agentofchange1:
greetings great geniuses here ... its been a while.

Greetings bro.

what else can I say than thank you to all who help me out and those who are not chanced am really grateful

How do I integrate 3^x log 3

download post utme past question from here www.pastquestionblog..com

pls help solve the following:
1. find the equation of the curve with gradient 2x+3 and which pass through the point (2,6)

2. suppose y varies as the sum of two quantities, one of which varies directly as x and the other inversely with x. when x =2, y = 7. find the relationship between x and y

samola01:
pls help solve the following:
1. find the equation of the curve with gradient 2x+3 and which pass through the point (2,6)

2. suppose y varies as the sum of two quantities, one of which varies directly as x and the other inversely with x. when x =2, y = 7. find the relationship between x and y

Are you sure the second question is comprehensively asked extremely well?If yes then the repeated use of the variable x is a suspect because there will be two different constants unless you want to expect the person to use the same constant for the variable x twice or otherwise.The question is a partial or part variation question though and it has to be properly looked into very well.If the question is correct then the two forms will be y=kx and y=k/x of which if you add both of them together you will have y=kx+k/x if that's what you expect though and substituting the values of x and y into that equation it will result to y=(14x^2+14)/5x.But if we solve it with two different constants as against the same constants then it will be a different ball game.
For the first question, the gradient is already the derivative of x which implies that it will be integrated with respect to x and it will be y=x^2+3x+c.On substituting this to x=2 and y=6 the value of c will be gotten as -4 which will be inputed into the function gotten so that at the end of the day the equation of the curve will be y=x^2+3x-4.

hello,i really need help with this question.An isosceles triangle of sides 13,13,10 is inscribed in a circle.what is the radius of the circle.anybody? Tanks in advance

ElectGINeer:
How do I integrate 3^x log 3

Here is the solution.

Aybalance:
hello,i really need help with this question.An isosceles triangle of sides 13,13,10 is inscribed in a circle.what is the radius of the circle.anybody? Tanks in advance

You did not give the units for the dimension. So, I will assume that it is in cm. The radius of the circle is approximately 7.04 cm. See the solution....

naturalwaves:

You did not give the units for the dimension. So, I will assume that it is in cm. The radius of the circle is approximately 7.04 cm. See the solution....

clear and understood.thanks once more.really appreciated

pls,i also need help on this simplification.thanks in advance

Aybalance:
clear and understood.thanks once more.really appreciated

You are welcome!

Aybalance:
pls,i also need help on this simplification.thanks in advance

You need to write out the questions well. Is that a raised to power 4/3? Your a also looks like 9.So, write out the question properly so I can solve.

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No let see the solution

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4+5+6+1+3+8=27

Now since 27 is divisible by 9 so 456138 will be divisible by 9 too.

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naturalwaves:

You need to write out the questions well. Is that a raised to power 4/3? Your a also looks like 9.So, write out the question properly so I can solve.

sorry for that .i think i need 2 improve on my writing but anyways it is 4/3 and every thing is "a" not 9.if it is still unclear ,i could post the questions again .thanks

Aybalance:
sorry for that .i think i need 2 improve on my writing but anyways it is 4/3 and every thing is "a" not 9.if it is still unclear ,i could post the questions again .thanks

okay. I will solve . I am on the road.

naturalwaves:
okay. I will solve . I am on the road.

natural waves ,am still expecting your reply because av been trying the question all this day without solution .I think da question iz faulty.But i need confirmation from someone

Aybalance:
natural waves ,am still expecting your reply because av been trying the question all this day without solution .I think da question iz faulty.But i need confirmation from someone

Okay. Will solve it today.

Aybalance:
pls,i also need help on this simplification.thanks in advance

Here is the solution :

naturalwaves:

Here is the solution :

Am really glad,thanks man

Pls guys help me solve this calculation wit explanations.
Alhaji bello has 36months car loan of #50,000 @ 12% interest rate per annum. What is the MONTHLY loan repayment?

Aybalance:
Am really glad,thanks man

You are welcome.You understand the solution well, right?

afo7219:
Pls guys help me solve this calculation wit explanations.
Alhaji bello has 36months car loan of #50,000 @ 12% interest rate per annum. What is the MONTHLY loan repayment?

