Welcome, Guest: Register On Nairaland / LOGIN! / Trending / Recent / NewStats: 3,194,234 members, 7,953,882 topics. Date: Friday, 20 September 2024 at 08:16 AM |
Nairaland Forum / Nairaland / General / Education / A Thread For 2014 GCE Candidates (22123 Views)
2013/2014 NECO GCE Candidates.practical,theory Nd Obj Answers Available Here!!! / Gce Candidates(waec,neco & Nabteb) / Past Gce Candidates Share Ur Experience On Food And Nutrition Practical Exam (2) (3) (4)
(1) (2) (3) (4) (5) (6) (7) (8) (9) (10) ... (14) (Reply) (Go Down)
Re: A Thread For 2014 GCE Candidates by Nobody: 8:36am On Aug 04, 2014 |
cumz: a very good morning to you all....Good morning bro 1 Like |
Re: A Thread For 2014 GCE Candidates by emmy02(m): 8:45am On Aug 04, 2014 |
Just in case u haven't registered yet, iv got the pin for registration for just N9500. Closing date is 15/8/2014 |
Re: A Thread For 2014 GCE Candidates by cumz(m): 8:57am On Aug 04, 2014 |
godG:thanks bro. you are really doing a great job |
Re: A Thread For 2014 GCE Candidates by beatsbyj2g(m): 10:16am On Aug 04, 2014 |
Rapsainot: sent.... notify me if it gets to youthanks have seen it |
Re: A Thread For 2014 GCE Candidates by Aphex(m): 10:20am On Aug 04, 2014 |
cumz:jus got them sha |
Re: A Thread For 2014 GCE Candidates by beatsbyj2g(m): 10:40am On Aug 04, 2014 |
June 2006 waec alternative to practical question. 1. A is a solution containing 6.3gdm^-3 of HNO3, B is a solution of Na2CO3 . À. Put A into d burette n titrate it against 20.0cm3 or 25.0cm3 portion of B using methyl orange as indicator . record d volume of ur pipette. Repeat d titration to obtain consistent titres. Tabulate ur burette reading n calculate d average volume of A used. The equation for d reaction involved in d titration is 2HNO3 + Na2CO3 ---> 2NaNO3 + CO2 + H2O. B. From ur result n information provided above, calculate d 1. concentration of B in mol dm^-3 2. Concentration of B in g ddm^-3 3. Mass of sodium ions in 1.0 dm^-3 of B . {H=1; C=12; O=16 N=14 Na =23}. Pls help with proper explanation 1 Like |
Re: A Thread For 2014 GCE Candidates by Nobody: 11:46am On Aug 04, 2014 |
godG:Nice 1 bro... but please explanations on summary and comprehension ll be more appreciated. Good morning sir |
Re: A Thread For 2014 GCE Candidates by Rapsainot(m): 11:47am On Aug 04, 2014 |
Pprovost: |
Re: A Thread For 2014 GCE Candidates by cumz(m): 12:03pm On Aug 04, 2014 |
beatsbyj2g: June 2006 waec alternative to practical question.oya all the chemist gurus.... over to you |
Re: A Thread For 2014 GCE Candidates by Nobody: 12:07pm On Aug 04, 2014 |
beatsbyj2g: June 2006 waec alternative to practical question.wow. gud. but let me tell you dat you can not have this kind of question in GCE.... since we can not titrate(external exam) but ll only be given the result of the titration and have to answer some calcuations starting with balancing the equation (the equation here is balanced anyway). but we need a titre value |
Re: A Thread For 2014 GCE Candidates by cumz(m): 12:13pm On Aug 04, 2014 |
Pprovost:guessed as much. . .. please bring physics questions... I might be able to help. that's what am studying in school |
Re: A Thread For 2014 GCE Candidates by Nobody: 12:48pm On Aug 04, 2014 |
Re: A Thread For 2014 GCE Candidates by Nobody: 12:48pm On Aug 04, 2014 |
don't forget that it is d volume of the acid we are looking for in titration (burrete reading) so that we can get the concentration of the base. alternative method is dis It is easy to get the concentration of Acid by using this formular... i.e concn in moldm-3= concn in gdm-3/molar mass ( molar mass of HNO3 in dis case) then to get the concn of Base in moldm-3 u simply apply cava (If you can still remember) i.e CAVA/CBVB=NA/NB (don't forget dat you ll get NA and NB from a balanced equation above) Now to get the concn of d base in gdm-3. u just multiply d concn in moldm-3 by the molar mass(i.e molar mass of Na2CO3 pls ask questns if you are not clear |
