thankyouJesus:

use
sin A + sin B = 2sin((A+B)/2) cos((A-B)/2)) = x
cosa + cosb = 2cos((a+b)/2) cos((a-b)/2) = y
divide x/y = tan((a+b)/2)
use knowledge of right angled triangle and Pythagora's to complete it.

Wrong approach.

thankyouJesus:


I stated the one for cos above.

sina - sinb = 2cos((a+b)/2) sin((a-b)/2)

continue from here

That is a terrible way to approach the problem. I believe they are more sophisticated identities that could bail you out.

Icosahedron:



That is a terrible way to approach the problem. I believe they are more sophisticated identities that could bail you out.

I dof my hat for you. Wrong approach! Smiles.


Well, what do I know?

holuwajobar:
Chop this simple math

4^x=8x......

Show workings....am nt interested in ur guess...

Trying to solve this analytically may raise some eye lids.
Use Falsi method to pick initial point, complete your solution with Newton Raphson method (Numerical Analysis).

thankyouJesus:

I dof my hat for you. Wrong approach! Smiles.


Well, what do I know?

Given that
sinA + sinB = x and
cosA + cosB = y

To solve this systems of equations. Sqaure both systems to obtain

sin²A + 2sinAsinB sin²B = x² (*)
cos²A + 2cosAcosB + cos²B = y² (**)

adding we obtain

2 + 2(sinAsinB + cosAcosB) = x² + y²
or
2 +2(cos(A-B)) = x² + y²

*** cos(A-B) = (x² + y² - 2)/2

Complete the solution thankyoujesus and you shall obtain similar argument for tan(A-B) and use the half-angle identity to obtain the value of tan(A-B)/2 and then proceed to solve the original problem.

Let a,b,c,d be numbers on the interval (0, 180) such that

sina 7sinb =4(sinc + 2sind)
cosa + 7cosb =4(cosc + 2cosd)

Prove that 2cos(a-d) = 7cos(b-c),

thankyoujesus you can actually use the method exemplified above to solve this problem.

Let ABC be a triangle, prove that

(a+b+c)[tanA/2 + tanB/2] = 2cotC/2

Icosahedron:
Given that
sinA + sinB = x and
cosA + cosB = y

To solve this systems of equations. Sqaure both systems to obtain

sin²A + 2sinAsinB sin²B = x² (*)
cos²A + 2cosAcosB + cos²B = y² (**)

adding we obtain

2 + 2(sinAsinB + cosAcosB) = x² + y²
or
2 +2(cos(A-B)) = x² + y²

*** cos(A-B) = (x² + y² - 2)/2

Complete the solution thankyoujesus and you shall obtain similar argument for tan(A-B) and use the half-angle identity to obtain the value of tan(A-B)/2 and then proceed to solve the original problem.

Your approach was highly sophisticated no doubt, welldone sir. Na you o, wetin I know.

Icosahedron:
Let ABC be a triangle, prove that

(a+b+c)[tanA/2 + tanB/2] = 2cotC/2

Why post questions you have solution to? Post questions you don't have solution to so that people can help.

I have lot to type based on our short memo but I dont take things personal. Word on marble, you are good no doubt but my working will also lead to same answer just that my approach is not sophisticated as you have rightly termed it, smiles.

Be flexible, most Mathematics questions can be solved in variety of ways.


Note: You can always beckon on me if you have Mathematics questions you can't solve. One love.

thankyouJesus:
Why post questions you have solution to? Post questions you don't have solution to so that people can help.

I have lot to type based on our short memo but I dont take things personal. Word on marble, you are good no doubt but my working will also lead to same answer just that my approach is not sophisticated as you have rightly termed it, smiles.

Be flexible, most Mathematics questions can be solved in variety of ways.


Note: You can always beckon on me if you have Mathematics questions you can't solve. One love.

Alright, I'll be sharing with you my Calculus assignments then if you UNIBEN accepts me since I don't like Calculus.

As for the problems above, I didn't have answers to them when I shared the problem on this forum, it was an exercise in a textbook I was reading for Trigonometry.

Icosahedron:



Alright, I'll be sharing with you my Calculus assignments then if you UNIBEN accepts me since I don't like Calculus.

As for the problems above, I didn't have answers to them when I shared the problem on this forum, it was an exercise in a textbook I was reading for Trigonometry.

Okay then.

Icosahedron:



Alright, I'll be sharing with you my Calculus assignments then if you UNIBEN accepts me since I don't like Calculus.

As for the problems above, I didn't have answers to them when I shared the problem on this forum, it was an exercise in a textbook I was reading for Trigonometry.

Please do dat ASAP

Patbaker:



Please do dat ASAP

I'm sorry but I don't get you

Icosahedron:


I'm sorry but I don't get you

Lol, she meant, do it quickly , WITHOUT wasting time

Tollicin:

Lol, she meant, do it quickly , WITHOUT wasting time

I should do what quickly

Icosahedron:


I should do what quickly

ARE you not the one that said, you want to share your calculus assignment ?

Tollicin:

ARE you not the one that said, you want to share your calculus assignment ?

Uhm.. Patbaker are you having problems on Calculus

Icosahedron:


I'm sorry but I don't get you

Lol I meant Please share ur calculus assignment with us as soon as possible ooo

Patbaker:



Lol
I meant
Please share ur calculus assignment with us as soon as possible ooo

I understand we applied for the same course at UNIBEN, right?

Icosahedron:

I understand we applied for the same course at UNIBEN, right?

Yeah i just hope we re all given the admission since the course is not competitive

Who can help me solve this step by step?

agentofchange1:


Yes

Ok

Add me up to the group...Pls 08172578620

Done !

Good day everyone.. Pls who can help me dissolve this mathematics.. Thanks

Please, I want Mathematics scholars to solve this question for meTake this Find x & y If x^x^x=log3 and x^y^y=log8.

celenas:
Good day everyone.. Pls who can help me dissolve this mathematics.. Thanks

the variation question. answer is $2500.
Factorization is 3 or 0.5.
that third X does not have any coefficient

agentofchange1:

Yes

08164430528 do it boss

gurus help me out I'm half way

rjek:
Who can help me solve this step by step?

Ordinary differential equation? It is exact.

celenas:
Good day everyone.. Pls who can help me dissolve this mathematics.. Thanks

1. You have to dismantle the shape into different shapes like triangle. Your knowledge of corresponding, alternate and opposite angle will be tested.
2. Use completing the square method.
3. Someone has provided answer already.

seunlly:
gurus help me out I'm half way

What are you trying to do?