Education › Re: UI 2018/2019 Admission Thread by Eben331: 12:43pm On Apr 14, 2018 |
Damayogenius18: ...I av college bio(idodo umeh)already..av read it once BT didn't really exploit it...dat's wat I wanna do now.... Ok bro. God will crown our efforts with success. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 12:42pm On Apr 14, 2018 |
Damayogenius18: ...some medical aspirant are using more than six self...if you are going for med...they are choosing at most 120 from up to 800 extremely brilliant student... You av to go extra mile... You are right but what matters most is the God factor and prayer. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 12:28pm On Apr 14, 2018 |
Damayogenius18: ...its gud BT ppl hype it a lot....it expose you to a lot of question BT does not give u the fundamental knowkedge u need...exam Focus is the opposite.. It cram a lot of information into small page BT gives few questions...u will be OK,if u can use both... I will like to buy both bt because of finance, i will go for explicit. i already have modern bio. College Bio is gud, u can go for it. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 12:16pm On Apr 14, 2018 |
Damayogenius18: ...Oh,I saw something related to medicine in is post.......PS: I use many bio textbook..modern,essential,comprehensive,explicit,exam focus...wanna try idodo umeh soon... chai!! about 6 textbooks on biology alone. How is Explicit Biology? |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 12:04pm On Apr 14, 2018 |
Damayogenius18: ...symbol of surface tension is Sigma..I cant get the symbol on my fone..as I don't have teta symbol also...also let's appreciate doc Samuel for also helpinh us..he does not av to but he came back to help we aspirant.. yeah bro. I really appreciate his efforts. I thought he is an engineer to be. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 11:47am On Apr 14, 2018 |
Damayogenius18: ...in circular motion angular velocity w = teta/t.. Teta is angule turn by the body in circular motion...angular velocity is the angle turn through per second...unit is radian per second...rads^-1...but for one complete oscillation,the body turn one revolution...teta is then = 2π and t is now the period "T".. So w= 2π/T...1/T =f..w=2πf..shm,we talk of "w" as angular frequency..is revs^-1( rev per second)..we don't talk abt it has angle turn..we talk abt is has frequency of body oscillating...there is no really any diffence BTW angular velocity and angular freqhency just a change of name..the unit is also rads^-1 thanks a bunch. what is the symbol for surface tension? gamma or s. Can we say surface tension=F/2l? I'm sori 4 asking too much questions. PS: Which bio txtbook do u use bro? |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 11:15am On Apr 14, 2018 |
Damayogenius18: ...doc,there is formula for surface tension....is force per unit length acting on the surface of the liquid....F/l...MLT^-2/L...MT^-2.... Force can be generally group into pull or push...tension, thrust...e.t.c are forces..Tension has many formula depending on the question but let's use this...T= mv^2/ r + mg..T=ma + mg...MLT^-2 + MLT^-2...T =MLT^-2.... Thanks bro, I knw there must be a formula for tension. Elucidate on angular frequency. What is the symbol of surface tension? |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 10:52am On Apr 14, 2018 |
samuelizz: It doesn't really have a particular formula tho.
it is advisable that when solving for angular velocity, the unit should always be in rad/s.
just know that 1rev/s equals 2πrad/s Thanks boss. The thing is complicated then. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 10:48am On Apr 14, 2018 |
samuelizz: surface tension = Force/length.