Re: A Thread For 2014 GCE Candidates by peterirhivben: 1:04pm On Aug 04, 2014 |
FOR ALL UNIVERSITY POST UME, POLYTECHNIQUES AND COLLEGE OF EDUCATIONS, ENTRANCE EXAM LIKE P.T.I,E.T.C ALSO RECOMMENDED FOR THOSE PREPARING FOR JAMB, WAEC, NECO AND OTHERS CHEMISTRY GENERAL OBJECTIVES The aim of this question pack in Chemistry is to prepare candidates for all possible questions in chemistry examination. It is designed to test their achievement of the course objectives, which are to prepared the candidate to be able to quickly tackle any questions in chemistry. The video DVD will help candidate apply the knowledge of chemistry to industry and everyday life. TOPICS/CONTENTS/NOTES 1. SEPARATION TECHNIQUES 2. ATOMIC STRUCTURES AND PERIODIC TABLE 3. BONDING AND SHAPES OF MOLECULES 4. NUCLEAR CHEMISTRY 5. CHEMICAL COMBINATION 6. KINETIC THEORY AND GAS LAW 7. RATE OF REACTION AND EQUILIBRIUM 8. ACID BASE SALT 9. OXIDATION ANND REDUCTION 10. ELECTROCHEMICAL CELL AND ELECTROLYSIS 11. WATER SOLUTION AND SOLUBILITY 12. OXYGEN HYDROGEN AND AIR 13. NITROGEN AND SULPHUR 14. CARBON AND ITS COMPOUND 15. HALOGEN AND ITS COMPUND 16. NON-METAL AND ITS COMPOUND 17. METAL AND TRANSITION METAL 18. HYDROCARBON 19. ORGANIC CHEMISTRY-ALKANE, ALKENE ALKYNE 20. ORGANIC CHEMISTRY – ALKANOL, ALKANOIC ACID, ALKANOATE 21.ORGANIC CHEMISTRY- GAINT MOLECULES 22. INDUSTRIAL CHEMISTRY 23. MODERM CHEMISTRY 24. CHEMISTRY FORMULAR AND EQUATION 25. CHEMISTRY PRACTICALS for enquiry call: 09096119817 e-mail: edumate2015@gmail.com; blueprinteducationaldvd@gmail.com |
Re: A Thread For 2014 GCE Candidates by Nobody: 1:11pm On Aug 04, 2014 |
to get d mass of ion just multiply 1.0 (given) by 6.23x10-23 (avogadro's constant) |
Re: A Thread For 2014 GCE Candidates by beatsbyj2g(m): 3:10pm On Aug 04, 2014 |
Thank u very much for d chemistry problem solution. But one more thing is Physics there are just too many formulas can u pls help us out with the basic formulas we would need especially in d practicals n theory |
Re: A Thread For 2014 GCE Candidates by cumz(m): 3:41pm On Aug 04, 2014 |
beatsbyj2g: Thank u very much for d chemistry problem solution.yeah yeah.. I think I can do that... but don't know how convenient it will be typing on this my palasa techno....Buh I will try... will go topic by topic |
Re: A Thread For 2014 GCE Candidates by Rapsainot(m): 3:54pm On Aug 04, 2014 |
cumz:thanks |
Re: A Thread For 2014 GCE Candidates by beatsbyj2g(m): 4:05pm On Aug 04, 2014 |
cumz:thank u very much |
Re: A Thread For 2014 GCE Candidates by cumz(m): 4:14pm On Aug 04, 2014 |
beatsbyj2g: thank u very much Rapsainot: thanksy'all welcome... but currently busy... before today runs out will surely update |
Re: A Thread For 2014 GCE Candidates by ultraawesome(m): 11:10pm On Aug 04, 2014 |
. |
Re: A Thread For 2014 GCE Candidates by sacrono: 11:35pm On Aug 04, 2014 |
ok guys.. 60cm3 of hydrogen was sparked with 20cm3 of oxygen at 100degree/C. The total volume of the residual gases is ?? I think the book am solving with got the answer wrong so please i need confirmation |
Re: A Thread For 2014 GCE Candidates by cumz(m): 7:40am On Aug 05, 2014 |
