No,I haven't.
Though am not in Lagos.

Geofavor:
Guys, there are some putme past questions being sold here in Lagos. I was surprised when I saw the advert in front of a bookshop.

In each book, they combined past questions from two schools: Part 1 for one school and part 2 for the other school.

Delsu and uniben were put together in the same book. The questions are up to date: 2005 - 2015. The 2015 exams which were computer based -- their questions are put in disks and attached to the books.

Answers are provided, however, they didn't show their workings.

The book goes for ₦1,500.


Has anyone else seen it?

Damscrob:
Hello guys.. Hope y'all are fine.... I have been quite busy this days because of my IT.... But I am glad it's going well.... I remain your one and only Hon. Damscrob Repping 400L chemical engineering, UNIBEN..... for those that have questions as regards UNIBEN admission should message me on whatsapp:08104459028...wish y'all d very best this year... And Happy Sunday!

#Damscrob

Ok, ekabor sir

IamLukas:
No,I haven't. Though am not in Lagos.

all right. Which one are you using?

Quintessence! Though not the current.

Geofavor:
all right. Which one are you using?

IamLukas:
Quintessence!
Though not the current.

okay. This quintessence seems to be the best so far. The spoiler in it is that it doesn't have 2015 questions included.

You guys said the exam should be by either late may or very early june, right? That should be roughly a month from now.

I guess it's time to quit everyother thing and focus solely on preparing for this test.

Geofavor:
okay. This quintessence seems to be the best so far. The spoiler in it is that it doesn't have 2015 questions included.

You guys said the exam should be by either late may or very early june, right? That should be roughly a month from now.

I guess it's time to quit everyother thing and focus solely on preparing for this test.

bro am also a uniben aspirant... how the jacking they go na??
Cuz nowadays .. I sleep on top my books

Do these if you can,

(1) Solve 8x = 4^x

2) A body which is uniformly retarded comes to rest in 10s after travelling a distance of 20m. Calculate its initial velocity.

3) calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30m/s

4) zinc cannot be displaced by copper from zinc tetraoxosulphate(vi) because
a) zinc is Less reactive b) copper is more reactive c) zinc is above copper in the activity series d) copper is above zinc in the activity series

jaymejate:

Ok, ekabor sir

Lol how u dey na.... Men GUYZ be hustling hard coz of IT

Damscrob:

Lol how u dey na.... Men GUYZ be hustling hard coz of IT

Im fine bro, hope you're getting paid for where you de do IT?

CaptainECole:
bro am also a uniben aspirant... how the jacking they go na??
Cuz nowadays .. I sleep on top my books

Kikiki
Bro, if i tok say mak una de read with determination, d rate you go de sleep go increase.
1... Just take black coffee (i love the movie) .
2... Maybe 4 your area, u never see pesin wey no old reach u dat is in uni. If you have seen them, no1 will tell u 2 Jack.
U better enter uni and not poly.

jaymejate:

Kikiki
Bro, if i tok say mak una de read with determination, d rate you go de sleep go increase.
1... Just take black coffee (i love the movie) .
2... Maybe 4 your area, u never see pesin wey no old reach u dat is in uni. If you have seen them, no1 will tell u 2 Jack.
U better enter uni and not poly.

abi ooo.. thanks for the tip.. I'll surely get some coffee .. and I'll put in more effects ..

CaptainECole:
bro am also a uniben aspirant... how the jacking they go na??
Cuz nowadays .. I sleep on top my books

I'm just going into preparation fulltime. What course are you aspiring to get?

Geofavor:
Do these if you can,

(1) Solve 8x = 4^x

2) A body which is uniformly retarded comes to rest in 10s after travelling a distance of 20m. Calculate its initial velocity.

3) calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30m/s

4) zinc cannot be displaced by copper from zinc tetraoxosulphate(vi) because
a) zinc is Less reactive b) copper is more reactive c) zinc is above copper in the activity series d) copper is above zinc in the activity series

so, nobody here can attempt these?

Geofavor:
I'm just going into preparation fulltime. What course are you aspiring to get?

chemical engineering .. and you?

CaptainECole:
chemical engineering .. and you?

Mmm, nice course. I'm going for Geology.

This means we're going to the same faculty -- Engineering and physical sciences. Hope you know your subject combo?

Lalasticlala, abeg help the life of this thread.

Geofavor:
Mmm, nice course. I'm going for Geology.

This means we're going to the same faculty -- Engineering and physical sciences. Hope you know your subject combo?

hehe
. sure man,this is my second try at uniben .. so I'm kinda familiar with everything

CaptainECole:
hehe
. sure man,this is my second try at uniben .. so I'm kinda familiar with everything

Oh, I see. So, how far have you gone with your preparations?

Geofavor:
Do these if you can,

(1) Solve 8x = 4^x

2) A body which is uniformly retarded comes to rest in 10s after travelling a distance of 20m. Calculate its initial velocity.

3) calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30m/s

4) zinc cannot be displaced by copper from zinc tetraoxosulphate(vi) because
a) zinc is Less reactive b) copper is more reactive c) zinc is above copper in the activity series d) copper is above zinc in the activity series

1)
divide both sides by 4
2x=x
2x-x=0
x=0 (im nt so sure)
2)
u= ?
v=0
t= 10sec
s= 20m.
recall
s=(u+v/2)t
20=(u+0/2)10
20=5u
u=4ms
3)
u=0
s=?
v=30ms
recall
vsquared= usquared+2as
30squared= 0+2x10xs
900=20s
s=45m

4)c

Geofavor:
Oh, I see. So, how far have you gone with your preparations?

lets just say 50%.. am about to up my game.. put in more effort, I don't wanna give myself an excuse for failure

jaymejate:
Im fine bro, hope you're getting paid for where you de do IT?

Na change o. But we managing it....

CaptainECole:
lets just say 50%.. am about to up my game.. put in more effort, I don't wanna give myself an excuse for failure

confirm.

Kphantom, well done. You got all but 1)

HurricaneMIMZY:

A good evening to you all.


May God grant your admission wishes.


As you await the envisaged good news (which would surely come), remember to vote Mimzy.




VoteMimzyAsMissNairaland2016

So, how much does she get if she wins? Chai Nigerians.

Geofavor:
confirm.

Kphantom, well done. You got all but 1)

aiit, pls put the solution to 1... Btw, did u still buy the past question in lag? and hw sure r u that the 2015 that is on a diskette is truly it.. I mean, hw did they get it since it was cbt?

Geofavor:
so, nobody here can attempt these?

We can

Geofavor:
Do these if you can,

(1) Solve 8x = 4^x

2) A body which is uniformly retarded comes to rest in 10s after travelling a distance of 20m. Calculate its initial velocity.

3) calculate the height from which a body is released from rest if its velocity just before hitting the ground is 30m/s

4) zinc cannot be displaced by copper from zinc tetraoxosulphate(vi) because
a) zinc is Less reactive b) copper is more reactive c) zinc is above copper in the activity series d) copper is above zinc in the activity series

Good job you're doing. This is what is needed here.

Geofavor:
confirm.

Kphantom, well done. You got all but 1)

Since he got all but number one, I'll attempt only number one then.
There are more than a billion ways to solve that very question.
Here's one of them

4 ^x = 8X

Apply log to both sides

Log4 ^x = Log(8X)

Log4 ^x = Log8 + LogX

Log2 ^2x = Log2 ³ + LogX

Applying the laws of indices, we have

2XLog2 = 3Log2 + LogX

2XLog2 - 3Log2 = LogX

Log2(2X - 3) = LogX

Eliminating Log from both sides

2(2X - 3) = X

4X - 6 = X

4X - X = 6

3X = 6

X = 6/3

X=2

UnibenPilot:

Since he got all but number one, I'll attempt only number one then.
There are more than a billion ways to solve that very question.
Here's one of them

4 ^x = 8X

Apply log to both sides

Log4 ^x = Log(8X)

Log4 ^x = Log8 + LogX

Log2 ^2x = Log2 ³ + LogX

Applying the laws of indices, we have

2XLog2 = 3Log2 + LogX

2XLog2 - 3Log2 = LogX

Log2(2X - 3) = LogX

Eliminating Log from both sides

2(2X - 3) = X

4X - 6 = X

4X - X = 6

3X = 6

X = 6/3

X=2

chai, that awkward moment after a test when ur frnds r arguing whether the answer was 2 or 3 but what u got was 0.. lol. nice one.. #i regret nt taking maths serious in secondary skul.

KPhantom:

aiit, pls put the solution to 1...

unibenpilot has done justice to it.

Btw, did u still buy the past question in lag? and hw sure r u that the 2015 that is on a diskette is truly it.. I mean, hw did they get it since it was cbt?

I haven't bought it yet. I should get it before this week runs out.

Talking about how they got the 2015 questions, I think it's possible. Jamb 2015 was also computer based, yet they got the questions out to sell.

please, someone should post uniben past question answer. please i need it badly please.

UnibenPilot:

Since he got all but number one, I'll attempt only number one then.
There are more than a billion ways to solve that very question.
Here's one of them

4 ^x = 8X

Apply log to both sides

Log4 ^x = Log(8X)

Log4 ^x = Log8 + LogX

Log2 ^2x = Log2 ³ + LogX

Applying the laws of indices, we have

2XLog2 = 3Log2 + LogX

2XLog2 - 3Log2 = LogX

Log2(2X - 3) = LogX

Eliminating Log from both sides

2(2X - 3) = X

4X - 6 = X

4X - X = 6

3X = 6

X = 6/3

X=2

yeah, it's indeed a popular question. Well done.

By the way, are you also an aspirant?