Oops... didn't went through the 1st page, there are tutors for this... hope I won't be banned for this? I'm really sorry generals.
cc Dejt4u
raayah
logoDwhiz
goofyone.

factorial1:
Oops... didn't went through the 1st page, there are tutors for this... hope I won't be banned for this? I'm really sorry generals.
cc Dejt4u
raayah
logoDwhiz
goofyone.

you're highly welcome here please.

Feel free.

factorial1:

Alright... here is the solution:
Note: π represent lambda.
Q = π(√2gh/r² - 1)
Now, squaring both sides to remove the square root in the R.H.S...
The question becomes Q² = π²(2gh/r² - 1)
Then... cross multiply to have (r² - 1)Q² = π²2gh
Opening the bracket... the eqn becomes Q²r² - Q² = π²2gh... Now, making Q²r² the subject of the formula.. then we have Q²r² = π²2gh + Q². Since we are to make "r" the subject of the formula and not Q²r²... we then firstly divide both sides by Q²... making the eqn to be r² = (π²2gh + Q²)/Q²... which is also r² = π²2gh/Q² + Q²/Q² and it implies r² = π²2gh/Q² + 1. Now... to get "r"... we then find the square root of both sides... which is √r² = √(π²2gh/Q² + 1) and finally r = √(π²2gh/Q² + 1).

U Guyz Ar So Good...Fankz Bro

LogoDWhiz:


you're highly welcome here please.

Feel free.

Alright...

VEVEDIHNO:

U Guyz Ar So Good...Fankz Bro

you welcome bro...

We need more question

Profit[b][/b] And[b][/b] Loss[b][/b]
profit&loss is all about finding the gain or loss made from selling a particular product/products..as we know it is SALES PRICE-BOUGHT PRICE determines whether profit or loss.so without wasting much time,all questions relating the topic should be posted&i will take care of it&anybody with different&faster solutions are also free to post thier solutions
Am going to give a quick solution based on discount,,
Discount is all about special money taken off a product bought..this is done usally in festive periods like Ramadan,Christmas,etc..we all know this,so without wasting any time,am going to give a quick soln concerning Discount
1)When you are asked to find the percentage paid on discount,this particular question takes a lot of time&requires you to find a lot before finding it but i will show you how to find it in less than 15secs.you can apply this in waec,neco and other exams that requires you to find such.infact it was in this years waec..Waec students can apply this formular in their rough work in theory as it makes the student to know the final ans before detailed solution
Example[b][/b]
1). A shop-keeper marks his television set for sale at #36000 so as to make a profit of 20% on the cost price.When he sells it,he allows a discount of 5% off the marked price.Calculate percentage profit?
to ans the above questions you are required to find a lot especially profit but using my MAGIC formular,you can know the percentage easily.so
i)ratio of marked price to cost price=(100+20):100
ii)ratio of Cash price to Marked price=(100-5):100[cos is a discount of 5%,the consumer will pay 95%]
Cash price=95% of marked price
marked price=120% of cost price
therefore the cash price=95/100x120/100 of the cost price

so to apply the above formular just do this
1).100+inital percentage=100+20=120
2).100-ddiscount=100-5=95
3).120x95/100=114
just minus this price to the cost price ratio which is 100{114-100}=14%
the ans is 14%..this should take less than 10secs if possible[note-i only worked with the percentage figure&i didnt use the amount that is #36000]
for a detailed soln
1).Gain%=actual gain/cost price x 100
0.2=36000-y/y[note-20/100=0.2]
0.2y=36000-y
1.2y=36000
y=36000/1.2
y=#30000
discount=5% of #36000
=5/100 x 36000=#1800
New selling price=#(36000-1800)=#34200
gain=#(34200-30000)=#4200
gain%=4200/30000 x 100=14%
same ans..so for jambites,this process is not needed..waec students can use my formular to get the correct ans before giving detail solutions..HOPE THIS HELPS..feel free to ask any question

4 differentiation, calculus etc visit http://schoolinland.com

GeneralShepherd:
I am willing to teach any topic on mathematics here.

I don't mind taking out 30mins everyday from my busy schedule to coach the future engineers and scientists that will move Nigeria to where we need to be.

Quote anytime, with a question and I will reply.