There are different ways to solve this but let us take a simple approach. Since the interest rate is given per annum, you have to use years to solve.
36 months is 3 years. Number of years = 3 years.
Let us now calculate his interest
I= PRT
I= 50000* 12/100 * 3
I= 18000
The interest is 18,000 naira. So, the amount he is supposed to pay for the whole 36 months will be 50,000+ 18,000 = 68,000 naira.
This means that he is going to pay 68k back for the 50k he collected.
Since he is going to pay 68000 naira for 36 months, he will pay 68,000/36 every month and that will be #1,888. 89k.
Every month, he will pay #1,888.89k

naturalwaves:

There are different ways to solve this but let us take a simple approach. Since the interest rate is given per annum, you have to use years to solve.
36 months is 3 years. Number of years = 3 years.
Let us now calculate his interest
I= PRT
I= 50000* 12/100 * 3
I= 18000
The interest is 18,000 naira. So, the amount he is supposed to pay for the whole 36 months will be 50,000+ 18,000 = 68,000 naira.
This means that he is going to pay 68k back for the 50k he collected.
Since he is going to pay 68000 naira for 36 months, he will pay 68,000/36 every month and that will be #1,888. 89k.
Every month, he will pay #1,888.89k

sorry. I have tried this approach n I got d same tin but d answer is 1,661

Which other way can one use to solve it?

afo7219:
sorry. I have tried this approach n I got d same tin but d answer is 1,661

The answer is wrong then. Not everything you see in a book is correct.

Good job here!

naturalwaves:

It does not satisfy. Will solve again and see where it went wrong when I am settled. Thanks.


Modified:

X is undefined at 0. Hence x is not equal to 0 and cannot be substituted either. Try out other sets of values and you will see that the answer is absolutely correct. The reason why X is undefined at 0 is because one of the given terms in the question has X as its base. Therefore, X cannot be subtututed at 0. CC: masperano

Nah I don't think so (although I picked the wrong example), I am pretty sure it is incorrect. Try any number greater than -2/3 but less than 4/3 (for example 1 which is greater than -2/3)... Your solution crumbles ( it fails to satisfy the quadratic).
Or indeed try out other values outside your solution set, say -5 (infact any number less than -2/3) you see that it satisfies the quadratic solution which again invalidates your solution.

The true solution to that your quadratic equation is x<-2/3 and x>4/3. Cheers!

naturalwaves:
You are welcome.You understand the solution well, right?

100% clear.Ar u a student,aspirant or ??.Sorry 4 the questions

masperano:


Nah I don't think so (although I picked the wrong example), I am pretty sure it is incorrect. Try any number greater than -2/3 but less than 4/3 (for example 1 which is greater than -2/3)... Your solution crumbles ( it fails to satisfy the quadratic).
Or indeed try out other values outside your solution set, say -5 (infact any number less than -2/3) you see that it satisfies the quadratic solution which again invalidates your solution.

The true solution to that your quadratic equation is x<-2/3 and x>4/3. Cheers!

Bro, you are still wrong, X > -2/3, x >4/3 is the correct set. This means that -2/3 < X > 4/3. If you look at this, it looks disjoint because we could then just say that X > 4/3 since it is greater than -2/3 as well. In such cases, rather than write X> -2/3 or X > 4/3 which is the same as -2/3 < X > 4/3, the proper way of writing it when such situation occurs is -2/3 < X < 0, X> 4/3.The only mistake I made was not to split it with the "0" interval. Therefore correct answer is -2/3 < X <0, X> 4/3



Quick check.: -2/3 is approximately -0.667 which is approximately -0.7. The set of values that will satisfy my answers for part 1 are all numbers that are greater than this(-0.7) but less than 0. Examples of such are; -0.5,-0.4,-0.3,-0.2,-0.1 etc. You can try as much as you want.
Note: All trials must be checked with the initially given inequation and not the quadratics you are trying it out with.

I even used online tools and inequality solvers online to crossycheck and this was what they showed.

Aybalance:
100% clear.Ar u a student,aspirant or ??.Sorry 4 the questions

No bro. I grad 7 years ago o.

@masperano. See another solution from cymath