cumz: a very good morning to you all....

godG:

Sorry about that, sir. What are the challenges you seem to be having? I don't want to take a shot in the dark by just rendering any help, sir. Anything you feel you need to know and we are on.

However, when I have the time, I'm still going to give some sorts of 'tricks' to answering questions in O Level English. I just hope I get one past question around me here, because I don't really know what the questions look like again.

Rapsainot: sent.... notify me if it gets to you

cumz:
yes I can...
I downloaded all of them recently from the net
will get the links for you if I still av them
or better still we can talk on watsap

godG:

Sorry about that, sir. What are the challenges you seem to be having? I don't want to take a shot in the dark by just rendering any help, sir. Anything you feel you need to know and we are on.

However, when I have the time, I'm still going to give some sorts of 'tricks' to answering questions in O Level English. I just hope I get one past question around me here, because I don't really know what the questions look like again.

Pprovost:
Nice 1 bro... but please explanations on summary and comprehension ll be more appreciated. Good morning sir

beatsbyj2g: June 2006 waec alternative to practical question.

1. A is a solution containing 6.3gdm^-3 of HNO3, B is a solution of Na2CO3 .

À. Put A into d burette n titrate it against 20.0cm3 or 25.0cm3 portion of B using methyl orange as indicator . record d volume of ur pipette. Repeat d titration to obtain consistent titres. Tabulate ur burette reading n calculate d average volume of A used. The equation for d reaction involved in d titration is 2HNO3 + Na2CO3 ---> 2NaNO3 + CO2 + H2O.

B. From ur result n information provided above, calculate d
1. concentration of B in mol dm^-3
2. Concentration of B in g ddm^-3
3. Mass of sodium ions in 1.0 dm^-3 of B .


{H=1; C=12; O=16 N=14 Na =23}.



Pls help with proper explanation

beatsbyj2g: June 2006 waec alternative to practical question.

1. A is a solution containing 6.3gdm^-3 of HNO3, B is a solution of Na2CO3 .

À. Put A into d burette n titrate it against 20.0cm3 or 25.0cm3 portion of B using methyl orange as indicator . record d volume of ur pipette. Repeat d titration to obtain consistent titres. Tabulate ur burette reading n calculate d average volume of A used. The equation for d reaction involved in d titration is 2HNO3 + Na2CO3 ---> 2NaNO3 + CO2 + H2O.

B. From ur result n information provided above, calculate d
1. concentration of B in mol dm^-3
2. Concentration of B in g ddm^-3
3. Mass of sodium ions in 1.0 dm^-3 of B .


{H=1; C=12; O=16 N=14 Na =23}.



Pls help with proper explanation

Pprovost:
wow. gud. but let me tell you dat you can not have this kind of question in GCE....
since we can not titrate(external exam) but ll only be given the result of the titration and have to answer some calcuations starting with balancing the equation
(the equation here is balanced anyway).
but we need a titre value

beatsbyj2g: Thank u very much for d chemistry problem solution.


But one more thing is Physics there are just too many formulas can u pls help us out with the basic formulas we would need especially in d practicals n theory

cumz:
yeah yeah..
I think I can do that...
but don't know how convenient it will be typing on this my palasa techno....Buh I will try...
will go topic by topic

cumz:
yeah yeah..
I think I can do that...
but don't know how convenient it will be typing on this my palasa techno....Buh I will try...
will go topic by topic

beatsbyj2g: thank u very much

Rapsainot: thanks

sacrono: ok guys.. 60cm3 of hydrogen was sparked with 20cm3 of oxygen at 100degree/C. The total volume of the residual gases is ??

I think the book am solving with got the answer wrong so please i need confirmation

cumz:
I got 40cm³ is that your answer..??

cumz: SIMPLE MACHINE...
A machine is a device that makes work easy.
Its also a device where little application of force can overcome great amount of load.
MECHANICAL ADVANTAGE..
This is the ratio of of load to effort
I.e M.A=LOAD/EFFORT.
M.A=L/E...... it has no unit
VELOCITY RATIO
this is the ration of distance moved by effort to distance moved by load..
V.R= DE/DL..
EFFICIENCY
this is the ratio of useful work done by machine to the useful work done on the machine.
also define as the ratio of useful work output to useful work input.
E= (work output/work input)× 100%
E= (WORK DONE ON LOAD/WORK DONE ON EFFORT) × 100%
E= {[L × DL]/[E ×DE] } × 100%
E= M.A/V.R .
.
.
.
velocity ratio varies for different kind of machine
inclined plane.. VR=I/SIN®
WHEEL AND AXLE... VR=R/r...
R= radius of wheel
r= radius of axle.


SCREW JACK..
V.R= 2πa/p
a= radius of screw
p= pitch
.
.

hydraulic press...
V.R= R²/r².
R=radius of large ring
r= radius of small Ring.
.
.

PULLEY SYSTEM.
V.R is the no of pulleys.
.
.
. A very good morning to us..
more updates later

cumz: Created this thread few months back, but the tsunami that happened on nairaland cleared it all...

Ok.. If u are writing Gce come september.. Come in and let's prepare together

sacrono: ok guys.. 60cm3 of hydrogen was sparked with 20cm3 of oxygen at 100degree/C. The total volume of the residual gases is ??

I think the book am solving with got the answer wrong so please i need confirmation

Rapsainot: 2H+O->H20, I.e if 2 moles of hydrogen sparks with a mole of oxygen, 40cm of hydrogen Wil react with 20cm of oxygen..... volume of the residual gas (volume of excess hydrogen) = 60-40=20cm3 so the final answer is 20cm3

beatsbyj2g: how did u solve this