Thanks.
GeneralShepherd. B.eng,M.sc

pls help with this.......In a fund-raising lottery,42% of the money collected is given as cash prizes. there are eight cash prizes altogether . the first prize winner gets #3500, the second gets #3100, the third #2700, and so on in arithmetic progression.
a. How much money does the eight get?
b. How much price money is there all together?
c. How much money is raised for fund?

lizzlix:

pls help with this.......In a fund-raising lottery,42% of the money collected is given as cash prizes. there are eight cash prizes altogether . the first prize winner gets #3500, the second gets #3100, the third #2700, and so on in arithmetic progression.
a. How much money does the eight get?
b. How much price money is there all together?
c. How much money is raised for fund?

I
A. The eight person gets a + 7d

Where a is the first term and D is the arithmetic difference between successive terms.

D = 3100 - 3500 = - 400

Note that it is negative because the numbers are decreasing.

Hence Term 8 = 3500 - 2800 = 700

I'll solve C before B

C. Is sum of the a.P, Sn=N/2(a+l)

Where n is number of terms which is 8
A is the first term 3500 and l is last term is 700.

Sn= 8/2(3500+700) =
4(4200) = 16800.

B. If 42% of total money is
16800

0.42X =16800
X =16800/0.42 = 40000


I hope this helps

GeneralShepherd:

I
A. The eight person gets a + 7d

Where a is the first term and D is the arithmetic difference between successive terms.

D = 3100 - 3500 = - 400

Note that it is negative because the numbers are decreasing.

Hence Term 8 = 3500 - 2800 = 700

I'll solve C before B

C. Is sum of the a.P, Sn=N/2(a+l)

Where n is number of terms which is 8
A is the first term 3500 and l is last term is 700.

Sn= 8/2(3500+700) =
4(4200) = 16800.

B. If 42% of total money is
16800

0.42X =16800
X =16800/0.42 = 40000


I hope this helps

Well, I think money raised for the fund = #(40000 - 16800) = #23200.
From the total money ganerned from the lottery, part (#16800) was raised as fund while the reminants was raised as funds.
Tnks.

Well, I think money raised for the fund = #(40000 - 16800) = #23200.
From the total money ganerned from the lottery, part (#16800) was used as prizes while the reminants were raised as funds.
Tnks.

sorbentcrooner:


Well, I think money raised for the fund = #(40000 - 16800) = #23200.
From the total money ganerned from the lottery, part (#16800) was raised as fund while the reminants was raised as funds.
Tnks.

Well, I think money raised for the fund = #(40000 - 16800) = #23200.
From the total money ganerned from the lottery, part (#16800) was used as prizes while the reminants were raised as funds.
Tnks.

Very true, I failed that bit. Thanks

GeneralShepherd:


Very true, I failed that bit. Thanks

Aii - u welcome.

Finally the secrets on how to write and pass jamb computer based test CBT in flying colours is out and you don't wanna miss this....
Visit www..scholactive. for more details.....share among your family and friends that can benefit from the goodnews

Someshuld tackle diz Questions for me


(1) 4x-3=3x+y=2y+5x-12


(2) The Ages Of Tosan and Isa Differ by 6 and the product of their ages is 187.Find Their Ages.

Tanks In Advance.

VEVEDIHNO:
Someshuld tackle diz Questions for me


(1) 4x-3=3x+y=2y+5x-12


(2) The Ages Of Tosan and Isa Differ by 6 and the product of their ages is 187.Find Their Ages.

Tanks In Advance.

Question 1. I dont know if its the right way to work it but here's what I did.

Divide it into two parts

4x-3=3x+y--------- eq 1

and 3x+y=2y + 5x-12.--------eq 2

rearranging eq 1

4x-3x-y=3

x-y=3---------eq 3

rearranging eq 2

3x-5x+y-2y=-12

-2x -y =-12--------eq 4

solving eq 3 and 4 simultaneously

x-y=3
-2x-y=-12

from eq 3, we can see x= 3+y, putting this back in eq 4

-2(3+y)-y=-12
-6-2y-y=-12
-6-3y=-12
-3y=-12+6
-3y=-6
y=2

and from x=3+y
x=3+2
x=5

x=5 and y=2
check:

4x-3= 4(5)-3=20-3=17

3x+y=3(5)+2= 15+2=17

2y+5x-12=2(2)+5(5)-12
=4+25-12
=29-12
=17.

