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ANDREW2EIC's Posts

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EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 11:33am On Mar 17, 2013
Simplefemo: v=3u
1/3u+ 1/u=1/15
1+3/3u=1/15
60=3u
u=20cm
object distance, u= 20cm
U are wrong my guy.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 10:15am On Mar 17, 2013
Attempt this:

A certain far-sighted person cannot see objects that are closer to the eye than 50cm clearly. Determine the power of the converging lens which will enable him to see at 25cm.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 10:05am On Mar 17, 2013
Attempt this:

An image in a convex lens is upright and magnified 3 times. If the focal length of the lens is 15cm, what is the object distance?
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 8:13am On Mar 17, 2013
t.boy007:
1)Which of there undergoes condensation reaction
a)alkanol
b)amine
c)alkanal
d)haloalkane
Am biased towards option a) cos when they react with carboxylic or alkanoic acids they give out water. Is that correct?
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 8:06am On Mar 17, 2013
t.boy007:
A particle in a straight line specified by the equation y=4t^4 - 3t^3.find the acceleration after 3 seconds.
Velocity(v) of the particle = dy/dt = 4x4xt^3 - 3x3xt^2, v = 16t^3 - 9t^2.
Acceleration(a) of the particle = dv/dt = 16x3xt^2 - 9x2xt, a = 48t^2 - 18t., but t = 3seconds, hence:
a = 48(3^2) - 18x3, a = 48x9 - 18x3, a = 432 - 54, a = 378m/s

therefore the acceleration of the particle is 378m/s.
My 2cent on the question.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 7:44am On Mar 17, 2013
t.boy007:
2)which of the following react with NaOH to give double salts?
a)S02
b)S03
c)P04
d)N02
d)NO2,. This is because it is a mixed acid anhydride.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 8:10pm On Mar 16, 2013
buzyguy: Hmm,u r vry rite.no wahala jamb z already in wahala ijn.we r all gonna mak it big!
Amen o. We are gonna hammer wella
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 5:46pm On Mar 16, 2013
buzyguy: Mag.=v/u,v z sam with u in distance from da mirror.so 10cm/10cm=1 no unit.i lyk dat level don chang we r nw on level ten over ten.lolz!
Bravo for ur good reasoning. You know, after solving the question the first time, i just told myself "wow! Jamb could be so tricky sometimes".

I think why some students fail exams thesedays is dawn to lack of composure in exam hall, rather than ignorance.
I keep asking God for this wonderful virtue called composure together with serenity. With them, i know i will keep blasting exams after exams.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 3:07pm On Mar 16, 2013
Attempt this:

The magnification of an object tall when placed 10cm in front of plane mirror is
EducationRe: University Of Ibadan 2013/2014 Admission by ANDREW2EIC(m): 3:49pm On Mar 15, 2013
Good to be back after being absent for a while. Abi fynestboi don change to fynestbarrister or abi na another person?
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 8:28pm On Mar 14, 2013
t.boy007:
focal lenght=15
mirror's equation=>1/f=1/u + 1/v
since the image produced is 4 times the object.therefore 1v=4u.
So, 1/15=1/u + 1/4u
u=75/4
u=+18.75cm(since it's a concave mirror)
Gbam! You are On point.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 4:42pm On Mar 14, 2013
Attempt this:

A concave mirror of radius of curvature 30cm produced an inverted image 4 times the size of an object placed perpendicular to the axis. Determine the position of the object.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 7:01am On Mar 13, 2013
Nemidav: o! Owk. . . Gudluck bro.
Thanks a bunch
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 7:41pm On Mar 12, 2013
Nemidav: yu too. . .tot ui is a federal uni??
Yea, it is. I learnt that they admit 2nd choice candidates.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 7:46am On Mar 12, 2013
buzyguy: Yeah,whr av u bn snce?u r 2correct!
I have been around my guy, but didn't know the existence of this thread. I just found it yesterday. Anyways, how is jacking going over there? The D day is almost close
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 6:15am On Mar 12, 2013
buzyguy: Sum1 try ds,A Car of mass Mkg is accelratd uniformly frm rest by an engine power P.The minimum time it wil take to attain a speed V is,a.MV/P b.MV/2P c.MV^2/2P d.MV^2/P
My real guy nice to meet u here.
The answer to ur question is c).
Reason: the power of the accelerated car = energy expended by the car/time taken.
But in this case, the energy of the car is all kinetic.
Hence, power(P) = k.e/time(T), P = 1/2MV^2/T. Multiplying both sides by T.
PxT = 1/2MV^2/TxT, PT = 1/2MV^2. Divide both sides by P.
PT/P = 1/2MV^2/P,
Therefore, T = MV^2/2P.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 5:59am On Mar 12, 2013
Nemidav: thanks 4 d nice words smiley. . . i'm goin 4 medicine,uniben. . . I filld d same tin last year bur i was 10% lower dan medicine's cutoff,i was given biology tho. . Bur i turned it down. . . . Wht about you?
Our good Lord will grant you your heart desire this year. Am going for electrical electronics engineering, futo is my 1st choice while ui is my 2nd. Nice to have u around here.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 9:31pm On Mar 11, 2013
Nemidav: anoda method learnt,thanks