Tension has no particular formula. it is always derived when solving questions especially in mechanics how can tension be derived in mechanics? Which physics textbook do u use? I am sorry for asking too much questions. Thanks. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 10:46am On Apr 14, 2018 |
Samsonyte: sory boss, datz no2 question is 27^(1 + x) and that no1 wat is get is different frm urs, i have x + 5 rem -12 Boss ke. I'm ur boy o. You can ascertain whether the ans is A or C by checking using dis formula: dividend=divisor*quotient+remainder. Question 2 ans is D(-1/3) |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 10:39am On Apr 14, 2018 |
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Education › Re: UI 2018/2019 Admission Thread by Eben331: 9:56am On Apr 14, 2018 |
samuelizz: when angular velocity is measured in rev/s (revolution per sec), it can also be called Angular Frequency but when it is measured in rad/s, it is strictly called angular velocity. bro, pls write the formula for angular velocity when it is measured in rev/s. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 9:51am On Apr 14, 2018 |
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Education › Re: UI 2018/2019 Admission Thread by Eben331: 9:49am On Apr 14, 2018 |
Samsonyte: Divide the expression x³ + 7x² -
x - 7 by 1 + x²
A x + 7 rem -2x - 14
B x - 7 rem x - 14
C x + 5 rem -2x - 10
D x - 5 rem x - 10
Given that 27 (1 + x) = 9, find x
A 1/3
B 1/6
C -1/6
D -1/3 (1) A (2) no ans in the option but it should be -2/3 |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 9:39am On Apr 14, 2018 |
samuelizz: The unit of surface tension is Nm-¹
where N is newton , and m is metre
Newton is the unit of a force, F, and F = m × a
where a is the acceleration and m is the mass
F = kg × ms-² = kgms-²
That is, newton equals kgms-²
Nm-¹ = kgms-² × m-¹
= kgs-²
which in dimension gives, MT-².
The unit of tension is the same as the unit of force which Newton = kgms-²
in dimension, that is , MLT-² Thanks bro, pls write d formula for both surface tension and tension out. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 9:35am On Apr 14, 2018 |
samuelizz: when angular velocity is measured in rev/s (revolution per sec), it can also be called Angular Frequency but when it is measured in rad/s, it is strictly called angular velocity. Thanks bro. I understand now. Would you mind if I ask the physics textbook you use? |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 10:25pm On Apr 13, 2018 |
fksymbol: everyone, including farmers, yahoo guys and children. O. K lmao |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 10:19pm On Apr 13, 2018 |
Pls House! What is the formula and dimension of surface tension and tension? Explanations will be appreciated. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 10:16pm On Apr 13, 2018 |
Damayogenius18: ...angular frequency and angular velocity can be use interchangeably...in circular motion it is called angular velocity but in shm,it is angular frequency....they are both w which is equal to 2πf....but strictly for angular momentumn,I should called it angular velocity....thanks for pointing it out.. But even in shm, it is called angular velocity. I have never heard of angular frequency b4. We keep on learning sha. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 10:11pm On Apr 13, 2018 |
boyejo124: boss could you make this explicit cause the answer I got is quite different regarding the powers of the answer,am getting mine in powers of four, for 22°c I got 1.36"10^4…
and at 100°c 1.38*10^4 Boss ke. I am your boy o. From V2=V1(1+gamma*change in tita) V2/V1=1+gamma*change in tita---eqn (i) Know dat volume is inversely proportional to density, we can say dat d=M/V where M is mass which is a constant. M=dV d1V1=d2V2 V2/V1=d1/d2 Substitute for eqn(i): 1+gamma*change in tita=d1/d2 d1=d2(1+gamma*change in tita) You can use d1 to rep density of mercury at 0degree celsius and d2 to rep density of mercury at 100 degrees celsius and at 22 degrees celsius. SOLUTION: By making d2 the subject of formula: d2=d1/1+gamma+change in tita d2 at 100^oC=1.36*10^2/1+180*10^-6*100=136/1.018=1.33*10^2kg/m3 d2 at 22^oC=1.36*10^2/1+180*10^-6*22=136/1.00396=1.35*10^2kg/m3. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 9:49pm On Apr 13, 2018 |
Mirabel2032: pls does ui accepts two sittings Yeah, for all faculties except college of medicine. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 9:47pm On Apr 13, 2018 |
coolxpaul: What are my chances of getting MBBS at ui. Utme 334 and am 4rm Delta state. Is there going to be issues since am not 4rm Southwest? What are deir catchment areas? All the 36 States are UI catchment area. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 9:43pm On Apr 13, 2018 |
