Neyozak:
2raised to power 2x = 8x

Mrshape:

Have this been solved?

chipretty48:
2^2x=8
2^2x=2x2x2
2^2x=2^3
when u cancel both 2 in the bracket, you have:
2x=3
divide both sides by 2
2x/2=3/2
x=3/2

flossy007:
2^ 2x = 8x

Log100 ^2x = 8x ( log to base 10)

100^2x = 10^8x

(10^2) ^ 2x = 10^8x

(2x)^2 = 8x

4x^2 = 8x

X^2 = 2x

X = 2

Hope I got it

clementnoble22:

Guy recheck ur question... I think this question is wrong.
2^2x=8x ---> Wrong
2^2x=8---> Right
Solution
2^2x=2^3
2x=3
x= 3/2

dejt4u:

2^2x=8x,

2^2x=2^3(x),

(2^2x) / (2^3) = x,

2^(2x-3)=x,

2^(2x-3)/4^(2x-3)=x/4^(2x-3),

(1/2)^(2x-3)=x*(1/4)^(2x-3),

(0.5)^(2x-3)=x*(0.25)^(2x-3),

(1-0.5)^(2x-3)=x*(1-0.75)^(2x-3),

by binomial approx.

1-(2x-3)*0.5...=

x*[1-(2x-3)*0.75+...]

re-arrangin gives;

1-x+3/2=x-3x/4*(2x-3) = 4-4x+6=4x-6x^2+9x

or

6x^2-17x+6=0,

x=2.4 or - 0.42

Reference to laplacian of nairaland maths clinic

Alvanify:
2x^2=8x
soln
divide thru by x
2x^2/x=8x/x
therefore, 2x=8
x=4ans

Softhands:
2^2x =8x..
take the equation and make it equal to zero
2^2x-8x=0
introduce differentiation,
dy/da ( 2^2x-8x)
4x^(2x-1) - 8 =0
4x^(2x-1)=8
2 X 2^ (2x-1) = 2^3
2x-1=3
2x=3 +1; 2x=4,
x=4/2= 2
Wrong

final ans , x=2

Danke.

INCREDIBLEGUY:
2^ 2x = 8x
Log100 ^2x = 8x ( 1*1=11+2+2 =22+1000000+10000000000 =2223556777777777777

Goalnaldo:
I would like to see your answer.

Hausa:
Wow. Interesting. I don't even know how I stumbled upon this, lol.
Please, for the fun of it, I would love to share this question to some of my whatsapp groups, and reward them for answering with complete steps.
Me, I no sabi maths o, but just a way to while away time in the covid-19 lockdown. I really think this would be fun.

Now, it is already established that the answer = 2.
But which of these people got it right and got the workings correctly?
I no wan make person start dey ask me question wey I no go fit answer.
Also, which set of school-level can answer this, and how much in airtime should the minimum reward be?
I no wan make person give me the answer in two minutes, lol. Make dem sweat small.

Thanks.

Cc:
Mrshape
Neyozak

Mrshape:


No university student unless he studied maths in the university can provide answer to that let alone a secondary school child.

Another set of people that can answer it are people that have mathematicians as friends and interact in mathematics daily( that's were I belong) similar questions before

The reason why they can't answer it is product log function which is also called Lambert w. Is only in the mathematics curriculum of some mathematics courses in the university.


So you can put #10000 or more depending on your pocket,

Tell them the answer is 2 they should form a numerical solution to it and explain each step.

Bet you no one will be able to answer it.

Then you will credit me they #5,000 inside you take #5,000. 50/50.


My solution is correct, use that as a template.
Tell them not to use graphing. ONLY NUMERICAL SOLUTION

Geophilip:


speak for yourself, I can solve it, if he promise to reward me,
note: I didn't study mathematics.

Geophilip:


speak for yourself, I can solve it, if he promise to reward me,
note: I didn't study mathematics.

macjurek:
2^2x=8x --->
Solution
2^2x=2^3x
NOTE THE X IS NOT A POWER ON THE LEFT HAND SIDE YOU AUTOMATICALLY TURNED IT YO A POWER THATS WERE YOU FAILED IT
2x=3x
Divide both sides by 2 or Divide both sides by 3
x= 3/2 or x =2/3

Thanks

Mrshape:

You might be in the category of the second class of people I mentioned.

Are you going to solve it with what you learn in the university or secondary school procedure,
If yes bring the numerical solution and I will show you your error.

I repeat again the method of solving this kind of equation numerically is only find in university mathematics student's curriculum in some schools.

