₦airaland Forum

Any one ?

EazyGiant:
There will be different values of " R " becos the polygon is irregular . The substended angle with respect to each arc / chord will determine the particular " R " in question . Definite method , not trial and error Sir . I have 2 questions for U ... 1). Do you agree with the substended angles stated above for each arc / chord ? If u disagree , make ur calculation and let's see . 2). Is the 7.42 u got for R the same for all the Rs in the Polygon ?

Irrespective of regular or irregular polygon inscribed in a circle the radius of the circle does not change it is a constant.
(1)I agree to your ratio of( lenght of arc/total lenght of chord ) x360 for only regular polygon to get angle subtended,
But this polygon is irregular, so I don't agree with your usage of this formula here it does not apply to irregular polygon
(2) yes the 4.2... I got for R is same for all R in the entire circle.
Hope you are convinced by this.

Check on my new shape and give it a trial sir

It is obvious a lot of people don't really understand how polygon operate must especially when dealing with irregular polygon, thus I made another shape on polygon
Find the area of the octagon,
Let the solving begin,
We are here to learn.
I remain Mr Shape

No hukus packus pls.

Anyone?

EazyGiant:
MrShape is absolutely wrong . The only person that got it right is Dacool1 . Dacool1 deserves an applause

I am very correct proof.
You guys got 7
Let me use the chord length of 5

This is wrong for irregular polygon my proof
L=2R sin(@/2)
R=5/(2sin(@/2))
R=5/(2sin(42.86/2))
R=2.5/sin(21.43)
R=6.842487

That is how all the radius of the different sector will be different, which is not true for a circle,
In a circle all radius at any point is equal.
Thus my solution is very correct,
I remain Mr Shape

EazyGiant:
This solution is wrong . The question is not as complex as u made it seems . Dacool1's solution is straight on point . U can apply his method for both regular and irregular polygon inscribe in a circle. Cheers

That's not true
Proof
The got 7
Let me use the chord length of 5

This is wrong for irregular polygon my proof
L=2R sin(@/2)
R=5/(2sin(@/2))
R=5/(2sin(42.86/2))
R=2.5/sin(21.43)
R=6.842487

That is how all the radius of the different sector will be different, which is not true for a circle,
In a circle all radius at any point is equal.
Thus my solution is very correct,
I remain Mr Shape

EazyGiant:
Solution

This is wrong for irregular polygon my proof
L=2R sin(@/2)
R=5/(2sin(@/2))
R=5/(2sin(42.86/2))
R=2.5/sin(21.43)
R=6.842487

That is how all the radius of the different sector will be different, which is not true for a circle,
In a circle all radius at any point is equal.
Thus my solution is very correct,
I remain Mr Shape

EazyGiant:
Use the same method to calculate the angles subtended by respective chords

This is wrong for irregular polygon my proof
L=2R sin(@/2)
R=5/(2sin(@/2))
R=5/(2sin(42.86/2))
R=2.5/sin(21.43)
R=6.842487

That is how all the radius of the different sector will be different, which is not true for a circle,
In a circle all radius at any point is equal.
Thus my solution is very correct,
I remain Mr Shape

Tonylyte:
Oga Ifada na u be this?

Yes oga slim we done carry shape come hare o

Mitocyan:
Nice try but this rule only applies to regular polygons.

It is wrong

Mitocyan:
Smart method but not cool. I was a bit shocked that you resorted to trial and error and this makes the problem less interesting. This method can work for any polygon with sides of arbitrary length and you made it look like we were supposed to use a property of prime numbers to arrive at the solution.

There is litrary no know way to do summation of more than three trigonometry inverse,
I was expecting someone to point that out.
The prime relationship is only on the length of the chord,

Find the area of the shaded region

Martinez39:
Post them. I have tried to no avail.

Let the anglees subtended at the center of each sector

by the perpendicular line draw from the circle centre

@1,@2,@3,@4,@5,@6

@1+@2+@3+@4+@5+@6=180

Sin^-1(1/R) +sin^-1(1.5/R)+sin^-1(2.5/R)+sin^-1 (3.5/R)

+sin^-1 (5.5/R)+sin^-1 (6.5/R)=180

The substitute values into R to check which is the

closest to 180° note you should start from values grater

than 6.5 because height of the longest chord

h=√(R^-6.5)

Note walfrom aphal can't even compute that and get

numerical values, so only substitution works or graph it

Thus R =7.4233units.
Look forward to my next shape, I remain Mr shape your shape lover,

DrayZee:
Is it 7.4?

Approximately 7.4
You are the first person to get it,
Show your workings sir

Adanairaland:
R = 17

Not correct madam.
Try again please

kombats:
r = 8.5
Prime = 17

Not correct sir
Try again sir

chloride6:
Simple



Let's see using the sin rule

R divided by the angle opposite to the prime number chord

This relation holds for all the prime numbers chords...

The sum of the opposite angles equals 360

While the sum of interior angles equals n-2 by 180

Solve for the rest..

Can you through more light on your methodology, I don't see any positive result from your explanation yet, please explain more

Gentle20love:
R = 9

Not correct sir
try again sir

NothingDoMe:
Na eye I use calculate am

In secondary school when there's no time we just do rough estimates based on observed distance on paper

OK make a solution and update your post people are looking up to u
I Am waiting sir

NothingDoMe:
Solved=7

7 is not correct

Smile no one has got it,
I will post solution later
Since it is already in frot page lets wait maybe someone will come with a solution

Martinez39:
I have been busy. Post your answer.

Cc. Mrshape

Martinez39:
Post them. I have tried to no avail.

Let the anglees subtended at the center of each sector

by the perpendicular line draw from the circle centre

@1,@2,@3,@4,@5,@6

@1+@2+@3+@4+@5+@6=180

Sin^-1(1/R) +sin^-1(1.5/R)+sin^-1(2.5/R)+sin^-1 (3.5/R)

+sin^-1 (5.5/R)+sin^-1 (6.5/R)=180

The substitute values into R to check which is the

closest to 180° note you should start from values grater

than 6.5 because height of the longest chord

h=√(R^2-6.5^2)

Note walfrom aphal can't even compute that and get

numerical values, so only substitution works or graph it

Thus R =7.4233units.
Look forward to my next shape, I remain Mr shape your shape lover,

Should I bring solution?

Don't restrictions you trial to prime numbers, think outside the box you will get the key to this shape

Any one?

jullidee2006:
I don't believe this...its either the data is wrong or it's an old research... currently in most schools (primary, secondary and tertiary) the girl child is topping most classes and departments in the various fields... boys ain't studying again like before...

You are very correct,
In my four schools the overall best in my junior school 2 and 3 are girls

In my four schools my overall best in jsz2 and Jss3 are girls, it depend on the location or environment

Anyone?

NOC1:
what other interpretation do you need. A woman and A man come together to become one via Marriage.

Good as a Lean man I now understand you.
You know many are afraid of X.
Lol

Salarys:
Basic Trig identity. Sin square X+Cos square X =1

Interpret it in a real life sense some are still staring at your comments and still wondering how it concerns marriage!

I am having difficulty posting shape with my other account thus I created this as a supplement fellow friends of shape.
Solve

If you understand this you will feel good please tell us what it means
Mathematics is a language a universal one, which can communicate to everyone irrespective of his country of origin
Please tell us what it means so that others can learn our language a bit.

Note: I am having difficulty posting shape with my other account @ifada123 thus I created another, fellow shape lovers.
I remain Mr shape.