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Re: Any Mathematician In The House...try Solving This Trick Question. by Legacy44(f): 2:51pm On Jan 30, 2015
PuntGenius:
I got a=0, b=0 and c=0 from my workings, but 3, 4 and 5 or 6, 4 and 8vare also correct but I can't seem to work that out

thats d deal...i need the workings.
Re: Any Mathematician In The House...try Solving This Trick Question. by Nobody: 3:04pm On Jan 30, 2015
Legacy44:


yeah...i need further explanation. I understand the following deductions:
a/c=3/5, c/b=5/4, a/b=3/4.

But how did the above translate to
a=3, b=4, c=5
because it seems like u jus guessed what should have been there...olusolaj also apparently got it 'right' cos it fitted perfectly to the question. His answer was a=1, b=4/3, C=5/3.

I can also say a=3/2, b=2, c=5/2 AND THE ANSWER WILL BE JUSTIFIABLE....it still doesn't make it right.

Pls clear workings will justify ur answer not assumptions
does answer u?

Re: Any Mathematician In The House...try Solving This Trick Question. by Nobody: 3:11pm On Jan 30, 2015
Legacy44:


yeah...i need further explanation. I understand the following deductions:
a/c=3/5, c/b=5/4, a/b=3/4.

But how did the above translate to
a=3, b=4, c=5
because it seems like u jus guessed what should have been there...olusolaj also apparently got it 'right' cos it fitted perfectly to the question. His answer was a=1, b=4/3, C=5/3.

I can also say a=3/2, b=2, c=5/2 AND THE ANSWER WILL BE JUSTIFIABLE....it still doesn't make it right.

Pls clear workings will justify ur answer not assumptions
here is the vertical view.

Re: Any Mathematician In The House...try Solving This Trick Question. by Nobody: 2:58pm On Jan 31, 2015
Legacy44, you don abandone your thread ni? if you are not satisfied, I bet you could show us your own working. we could learn from you cos I know you have an answer... to this problem. Keep up the good work.
Re: Any Mathematician In The House...try Solving This Trick Question. by PuntGenius: 9:32am On Feb 01, 2015
My final solution, note that the second solution might not be completely correct in all aspect because 0/0 =infinity

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Re: Any Mathematician In The House...try Solving This Trick Question. by fio(m): 4:14pm On Feb 04, 2015
AdeniyiA:
check d workings in d pix posted ...
a=3, b= 4, c=5

That is brilliant!!!!
Re: Any Mathematician In The House...try Solving This Trick Question. by fio(m): 4:17pm On Feb 04, 2015
PuntGenius:
My final solution, note that the second solution might not be completely correct in all aspect because 0/0 =infinity

I get it, very clever of u?
Re: Any Mathematician In The House...try Solving This Trick Question. by Nobody: 3:48pm On Apr 06, 2015
Legacy44:


thats d deal...i need the workings.

I atleast sent you a PM.

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