SIMPLE MACHINE... A machine is a device that makes work easy. Its also a device where little application of force can overcome great amount of load. MECHANICAL ADVANTAGE.. This is the ratio of of load to effort I.e M.A=LOAD/EFFORT. M.A=L/E...... it has no unit VELOCITY RATIO this is the ration of distance moved by effort to distance moved by load.. V.R= DE/DL.. EFFICIENCY this is the ratio of useful work done by machine to the useful work done on the machine. also define as the ratio of useful work output to useful work input. E= (work output/work input)× 100% E= (WORK DONE ON LOAD/WORK DONE ON EFFORT) × 100% E= {[L × DL]/[E ×DE] } × 100% E= M.A/V.R . . . . velocity ratio varies for different kind of machine inclined plane.. VR=I/SIN® WHEEL AND AXLE... VR=R/r... R= radius of wheel r= radius of axle. SCREW JACK.. V.R= 2πa/p a= radius of screw p= pitch . . hydraulic press... V.R= R²/r². R=radius of large ring r= radius of small Ring. . . PULLEY SYSTEM. V.R is the no of pulleys. . . . A very good morning to us.. more updates later |
Re: A Thread For 2014 GCE Candidates by cumz(m): 7:44am On Aug 05, 2014 |
sacrono: ok guys.. 60cm3 of hydrogen was sparked with 20cm3 of oxygen at 100degree/C. The total volume of the residual gases is ??I got 60cm³ is that your answer..?? |
Re: A Thread For 2014 GCE Candidates by beatsbyj2g(m): 9:25am On Aug 05, 2014 |
cumz:how did u solve this |
Re: A Thread For 2014 GCE Candidates by beatsbyj2g(m): 9:26am On Aug 05, 2014 |
cumz: SIMPLE MACHINE...good morning n thanks |
Re: A Thread For 2014 GCE Candidates by SenatorJames(m): 10:19pm On Aug 05, 2014 |
Success to you all!!! |
Re: A Thread For 2014 GCE Candidates by Ohraybs(m): 12:04am On Aug 06, 2014 |
cumz: Created this thread few months back, but the tsunami that happened on nairaland cleared it all...WAEC/NECO JAMB failure must surely rest in Peace.....Register with Distinction Tutorial Centre and you will surely make all your papers,our past results with our students is a guarantee that we can help you solve your constant getting of forms........Call us if you want us to help you out....The fee is not that much,Just 5k for all the subjects and we guarantee you SUCCess....Call us on 07030211988,or BB-Pin-2397cfcd or 2go-Ohraybs...... N.B-WAEC GCE form is still available...... |
Re: A Thread For 2014 GCE Candidates by Rapsainot(m): 1:32am On Aug 06, 2014 |
sacrono: ok guys.. 60cm3 of hydrogen was sparked with 20cm3 of oxygen at 100degree/C. The total volume of the residual gases is ??2H+O->H20, I.e if 2 moles of hydrogen sparks with a mole of oxygen, 40cm of hydrogen Wil react with 20cm of oxygen..... volume of the residual gas (volume of excess hydrogen) = 60-40=20cm3 so the final answer is 20cm3 |
Re: A Thread For 2014 GCE Candidates by cumz(m): 6:55am On Aug 06, 2014 |
Rapsainot: 2H+O->H20, I.e if 2 moles of hydrogen sparks with a mole of oxygen, 40cm of hydrogen Wil react with 20cm of oxygen..... volume of the residual gas (volume of excess hydrogen) = 60-40=20cm3 so the final answer is 20cm3well... you have to consider the volume of the gas produced to... like 20cm³ of oxygen will react with 40cm³ of hydrogen... and the volume of the gas produced is 40cm³.. so the residual gas is 40+20= 60cm³.. 2H2 + O2==== 2H20 ratio 2......:...1....;......2 volume that reacted .......40:......20............40 residual gas.. .........20:.......0.........40 volume left or residual gas will now be... 20+40= 60cm³ |
Re: A Thread For 2014 GCE Candidates by cumz(m): 6:58am On Aug 06, 2014 |
beatsbyj2g: how did u solve this |
Re: A Thread For 2014 GCE Candidates by cumz(m): 6:59am On Aug 06, 2014 |
anybody writing the exam in Ife here?? |
(1) (2) (3) (4) (5) (6) (7) (8) (9) (10) ... (14) (Reply)
OAU Students Union Maiden Newspaper:The Union Parrot. / Protest In Yabatech Over Death Of A Final Year Student (see Photos) / 100 Students Caught As UNILAG Begins Testing Students For Hard Drugs
(Go Up)
Sections: politics (1) business autos (1) jobs (1) career education (1) romance computers phones travel sports fashion health religion celebs tv-movies music-radio literature webmasters programming techmarket Links: (1) (2) (3) (4) (5) (6) (7) (8) (9) (10) Nairaland - Copyright © 2005 - 2024 Oluwaseun Osewa. All rights reserved. See How To Advertise. 50 |