (2 + 3t) (5t - 4), find ds/dt when t = 4/5 sec.
20. No 40, 2010
If y = (2x +1)³, find dy/dx
21. No 41, 2010
if y = x sinx, find dy/dx
. . . . . . . . . . . . . .. . . . . . . . . . .

. . . . . . . . . . . . . . . . . . . . . . . .
Have a splendid day.
27th March, 2015.
08:03:58.[/b]

bukie26:
I'm debby and m comin in for medicine and surgery

can a jamb score of 250 get med and surg in UI?

Beamborla:

All these students self

You just went AWOL... not cool.
Hope school and everything is going well sha.

Huuh
tanks ooo

ecaaychukwu:
can a jamb score of 250 get med and surg in UI?

The answer to your ''mumu'' oriented question is NO. Go to OAU, Unilorin or Unilag.

ecaaychukwu:
can a jamb score of 250 get med and surg in UI?

The answer to your ''mumu'' oriented question is NO. Go to OAU, Unilorin or Unilag. #I hate show-off

Ayo081:

Huuh
tanks ooo

You welcome

Ayo081:

FUTA accept ur Combo For URP

wil u.i accept dis subj combo 4 psychology. Maths, govt, english n econs.

07069103793. . pls add me.. science group

dupre:


wil u.i accept dis subj combo 4 psychology. Maths, govt, english n econs.

Where is ur bio.
I think it should be maths, Eng, bio, gov/econ