₦airaland Forum

qtguru:
Would you switch something, when you already have a business running on node and making money, there is no cost benefit for switching as a business, unless you're one of those coders who like to switch for the sake of something new.

Af0nja:
What is practical test? You mean coding challenge? I've passed it

Putinofrussia:
Otedola back after 6 years.
I have never seen any billionaire in Nigeria give as he does.
Givers don't lack.
Welcome,sir

coputa:
Why the double speak,in the earlier report they said 100 million was paid before their release

Timoleon:
Fufu

preciouswoman66:
Have anyone try using Windows USB modem with Wine in Linux?

You mind sharing your experience and how you did it?

.

func Trebuchet(input string) int {
	data, err := utils.ReadFile(input)
	if err != nil {
		fmt.Println(err)
	}
	sum := 0
	v1 := strings.Split(data, "\n" )
	for _, y := range v1 {
		left := 0
		right := len(y) - 1
		ptr := 0
		a := 0
		b := 0
		for ptr <= len(y) {
			if y[left] >= 48 && y[left] <= 57 {
				a = int(y[left] - 48)
			} else {
				left++
			}
			if y[right] >= 48 && y[right] <= 57 {
				b = int(y[right] - 48)
			} else {
				right--
			}
			ptr++
		}
		v2, _ := strconv.ParseInt(fmt.Sprintf("%d%d", a, b), 10, 64)
		sum += int(v2)
	}
	return sum
}

func transform(word string) string {
	word = strings.ReplaceAll(word, "twone", "21" )
	word = strings.ReplaceAll(word, "eightwo", "82" )
	word = strings.ReplaceAll(word, "nineight", "98" )
	word = strings.ReplaceAll(word, "eightthree", "83" )
	word = strings.ReplaceAll(word, "threeight", "38" )
	word = strings.ReplaceAll(word, "fiveight", "58" )
	word = strings.ReplaceAll(word, "nineight", "98" )
	word = strings.ReplaceAll(word, "oneight", "18" )
	word = strings.ReplaceAll(word, "sevenine", "79" )
	v := []string{"one", "two", "three", "four", "five", "six", "seven", "eight", "nine"}
	for x := range v {
		word = strings.ReplaceAll(word, fmt.Sprintf("%d", x+1), v[x])
	}
	p := []string{"1", "2", "3", "4", "5", "6", "7", "8", "9"}
	for x := range p {
		word = strings.ReplaceAll(word, v[x], p[x])
	}
	return word
}