thanks alot. . I jst learnt sumfin very valuable 4rm yu.
Honestly, u are such a great guy. Very flexible and willing to learn. These are the qualities that are lacking among us the students, but am really challanged. If you don't mind, which course are u aspiring for and ur preferred institutions?
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 8:10pm On Mar 11, 2013
t.boy007:
wao @andrew,i've gained from that explanation of yours...
I think it can also be solved this way,
from the law of conservation of energy { F=Mv/t}
since f=30N,M=0.075kg,t=0.05
then make v the subject of the formula and solve.the final answer will be 20 N/s
U are on point my guy. If u multiply both sides of that ur equation by t, u wil get the same thing i used.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m):
Nemidav: I jst messd up!. . .neva knew momentum was = impulse
I woud rather say that u made mistake, but didn't mess up. Come on! Nobody is perfect, we make mistakes everyday. Just keep the good work up.
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 7:37pm On Mar 11, 2013
Nemidav: thanks!
U are welcome
EducationRe: Biology, Chemistry and Physics tutorial thread for jamb by ANDREW2EIC(m): 6:02pm On Mar 11, 2013
Nemidav: i solvd it lyk diz f=30N,T= 0.05S,M= 0.075kg,u=0...a=f/m;a=30/0.075;a=400
then i used s=ut+1/2at^2
s=1/2*400*0.0025
;s=0.5;using speed=distance/time;0.5/0.05=10. . . . And therez no 10 in d options,did i make a mistake?
Perhaps u were wrong. I think u unnecessarily prolonged a simple work.
Below is my little explanation to the question:

When a force f(N) is applied on a body of mass m(kg) for a given period of time t(s), the body gains momentum i.e, the massive body moves forward with a certain velocity. The gain in momentum is as a result of force which acts with time. With the already established fact, i can safely say that the gain in momentum is also as a result of impulse on the body. I believe u still remember that impulse is mathematically expressed as: force x time, ft. From law of conservation of energy, energy exhausted for exerted force on the body for a period of time = energy gained by the body to give it momentum.

Hence, impulse = momentum gained, i.e, ft = mv (where m=mass of the body, v = velocity gained. Of course, f is force and t is time taken)

Relating my explanation with the problem at hand, we have:

force exerted by the footballer = 30N, time taken = 0.05s, mass of ball = 0.075kg, velocity= ?.
Substituting:
30x0.05 = 0.075xV, 0.075V = 1.5 (divide both sides by 0.075)
0.075V/0.075 = 1.5/0.075
V = 20m/s.
Therefore, the velocity gained by the ball is 20m/s.

N:B, i only elaborated this much for u to understand what really happened, not that the question is really that difficult.

Hope that helps!
EducationRe: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 4:57pm On Mar 02, 2013
buzyguy: Mbbs,i already knw urz EEE rite?datz great,may God help us in 4 our desired coursez.AMEN! 1nce again am vry sori in all av gone wrong.thks!
Amen o! U are more than welcome my guy.
EducationRe: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 3:47pm On Mar 02, 2013
Tizzie: Enough of all this Bants,can we continue with the main reason for being on this thread already?
We were merely expressing our opinions to each other. It's really nothing serious. Busyguy is my real man. K?
EducationRe: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 3:41pm On Mar 02, 2013
buzyguy: i apologize 4 callin u a boy cuz evn kidz nw adayz reject such,letz bury da hatchet.peace! Itz A bro,mayb u didnt read it wel chck bak tru it.thkz
Apology accepted. I also sincerely tender my apology to you. I didn't mean to insult or debase ur integrity. We can stil be friends. Ehee! Before i forget, which course are u aspiring for? Nice weekend!
EducationRe: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 3:32pm On Mar 02, 2013
buzyguy: ltz nt a fight.ds thread z for a purpoze so let faze.
Fight? It's been more than decade i fought last and i can't imagine myself engaging in a fight with anyone.
EducationRe: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 3:27pm On Mar 02, 2013
buzyguy: so chang dat ur mentality,
Thank u for the advice, but.....
EducationRe: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 3:23pm On Mar 02, 2013
buzyguy: i shld say sumtn bt i dnt jst wonu offend any1 here ,
U have already written more than one page about a guy u've not met before.
EducationRe: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 3:19pm On Mar 02, 2013
buzyguy: i sense u r da one being discourteouz.
Perhaps that's ur opinion, but am really better than what you think of me. Am really a nice and easy-going guy.
EducationRe: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 3:11pm On Mar 02, 2013
buzyguy: if nt of my dream courz wich i stil av in mind,nd determd to pursue afta completn a degr i dnt fink i shld b here absorbn insultz frm an anönymouz fellow here.
Anonymous fellow? Adding insult to injury, yet u feign a gentleman. My name is Andrew and not anonymous fellow.
EducationRe: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 2:55pm On Mar 02, 2013
buzyguy: i wz silent cuz i knw itz nairaland tnz nd u r free to say worefa u wish here.wot do think?
Hell no! U weren't silent, rather u doubled the supposed insult. I also differ with u there. One is not entitled to say what one wants provided that it's deflamatory to other people's integrity or personality.( I myself, is not excepted to that).
EducationRe: Online tutorial in Physics, Chemistry, Maths for Jamb and pume by ANDREW2EIC(m): 2:54pm On Mar 02, 2013
buzyguy: do u rememba ur quote dat i mak a baseless argument,of courz datz 2ridiculouz 2my persnalty..
I was just trying to let u know that u needed to back ur argument with proof,cos i thought u countered my effort without enough reasons to put me right( i.e, if i was wrong). I didn't mean to insult you. Even if u were insulted by that, i think u should have called my attention.

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