There might be a shorter option but here's my method.

VEVEDIHNO:
Someshuld tackle diz Questions for me


(1) 4x-3=3x+y=2y+5x-12


(2) The Ages Of Tosan and Isa Differ by 6 and the product of their ages is 187.Find Their Ages.

Tanks In Advance.

Question 2

Let Tosan age be x and Isa age be y..

from the question x-y=6------------- eq 1
and xy=187-------eq 2

x=6+y from equation 1

substituting into eq 2

(6+y)y=187

6y+y^2=187
rearranging
y^2+6y-187=0

The only two numbers that can be added or subtracted and gives 6 and can also be multiplied to give -187 are minus 11 and 17.
To get these numbers a bit of thinking might be involved!!
back to solution

y^2+6y-187=0
y^2+17y-11y-187=0

factorizing
y(y+17)-11(y+17)=0

so (y-11) =0 or y+17=0

so y=-17 or y=11.

Since y cannot be negative, age cannot be negative, y=11. Therefore Isa is 11 years.

to get Tosan age we know that x-y=6

x-11=6

x=11+6

x=17.

Therefore Tosan is 17 years.

raayah:


Question 2

Let Tosan age be x and Isa age be y..

from the question x-y=6------------- eq 1
and xy=187-------eq 2

x=6+y from equation 1

substituting into eq 2

(6+y)y=187

6y+y^2=187
rearranging
y^2+6y-187=0

The only two numbers that can be added or subtracted and gives 6 and can also be multiplied to give -187 are -11 and 17.
To get these numbers a bit of thinking might be involved!!
back to solution

y^2+6y-187=0
y^2+17y-11y-187=0

factorizing
y(y+17)-11(y+17)=0

so (y-11) =0 or y+17=0

so y=-17 or y=11.

Since y cannot be negative, age cannot be negative, y=11. Therefore Isa is 11 years.

to get Tosan age we know that x-y=6

x-11=6

x=11+6

x=17.

Therefore Tosan is 17 years.

U right guy

raayah:


Question 2

Let Tosan age be x and Isa age be y..

from the question x-y=6------------- eq 1
and xy=187-------eq 2

x=6+y from equation 1

substituting into eq 2

(6+y)y=187

6y+y^2=187
rearranging
y^2+6y-187=0

The only two numbers that can be added or subtracted and gives 6 and can also be multiplied to give -187 are minus 11 and 17.
To get these numbers a bit of thinking might be involved!!
back to solution

y^2+6y-187=0
y^2+17y-11y-187=0

factorizing
y(y+17)-11(y+17)=0

so (y-11) =0 or y+17=0

so y=-17 or y=11.

Since y cannot be negative, age cannot be negative, y=11. Therefore Isa is 11 years.

to get Tosan age we know that x-y=6

x-11=6

x=11+6

x=17.

Therefore Tosan is 17 years.

fankz bro

raayah:


Question 2

Let Tosan age be x and Isa age be y..

from the question x-y=6------------- eq 1
and xy=187-------eq 2

For anyone who gets a question like this in JAMB (and it does seem like a very likely JAMB question), it would help you a lot not to bother with all the calculations. Don't get me wrong! The calculation is cool and good to know. But in a situation where you need to be time-conscious, like in JAMB, you need all the awareness you can get.

If the options is comprised of just integers, then it would help if you knew that the number 187 is not divisible by any other numbers except 11 & 17. Those are the only two numbers that can multiply to give you 187. Both are primes and 187 is a product of those two primes.

If you knew that, you are well on your way to the answer to this question.

goofyone:


For anyone who gets a question like this in JAMB (and it does seem like a very likely JAMB question), it would help you a lot not to bother with all the calculations. Don't get me wrong! The calculation is cool and good to know. But in a situation where you need to be time-conscious, like in JAMB, you need all the awareness you can get.

If the options is comprised of just integers, then it would help if you knew that the number 187 is not divisible by any other numbers except 11 & 17. Those are the only two numbers that can multiply to give you 187. Both are primes and 187 is a product of those two primes.

If you knew that, you are well on your way to the answer to this question.

