₦airaland Forum

femi4:
This should do it

A rectangle is formed at the centre by merging the two squares.

So if x is the length of the square
L of the rectangle = 2x
b of the rectangle = length of the square = x
Diagonal = x√5

Now
4² + 4² = (4+ x√5)²

32 = (4+x√5)²
4+x√5 = 4√2
x = (4√2 - 4)/√5
Area of the square = x² = (4√2 - 4 )²/5 = 0.5490unit²

Martinez39:


A = (24 - 8√5) ÷ 5 ≈ 1.22229124 unit².

Cc. Mrshape

femi4:
(6-X)²+4² = 4² +(4+X)²
36-12X+ X²= 16 + 8X + X²
20x = 20
X = 1
Area of the square = 1² = 1unit²
Try again sir

Martinez39:
Mrshape aka Ifada123 didn't waste time in "killing" this shape. I look forward to seeing more shapes from Mrshape.

Martinez39:
Correct. Now you've gotten it.

Martinez39:
Assuming π = (22/7)

A = 49(π - 2) = 56 units²

Martinez39:
Assuming π = (22/7)

A = 49(π - 2) = 56 units²

femi4:
lol...That's about a week ban

Martinez39:
ABC = 1/2 unit² , MBN = 1/8 unit²

MNAC = ABC - MBC = ½ - ⅛ = 3/8 unit²

MNAC = 3/8 unit²

Martinez39:
No I didn't. It was simple.

femi4:
Login with the old moniker and click on your moniker. Scroll down to see if you were banned by mod or antispam bot

Martinez39:
3/8 unit².

femi4:
e.g Banned till 2020 or something like that

femi4:
Its workers day, i don't do shapes on workers day. How many months ban did you receive?

Akious2k2:
You did a good job but I noticed a slight mistake...
Check this,
Your area of triangle should be (half base x height) = (1/2 × 4) × sq. root of (16 - 4) = 2 × Sq root of 12 = 4 surd 3 units sq
Area of one sector = (60 / 360) pi 4 sq = 1/6 pi 4 sq
Area of the two sectors put together is therefore, 1/3 pi 4 sq
Answer is therefore,
Area of square - (4 surd 3) - (1/3 pi 4 sq)

You did a good job