500samuel:
2^2x=8x
expand 2^2x will be 4x(square)
4x(square) =8x
divide both side by 4x
4x(square)/4x=8x/4x
x=2

Wrong!

Adehorze:
2^2x=8x
Taking log of both sides,
Log2^2x=Log8x
2xLog2=Log8+Logx
2xLog2=Log2^3+Logx
2xLog2=3Log2+Logx
2xLog2-3Log2=Logx
(2x-3)Log2=Logx
Equating d log of both sides,
>>
(2x-3)2=x
4x-6 =x
4x-x=6
3x=6
Dividing both sides by 3
3x/3=6/3
x=2

Very close but ur finishing [4rm where u quoted (2x-3)2=x] is not in conformity with mathematical laws.

The answer is 4x^2.

ETHENE TELL THEM. WHAT IS GENERAL NAME OF ETHENE

Mekyno:

gr8.....tnk God n ur parents 4 me

he tried, but what he did in the step where he removed the log was mathematically wrong

prideofscience:
ETHENE TELL THEM. WHAT IS GENERAL NAME OF ETHENE

I guess u meant to ask "what family does Ethene belongs to?" If that's what u meant to ask, Ethene belongs to the family of Alkenes.

ethene:

I guess u meant to ask "what family does Ethene belongs to?" If that's what u meant to ask, Ethene belongs to the family of Alkenes.

he asked for general name of ethene. its acetylene.

2^2x=8
(2^x)^2=2^3
2x=3
X=3/2

2^2x= 8x 2x*2x=4x 4x=8x divide both side by 4x 4x/4x=8x/4x 1 2x replace x with 2x in the left hand equation 2^2(2x) 2^4x bring down 4x 2*1/4x cross multiply 2*4x= 8x • • • 8x=8x. Rate me . Thanks.

bchi:
2^2x= 8x 2x*2x=4x 4x=8x

The bolded is wrong. Consequently anything that comes after is wrong.

Prinzofparis:

he asked for general name of ethene. its acetylene.

I wonder when acetylene became the general name for ethene? Acetylene is an old name for ethyne(not even ethene). Like I said if by general name u mean family name then it is 'Alkene'; so u see! Don't be too quick to arrogantly correct what u don't know.

chipretty48:
2^2x=8 2^2x=2x2x2 2^2x=2^3 when u cancel both 2 in the bracket, you have: 2x=3 divide both sides by 2 2x/2=3/2 x=3/2

it's wrong bro. where did u drop the x?

ethene:

I wonder when acetylene became the general name for ethene? Acetylene is an old name for ethyne(not even ethene). Like I said if by general name u mean family name then it is 'Alkene'; so u see! Don't be too quick to arrogantly correct what u don't know.

my bad,.....ethylene(general or common name) is ethene(IUPAC) and ethyne(IUPAC) is acetylene(general or common name).
Besides, there was no arrogance in my earlier post.

There is also a big difference between family name or homologous series and general or common name.


nairaland remains an avenue for learning.

enjoy

Mature reply.....

Prinzofparis:

my bad,.....ethylene(general or common name) is ethene(IUPAC) and ethyne(IUPAC) is acetylene(general or common name).
Besides, there was no arrogance in my earlier post.

There is also a big difference between family name or homologous series and general or common name.


nairaland remains an avenue for learning.

enjoy

singlefade25:
Mature reply.....

lol

chiv:
Just got the answer
2^2x=8x
2^2(x)=8x
4^x=8x........eqn(1)
2^2x=8x
2^2x=(2^3)x
Divide both sides by 2^3
x=2^(2x-3)........eqn(2)
Substitute 2^2(2x-3) for x in eqn(1)
4^(2^(2x-3))=8(2^(2x-3))
16^(2x-3)=2^3(2^(2x-3))
2^4(2x-3)=2^3(2^(2x-3))
2^4(2x-3)=2^3(2^2x)/2^3
2^4(2x-3)=2^2x
Equate the powers of 2 on both sides
4(2x-3)=2x
8x-12=2x
-12=2x-8x
-12=-6x
x=2

Here is your solution in writing, it makes these errors more obvious:
1. Making x a solution of itself in x=2^(2x-3)
2. Opening an outer bracket before the inner bracket to get 16^(2x-3)

I agree with AK461, it's trial and error
Or if you can do the wahala, equate each side to 0 and solve simultaneously.


Cc @ Neyozak

I hope I'm right.

So who now get hired ooo OP.

Prinzofparis:
.

Long time no see in the chatroom

I love Maths; I'm glad I stumbled on this thread.

Hmmm.... I'm impressed . You guys demonstrated quite a number of mathematical skills. But I'm afraid, you aren't getting it right . And of course you can easily guess the answer . Let it be known that you can't use an analytical approach to accurately solve such exponential equation . Rather, you make use of the graphical approach .
The question is this; how do you use the graphical approach?
step 1: Draw the graph of y = 2^(2x)
step 2: Draw the graph of y = 8x
The x-coordinate of the point of intersection of the two graphs will give you the solution to the exponential equation. In this case, you will obtain x = 2.
Hasta luego

Neyozak, where's my offer letter?

Luke1001:
I love Maths; I'm glad I stumbled on this thread.

Hmmm.... I'm impressed . You guys demonstrated quite a number of mathematical skills. But I'm afraid, you aren't getting it right . And of course you can easily guess the answer . Let it be known that you can't use an analytical approach to accurately solve such exponential equation . Rather, you make use of the graphical approach .
The question is this; how do you use the graphical approach?
step 1: Draw the graph of y = 2^(2x)
step 2: Draw the graph of y = 8x
The x-coordinate of the point of intersection of the two graphs will give you the solution to the exponential equation. In this case, you will obtain x = 2.
Hasta luego

Neyozak, where's my offer letter?

Yes, the answer is 2. But show example or I don't believe you.

naanxie:

Long time no see in the chatroom

hey babes, don't mind my big head.
how is you?

Prinzofparis:

hey babes, don't mind my big head.
how is you?

I'm chilling. You?

You should pop in there more often.

naanxie:

I'm chilling. You?

You should pop in there more often.

will try..thanks for checking up on me.
bbm?

naanxie:

I'm chilling. You?

You should pop in there more often.

will try..thanks for checking up on me.
bbm?

Prinzofparis:

will try..thanks for checking up on me.
bbm?

Pls send a pm.

naanxie:

Pls send a pm.

My mail is acting up

Neyozak:
2raised to power 2x = 8x

Simplifying
2x2 + 8x = 0

Reorder the terms:
8x + 2x2 = 0

Solving
8x + 2x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x'.
2x(4 + x) = 0

Ignore the factor 2.
Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0
Subproblem 2
Set the factor '(4 + x)' equal to zero and attempt to solve:

Simplifying
4 + x = 0

Solving
4 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + x = 0 + -4

Combine like terms: 4 + -4 = 0
0 + x = 0 + -4
x = 0 + -4

Combine like terms: 0 + -4 = -4
x = -4

Simplifying
x = -4
Solution
x = {0, -4}

Thank You

Prinzofparis:


My mail is acting up

.

naanxie:



It'll be my siggy at 7am tomorrow, will take it down 7:05am.



Quote if u copy

lol...just add up
pls don't quote

Prinzofparis:

lol...just add up ... pls don't quote

X=0