These questions did not come with options.I had to solve it the long way. You can tell the people posting questions to add the options in the questions also. Of course, it would seem easier to plug in the variables and work your way back. But w/o options given, what was I supposed to do. Hopefully, someone learned something from my calculations and you don't have to be so rude.

raayah:


These questions did not come with options.I had to solve it the long way. You can tell the people posting questions to add the options in the questions also. Of course, it would seem easier to plug in the variables and work your way back. But w/o options given, what was I supposed to do. Hopefully, someone learned something from my calculations and you don't have to be so rude.

Hey, come on! I understand. Not trying in any way to say you didn't or haven't done a good job. Easy now.
Just offering another insight into a solution.
Thanks anyways. And sorry if I came off as rude.

goofyone:


Hey, come on! I understand. Not trying in any way to say you didn't or haven't done a good job. Easy now.
Just offering another insight into a solution.
Thanks anyways. And sorry if I came off as rude.

guy abeg where you go..youve kept me in the dark..pls post questions and faster answers..thanks in advance

Y = tan x-x.
Find dy/dx. Anyone who can try ASAP.

Dacronym:
Y = tan x-x.
Find dy/dx. Anyone who can try ASAP.

y = tan x - x

dy/dx = Sec^2x - 1.
because ;
Differentiating tan x gives sec square x and differentiating x gives 1.

2muchopoTBdope:

y = tan x - x

dy/dx = Sec^2x - 1.
because ;
Differentiating tan x gives sec square x and differentiating x gives 1.

maybe you should explain how the derivative of tanx is sec²x.

factorial1:
maybe you should explain how the derivative of tanx is sec²x.

tan x = (sin x)/(cos x),
d/dx (tan x) = ?
Using quotient rule,
dy/dx = (vdu/dx - udv/dx) / v²,
.
.
.
fill in the spaces, then derivative of tan x = sec²x

dejt4u:


tan x = (sin x)/(cos x),
d/dx (tan x) = ?
Using quotient rule,
dy/dx = (vdu/dx - udv/dx) / v²,
.
.
.
fill in the spaces, then derivative of tan x = sec²x

not that I didn't know it... I just want him to give full explanation... As a matter of fact, I'm not the one that asked the question. The thing is... it would be more better for anyone that would be answering questions here to be giving the full solution, so that the aim of this thread can be achieved.

factorial1:
not that I didn't know it... I just want him to give full explanation... As a matter of fact, I'm not the one that asked the question. The thing is... it would be more better for anyone that would be answering questions here to be giving the full solution, so that the aim of this thread can be achieved.

bros bros.. I wont underate you now.. I know you and i knw your ability..

I only did that for the jambites here!

dejt4u:

bros bros.. I wont underate you now.. I know you and i knw your ability..

I only did that for the jambites here!

Lol.. oga mi, I get that jare... just to let the "question solvers" know ni.

factorial1:
maybe you should explain how the derivative of tanx is sec²x.

Aite,I will.
Tan x = Sin x/Cos x
Using quotient rule
d(u/v)/dx = (Vdu/dx - udv/dx)/v^2
In this case, u = sin x and v = cos x
du/dx = cos x and dv/dx = -sin x
then using the quotient rule above
we have; [cos x(cos x) - sin x(-sin x)]/(cos x)^2
>>>>>> [cos^2 x + sin^2 x]/ cos^2 x......equation1
From elementary trigonometry,we all know that
cos^2 x + sin^2 x = 1
from equation 1,we then ve
>>>>>>. 1/cos^2 x = sec^2 x
cos we all know that sec x = 1/cos x.
So this is hw the derivative of tan x gives sec^2 x.

any unilorin aspirant click dis link nd ask any information concerning unilorin admission processing... wish u success https://www.nairaland.com/2043020/unilorin-utme-2015-2016-aspirants#28851553

GeneralShepherd:

I
A. The eight person gets a + 7d

Where a is the first term and D is the arithmetic difference between successive terms.

D = 3100 - 3500 = - 400

Note that it is negative because the numbers are decreasing.

Hence Term 8 = 3500 - 2800 = 700

I'll solve C before B

C. Is sum of the a.P, Sn=N/2(a+l)

Where n is number of terms which is 8
A is the first term 3500 and l is last term is 700.

Sn= 8/2(3500+700) =
4(4200) = 16800.

B. If 42% of total money is
16800

0.42X =16800
X =16800/0.42 = 40000


I hope this helps

Yeah, a lot ....thanks big time . I will drop more.