₦airaland Forum

JoyceTed:
Net force= ma Fr= Umg Umg= ma a= Ug = 0.7 * 10= 7m/s^2
So v^2= u^2 + 2as u=0, so find v lidat

wrose:
when the brakes of the automobile is pressed, friction sets in between the tyres and the road, thus creating a dynamic friction with the moving car. From this, we can infer that the ;

Frictional force created= Total force applied by the brakes.

F=Fr.

Taking dynamic friction=¶=0.7
g= 10m/s^2
mass=1500kg
Initial velocity= 20m/s
Final velocity= 0m/s
Fr=¶R........1
also Fr=ma........2

;¶R=ma

¶ m×g=m×a

¶g=a

; acceleration= 0.7×10 =7m/s^2


From V^2=U^2+2as

and U=0

20^2=0+(2×7×s)

400=14s

; s=400/14

s= 28.57m
; Distance travelled during that motion=28.57m

EngrBello:
The coefficient of Friction , is it 017 or 0.17 ASAP

JoyceTed:
Help a sis please.....
0.16g of methane when burnt increases the temperature of 100g of water by 40 degree centigrade, what is the heat of combustion of methane if the heat capacity of the water is 4.2jg/10/c

Mobuoy19:
Good evening guys,
Here I am again...

1. In 24 days, a radioactive isotope decreases in mass from 64g to 2g. What is the halflife of the radioactive material?

2. The count rate of an alpha particle source is 400 per minute. If the half life of the source is 5 days, what would be the count rate per minut after 15 days?

3. 0.46g of ethanol when burned raised the temperature of 50g of water by 14.3k. Calculate the heat of combustion of ethanol. (O=16, H=1, Specific heat capacity of water = 4.2JgK^-1

Mobuoy19:
Q= MC∆θ Heat loss by methane = Heat gained by water M=100g, C= 4.2, ∆θ= 40°C H= 100 X 4.2 X 40 H= 16800J ≡ 16.8KJ 0.16g --------> 16800 16g(Rmm of CH4)---------> (16 x 16800)/ 0.16 = 1680000J ≡ 1680KJ ∴ the heat of combustion of methane is 1680KJ

Hardebaryor:
Please a friend of mine had D7 in phy in his result and he wants to go to the medical line. Will he be admitted for that course if he meets the required cut off mark in post utme?

EngrBello:
You guys are just advertising for Lamlad

.. are they no other books? e.g Albabio for Chemistry..A1 or calculation in physics and so on... Tell him,is not too late to read¿he just need consistency and setting of Target

for the question...

2CO + 2H2 → CH4 + CO2

2moles of CO → 6.02 × 10²³(Avog. Const)

n moles of CO → 8.75 × 10^25

n =( 8.75 × 2 × 10^25)/(6.02 × 10²³)

n = (17.50 × 10²)/6.02

n = 2.905 × 10²

n = 290.5moles of CO

mass of CO now= n x m.m

m = 290.5 × 28

m = 8134g

Ajet001:
pls check the question again
"required to produce 8.75*10^25molecules of what" I don't want to mix things up
.

CondomSir:
Just enter the card details and the OTP when it is sent to you by your bank. You don't need to indicate your bank name or anything similar. It's really simple.

Kunzu:
Dats ur own opinion sir, and no one can question u 4 dat. Also, unilorin is not a poo as u Have mentioned, it's one of the best Universities in Nigeria.

Kunzu:
The general cut off mark might be 180, but there are some dept in which their cut off marks is more than that and if you don't meet it, u will be moved to other departments

CondomSir:
The card name is your full name written on your card. The card number is that longer number(16 digits or so) on your card.

Adewhunmiiii:
It's either you pay at the bank or the other way by using master card/verve card/Internet banking. You can use whichever suit you.. I remember I used GTB mastercard last year and it was fast.. All you need do is to fill the required details on your atm card on the transaction id.
Put your mind at rest and let them open the portal officially for you to know what to do.

azora:
Thanks

Ajet001:
Yea You upload your O' level results.

CondomSir:
It'll not hurt to use Google Chrome or Firefox on your phone to input your data. But you'll need to upload certain files such as O'level results, signature, etc. Again, you'll need to print out the registration slip. Therefore, it is advisable you go to a nearby cybercafe to carry out the processes.

Ajet001:
Good morning everyone
Now that UI has made it official(on the school website) that post-UTME is gonna hold this year I employ everyone to start burning the candle for the last phase of the 2017 admission.

I pray God will grant us success.

In preparations to the exam don't be scared just try to revise what you've learned when preparing for UTME but this time with more focus and dedication
Thanks.





PS. Login in of bio-data to start next week (last week of August)

CondomSir:
Physics is the most explicit subject though.
I have problems with chemistry too.