seunlly:
Check this

help a bro with this.

find x and y 4x^2+3xy-2y^2=80 3x^2+xy-2y^2=48.

seunlly:
find x and y
4x^2+3xy-2y^2=80
3x^2+xy-2y^2=48.

Hint : let. y=vx....

Here

agentofchange1:
Here

bro u got that x but that y is not 2 and 6 Buh y is +-2

seunlly:
oops u can try again but that is not the answer

ok solved it with mathematica, got -3+1.00816 i and -3-1.00816 i

Good day...... I need ICAN study pack for skill level. I would be very glad if I can get it. My email address is adeshinaabayomi1@gmail.com. Thanks

[font=Lucida Sans Unicode][/font] it awe in the forum with mathematics gurus, kudos to u all

@Richiez
.
Can you solve this question for me?

If x^x^x = log3
and
x^y^y = log8.
Find x and y.

masperano:


ok solved it with mathematica, got -3+1.00816 i and -3-1.00816 i

that it.

(2)^n +1 = (3)^k where n and k are integers. Given that the pairs (1,1) and (3,2) are solutions in the form (n, k). Show that there exist another solution or no solution.

Cc: all of the maths gurus on this thread
Naturalwaves
Masperano
Agentofchange1

ratioxyz:
(2)^n +1 = (3)^k where n and k are integers. Given that the pairs (1,1) and (3,2) are solutions in the form (n, k). Show that there exist another solution or no solution.

Cc: all of the maths gurus on this thread
Naturalwaves
Masperano
Agentofchange1

There exist no other solutions outside (1,1),(3,2).

Indeed, for k>2, 3^k increases drastically and approaches 81 for k=4, and it would continue this way for higher values of k.

But 2^n , although an increasing function, it's growth is quite slow compared to 3^k. So, if we rewrite the equation as.

1 = 3^k - 2^n

the powers of 3 for k>2 are 27, 81, 243, 729, 2,187 . . .

and powers of 2 for n>3 are 32, 64, , 256, 128, 1024 . . .


So, since 3^k increases drastically than 2^n then there difference is never equal to unity hence no solution to the above equation.

Also. Subtract one from both sides to obtain 2^n = 3^k - 1. Now for k>3, this equation has no solutions, Indeed, we ask ourself, is there a power of 3 such that when diminished by unity equals a power of 2? Well, none(except) satisfies the given condition and observing how the sequence of powers of 3 increases drastically.

Deep analysis and care full argument has allowed us to conclude that the no solutions exist.


Remark: The question is quite cheap, to increase its difficulty, one could instead phrase it this way.

"Does there exist an integer k>2 such that 3^k - 1 is a power of 2"?

Icosahedron:




There exist no other solutions outside (1,1),(3,2).


Deep analysis and care full argument has allowed us to conclude that the no solutions exist.


Remark: The question is quite cheap, to increase its difficulty, one could instead phrase it this way.

"Does there exist an integer k>2 such that 3^k - 1 is a power of 2"?

Very nice attempt but I believe there are other solutions. You only considered the values of n to be little. If it's way higher, isn't there any chance the relationship between it and the power of 3 will be unity?

ratioxyz:
(2)^n +1 = (3)^k where n and k are integers. Given that the pairs (1,1) and (3,2) are solutions in the form (n, k). Show that there exist another solution or no solution.

Cc: all of the maths gurus on this thread
Naturalwaves
Masperano
Agentofchange1

No other pair(s) of solution exists.

seunlly:
bro the question is confusing.
is it the two mirror that is inclined at angle 40 or one of them.

sorry for the belated response. both mirrors are inclined at each other at angle 40. The first mirror will be drawn straight and the other will be inclined at it at angle 40 degree using a protractor. Here s the question again

DrinkWater10:
PHYSIC PLEASE.. sorry for derailing
Two plane mirrors are inclined at an angle of 40^o and a ray of light which makes an angle of incidence of 60^o with one of the mirrors happens to undergo two successive reflections at the mirrors. Determine the angle of deviation.

Back to math. please guys help me in solving these past questions- so that I can practise them.
Please solve it in a sheet of paper and post the snapshot for better understanding.
thanks in anticipation.

Back to math. please guys help me in solving these past questions- so that I can practise them. (preferably in a piece of paper)

thanks in anticipation.

DrinkWater10:
Back to math. please guys help me in solving these past questions- so that I can practise them. (preferably in a piece of paper)

thanks in anticipation.

I honestly think what you need is to have a good grasp of most of those concepts of limits, functions, differentiation, integration through thorough reading rather than just bring all of the questions here. I am sure that you can peruse them in 6 hours and go ahead to solve all these. Good luck!

please guys this is an assignment I need to submit tomorrow, help me out please, you as well help by tagging who will help please...


THANK YOU ALL



(1) three points A,B,C in the space have their position vectors defined by OA=(2,3,-1), OB=(1,-2,5) OC=(-1,0,4) relative to origin O find.

(a) the equation of line AB in symmetric form

(b)the equation of plane ABC

(c) the direction cosine of vector AC

(d) d/dt(A*B)

DrinkWater10:
PHYSIC PLEASE.. sorry for derailing
Two plane mirrors are inclined at an angle of 40^o and a ray of light which makes an angle of incidence of 60^o with one of the mirrors happens to undergo two successive reflections at the mirrors. Determine the angle of deviation.

Total angle of deviation =angle of deviation off mirror 1+angle of deviation off mirror 2
Total angle of deviation=60+60+20+20=160^o

Maths and science gurus needed @ the new educational help world
www.solutionxyz.com

two boats A and B left a port C at the same
time on different routes. B travelled on a
bearing of
150 and A travelled on the north side of B.
When A had travelled 8km and B had travelled 10km the distance between the two boats
was found to be 12km. Calculate the bearing of
A from C

benji93:

Total angle of deviation =angle of deviation off mirror 1+angle of deviation off mirror 2
Total angle of deviation=60+60+20+20=160^o

thanks bro but please can you post snapshot of your working for better understanding.

Profmaojo:
two boats A and B left a port C at the same
time on different routes. B travelled on a
bearing of
150 and A travelled on the north side of B.
When A had travelled 8km and the two boats
was found to be 12km. Calculate the bearing of
A route from C. Show your workings and
diagram

The two boats were found to be 12km what? Cross check the question and correct all omissions/ typos. Fast!

Profmaojo:
two boats A and B left a port C at the same
time on different routes. B travelled on a
bearing of
150 and A travelled on the north side of B.
When A had travelled 8km and the two boats
was found to be 12km. Calculate the bearing of
A route from C. Show your workings and
diagram

incomplete question

Engrcharlesid:
incomplete question

APART

naturalwaves:

The two boats were found to be 12km what? Cross check the question and correct all omissions/ typos. Fast!

APART

DrinkWater10:

thanks bro but please can you post snapshot of your working for better understanding.

Attached is a snapshot of the solution

Profmaojo:
APART

Retype the whole question particularly from ....when A had travelled 8km. That part doesn't make sense. Seems something is missing because you said ...." When A had travelled 8km AND the 2 boths were found to be 12km apart". Seems there is something before the "and" or just take a snapshot of the question. I think the question is from NGM. I have solved it before. Just cross check and type the correct thing or snapshot it.

Profmaojo:
APART

The distance of b from c is missing ....... i have solved it before ..

new general maths .
..
ss 2 ...

two boats A and B left a port C at the same time on different routes. B travelled on a bearing of 150 and A travelled on the north side of B. When A had travelled 8km and B had travelled 10km the distance between the two boats was found to be 12km. Calculate the bearing of A from C