₦airaland Forum

olasesi: INSANELY PATRIOTIC

hunkyjohn: Strict Muslims are forbidden to eat bush meat from animals such as monkeys and pigs,

manny4life: Um it is because it's either you're active or dormant, risk taker or not (you'd prefer the status quo which in this case is $1million.

As for your second question, I have no damn clue what you're talking

manny4life: Right now, there's 17 Red's and 12 Green

So it mean that 59% of people will rather stick with their status quo while 41% wanna take the chance and make it

topmostg: Math gurus pls solve dis 4 me.
Resolve to partial fractions. 2x^3-2x^2-2x-7/x^2-x-2.
Couldnt attempt it cos the numerator is more than the denominator. Shed more lite pls. Bless u.

cigie: Summation of (4*10^(n-1) + 4)
Abi?

solomon111: the answer obeyed the equation.
X+y=5
2+3=5.
X^x+y^y=31
2^2+3^3=31
(equation proved)

solomon111: That only applies when (x+y) is acting as a single variable,hence the bracket.
In the question,x and y are different variables.

solomon111: The fifth equation follows the principle/laws of logarithm.
E.g
1)logx +logy =logxy
2)alogx +blogy=ablogxy.
3)logx-logy=logx/logy

solomon111: The fifth equation follows the principle/laws of logarithm.
E.g
1)logx +logy =logxy
2)alogx +blogy=ablogxy.
3)logx-logy=logx/logy

Youngsage: x + y =5 -------- eqn i.
x^x + y^y=31 ----- eqn ii.
From equatns i & ii, take the log of both sides
(xlog^x + ylog^y) = log 31------ eqn iii.
logx + logy = log 5 ------------ eqn iv.
xylogxy= log 31 -------- eqn v.
log xy = log 5 --------- eqn vi.
(Using elimination method);
xylog5 = log31
xy = log 31/log 5 =6.2 approx. 6.

Recall, from eqn i, x + y = 5.
So x = 6/y or y = 6/x.
Therefore x=2 when y=3.
ans: x=2, and y=3.