I will like you to prove me wrong so that I will learn from you and change my perspective.

Bring numerical solution not approximate Newton Raphsson or hucus pacus. Nor graphical method,

Geophilip:
the person that asked the question didn't categorically say which method we are excepted to use, by the way I planned used any of the approximate method
Newton Raphson
Runge Kutta
or
do
trial methods
as far as the answer is correct and prove to be correct issues no de

Mrshape:


No university student unless he studied maths in the university can provide answer to that let alone a secondary school child.

Another set of people that can answer it are people that have mathematicians as friends and interact in mathematics daily( that's were I belong) similar questions before

The reason why they can't answer it is product log function which is also called Lambert w. Is only in the mathematics curriculum of some mathematics courses in the university.


So you can put #10000 or more depending on your pocket,

Tell them the answer is 2 they should form a numerical solution to it and explain each step.

Bet you no one will be able to answer it.

Then you will credit me they #5,000 inside you take #5,000. 50/50.


My solution is correct, use that as a template.
Tell them not to use graphing. ONLY NUMERICAL SOLUTION

Hausa:
The OP said that chiv seemed to be the only one that got the answer correctly.
I was thinking of using his solution as a guide. What method did the chiv guy use?

Also, your working is on a screenshotted paper. It'd have made more sense if you worked it like others directly.
Also, the original question, is it logarithm or indices?

Mrshape:

My workings is too technical to type with this basic keypad. It will consume my time besides let me see the chiv guys solution I have not seen it yer

chiv:
Just got the answer
2^2x=8x
2^2(x)=8x
4^x=8x........eqn(1)
2^2x=8x
2^2x=(2^3)x
Divide both sides by 2^3
x=2^(2x-3)........eqn(2)
[[[[[[[[Substitute 2^2(2x-3) for x in eqn(1)]]]]]]]]]
THE ENCLOSED SUBSTITUTE IS WRONG
YOU ARE SUPPOSED TO SUBSTITUTE
2^(2X-3)
BUT HE SUBSTITUTED 2^2(2X-3) WHICH IS WRONG.


4^(2^(2x-3))=8(2^(2x-3))
16^(2x-3)=2^3(2^(2x-3))
2^4(2x-3)=2^3(2^(2x-3))
2^4(2x-3)=2^3(2^2x)/2^3

2^4(2x-3)=2^2x
Equate the powers of 2 on both sides
4(2x-3)=2x
8x-12=2x
-12=2x-8x
-12=-6x
x=2

Hausa:
Just got the answer
2^2x=8x
2^2(x)=8x
4^x=8x........eqn(1)
2^2x=8x
2^2x=(2^3)x
Divide both sides by 2^3
x=2^(2x-3)........eqn(2)
Substitute 2^2(2x-3) for x in eqn(1)
4^(2^(2x-3))=8(2^(2x-3))
16^(2x-3)=2^3(2^(2x-3))
2^4(2x-3)=2^3(2^(2x-3))
2^4(2x-3)=2^3(2^2x)/2^3
2^4(2x-3)=2^2x
Equate the powers of 2 on both sides
4(2x-3)=2x
8x-12=2x
-12=2x-8x
-12=-6x
x=2

Adehorze:
2^2x=8x
Taking log of both sides,
Log2^2x=Log8x
2xLog2=Log8+Logx
2xLog2=Log2^3+Logx
2xLog2=3Log2+Logx
2xLog2-3Log2=Logx
(2x-3)Log2=Logx
Equating d log of both sides,
>>



[[[[[[[[[[[(2x-3)2=x]]]]]]]]]]
THIS IS WRONG IF YOU TAKE THE e OF BOTH SIDES OR LOG AS YOU SAID
THIS IS HOW OUR WILL BE
2^(2x-3)=x



4x-6=x
4x-x=6
3x=6
Dividing both sides by 3
3x/3=6/3
x=2

ZACHIE:


Yes.
Final amswer++++
OBATALA approved it

darium:
2~2x = 8x
Take log of both sides
Log 2~2x =log 8x
2xlog2 = log8 + log x
2xlog2 = 3log2 + log x
2xlog2 - 3log2 = log x
Log2(2x-3) = log x
Take anti-log of both sides


2(2x-3) = x


WRONG TAKE THE ANTI LOG YOU WILL GET
2^(2X-3)=X


4x - 6 = x
4x - x = 6
3x = 6
X = 2

Neyozak:

So far so good, this is the best approach. Invitation loading.

onlynaija:
My Solution