Miscellaneous:


1. Given: Y-4x+3=0

when y=0,
0-4x+3=0
-4x=-3
=>>> x=3/4
the point is thus =(3/4,0)

when x=0,
y-4(0)+3=0
y =-3
=>>> y=-3
thus the point is =(0, -3)

but, midpoint=(x1+x2)/2, (y1+y2)/2

for x, (3/4+0)/2=3/8
for y , (-3+0)/2 =-3/2

>>> therefore, midpoint is (x,y) = (3/8,-3/2)

2. Given 4X + 3Y - 5 = 0

we proceed by putting it in gradient intercept form
i.e , Y= -4/3X +5/3

for 2 lines to be perpendicular, m1 * m2 = -1

thus, -4/3 * 3/4 will = -1

so new gradient for perpendicular will be 3/4

from formula for gradient,

(y-y1)/(x-x1) = m2

so, 4(y-3) = 3(x+2)

4y -12= 3x+6
=>>>>>> 4y=3x+18

tuwayz:
. Thanks bro, I didn't understand the second solution though

Miscellaneous:


I simplified it as much as I could.....

just tell me wat u dont understand there ……& I'll explain.

tuwayz:
. Right from the start I don't knw hw U got d values, I taught u were making Y subject of formular but I got confused d 1st 3 steps how did u get d values pls

Miscellaneous:


4rm coordinate geometry,
the gradient intercept form is: y = mx + c
where m=gradient of the line

so, the first thing I did was actually making Y the subject of formula.

look closesly & u will see that on that line equation u made Y the subject, it's m = -4/3

Then we proceeded forward by using the rule for two lines to be perpendicular……… m1 * m2 = -1

m1 = the gradient of the 1st line
m2= gradient of 2nd

we don't av m2 .
make m2 the subject in

-4/3 * m2 = -1

i.e m2 = 3/4

then proceed………… using the formula for one-point form

(y-y1)/(x-x1) = m2

jackpot:
^^
@Miscellaneous, come and finish what you started.

Miscellaneous:


lol....

@ameer2 for two lines to be perpendicular, then the angle must be 90°

thus, from elementary mathematics,

tan90° = (m2- m1)/(1 + m2m1) which has no finite value.

so, 1 + m2m1 = 0

i.e, m2m1 = -1 for two perpendicular lines

ameer2:
wow...seems im grabbing somtin from dis...0=parallel line/perpendicular line? Ryt

jackpot:
Hello, Mr FuckYou!

FuckYou:
Please help!!
Angle of elevation:
-an engineer wishes to bridge a river.he observe that the angle of elevation of the top of a tree on the far bank is 27degree from a point on the near bank and 14degree from a point 30m further back.. How wide was the river Thanks
(2)from point P on level ground the angle of elevation of the top of a tower is 26degree 51'(min),from a point 25m closer to the tower and on the same line with p and the base of the tower of the angle of elevation of the top is 53degree 30min.... Calculate to three significant figures the height of the tower..
Please help me drawing(photo) will be highly appreciated. Thanks

FuckYou:
Angle of elevation:-an engineer wishes to bridge a river.he observe that the angle of elevation of the top of a tree on the far bank is 27degree from a point on the near bank and 14degree from a point 30m further back.. How wide was the riverThanks

mesoade:
The sum of the first n term of a geometric series is 127,the sum of their reciprocals is 127/64 ,the first term is 1 ,find n and the common ratio . .
.
Cc
factorial1
miscellanous

jackpot:
n=7, r=2

Hint:
(1-r^n)/(1-r)=127, (1-r^(-n))/(1-r)=127/64. Solve simultaneously.

mesoade:
it's the simultaneous part that gives me prob. . . Pls,kindly finish it for me

jackpot:
it is simple nah. Multiply the second equation with r^(n-1). You will now get 127=(127/64)r^(n-1), so r^(n-1)=64, so r^n=64r. Now, from 1-r^n=127(1-r), we have 1-64r=127(1-r). The rest is banana

mesoade:
thanks bro,but how did you come about that@emboldened

jackpot:
gave you lollipop to lick and you just returned it. Well, lemme savour the sweet taste.

Multiplying both sides of (1-r^(-n))/(1-r^(-1))=127/64 with r^(n-1), we have

(127/64)r^(n-1)= [(1-r^(-n))/(1-r^(-1))]r^(n-1)= [r^n(1-r^(-n))]/[r(1-r^(-1))]=(r^n-1)/(r-1)=(1-r^n)/(1-r)=127.

Therefore, (127/64)r^(n-1)=127 implies r^(n-1)=64.


Yummmmmmy. . .sweet

jackpot:
gave you lollipop to lick and you just returned it. Well, lemme savour the sweet taste.

Multiplying both sides of (1-r^(-n))/(1-r^(-1))=127/64 with r^(n-1), we have

(127/64)r^(n-1)= [(1-r^(-n))/(1-r^(-1))]r^(n-1)= [r^n(1-r^(-n))]/[r(1-r^(-1))]=(r^n-1)/(r-1)=(1-r^n)/(1-r)=127.

Therefore, (127/64)r^(n-1)=127 implies r^(n-1)=64.


Yummmmmmy. . .sweet

Hmmmm! Powerful, See scholar.

Dacronym:
Consider a rectangle with perimeter 28(units). Let thd width of the rectangld be w (units) bnd let the area of the region enclosed by the rectangle bd A (square units). Express A as a function of w. State the domain of A and find the range of A.

jackpot:

A(w)= w(14-w).
Domain A= { w: 0<w<14}

Range A= (0, 49]

Dacronym:

pls do you understand the question? No disrespect but This ans is incorrect. And if its not pls show workings cos i dont understand what u did

jackpot:

A(w)= w(14-w).

Domain A= { w: 0<w<14}

Range A= (0, 49]

dejt4u:


A(w)= w(28-w)

Tpappie:



A(w) is w(14-w)

Dacronym:
...This ans is incorrect. And if its not pls show workings cos i dont understand what u did

jackpot:
I bet any other different answer you post is incorrect.

Dacronym:
Consider a rectangle with perimeter 28(units). Let thd width of the rectangld be w (units)

Dacronym:
let the area of the region enclosed by the rectangle bd A (square units). Express A as a function of w.

jackpot:

[b]A(w)= w(14-w).