Damayogenius18: Guys...this issue abt O' level result upload... Av not uploaded my O level result which I did in 2015..when I filled the form I used awaiting result cos DAT day,I was not with my o level result..after jamb,I went for the upload and was told that there wasn't network...since then,I did not go...now, I heared that if u don't upload ur result and you used awaiting,even if one pass post utme,jamb won't give one admission at all...that the Caps system will sieve one...a guy said her sister experience that last yr...am really confuse...don't know wat to do...jamb said 20% that wrote jamb are SS2 student... I think that jamb has consider me as SS2 student....pls i need anybody to comment...don't wan2 waste my scores o... don't wait till August, you can upload it nw since coc/coi and correction is still going on. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 9:40pm On Apr 13, 2018 |
Damayogenius18: ..thrust is reaction force...formula is...rate of mass flow * velocity.... m/t * v.....angular momentum can be "mvr".. Remember L= Iw...=mr^2 * w.....but w= v/r...so L=mr^2 * v/r....=mr^2v/ r....= mrv.... PS...sori bro...I will l8ta Thanks for the clarification boss...m/t*v is just the same as ma...is w angular frequency or angular velocity? |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 11:29pm On Apr 12, 2018 |
Damayogenius18: ...Thrust is the same thing as force..dimension of force is MLT^-2....energy density= energy per unit volume....=ML^2T^-2/L^3...=ML^-1T^-2......angular momentum rep by L...L= Iw.. I= moment of inertia and w= angular frequency...I= mr^2 while w= 2πf...so L= mr^2(2πf)....2π is dimensionless...L= kgm^2/s unit...so dimension of L=ML^2T^-1....hope I try small... You try pass small...Thanks bro...I knw dat thrust is the same as force bt pls show its formula. I think we can also say that angular momentum=mvr Am I wrong? P.S: You haven't pm me yet via my mail. |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 10:07pm On Apr 12, 2018 |
Aceed: I know say e simple for una me still dey learn...
A body of mass 25kg, moving at 3ms¹ on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. Calculate the coefficient of sliding friction [g=10ms²]
The density of mercury is 1.36×10⁴kgm³ at 0°C. Calculate its value at 100°C and at 22°C. Take cubic expansivity of mercury as equal to 180×10^–6 K-¹.
A brass measuring tape is correct at 20°C. The value obtained when the length of a field is measured with the rule at 50°C appears to be 70.5m. What is the true length of the field? Linear expansivity of brass = 1.8×10^-5 K-¹.
PLEASE SHOW WORKINGS (3) density of mercury at 100 degrees celsius=1.33*10^2kgm^3 and density of mercury at 22 degrees celsius=1.35*10^2kgm^3 |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 9:20pm On Apr 12, 2018 |
Pls help me out with this. What is the formula and dimension of Thrust, Energy density and Angular momentum? |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 8:54pm On Apr 12, 2018 |
Aceed: I know say e simple for una me still dey learn...
A body of mass 25kg, moving at 3ms¹ on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. Calculate the coefficient of sliding friction [g=10ms²]
The density of mercury is 1.36×10⁴kgm³ at 0°C. Calculate its value at 100°C and at 22°C. Take cubic expansivity of mercury as equal to 180×10^–6 K-¹.
A brass measuring tape is correct at 20°C. The value obtained when the length of a field is measured with the rule at 50°C appears to be 70.5m. What is the true length of the field? Linear expansivity of brass = 1.8×10^-5 K-¹.
PLEASE SHOW WORKINGS (3) alpha=l2-l1/l1(t2-t1) where t=temperature 1.8*10^-5=70.5-l1/l1(50-20) 1.8*10^-5=70.5-l1/l1*30 1.8*30*10^-5*l1=70.5-l1 0.00054*l1=70.5-l1 0.00054l1+l1=70.5 1.00054l1=70.5 l1=70.5/1.00054 l1=70.46m True length=70.46m |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 8:43pm On Apr 12, 2018 |
Aceed: I know say e simple for una me still dey learn...
A body of mass 25kg, moving at 3ms¹ on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. Calculate the coefficient of sliding friction [g=10ms²]
The density of mercury is 1.36×10⁴kgm³ at 0°C. Calculate its value at 100°C and at 22°C. Take cubic expansivity of mercury as equal to 180×10^–6 K-¹.
A brass measuring tape is correct at 20°C. The value obtained when the length of a field is measured with the rule at 50°C appears to be 70.5m. What is the true length of the field? Linear expansivity of brass = 1.8×10^-5 K-¹.
PLEASE SHOW WORKINGS (1) m=25kg, u=3m/s, v=0m/s, s=2.5m, a=? using v^2=u^2+2as 0=3^2+2*a*2.5 0=9+5a 5a=-9 a=-9/5 a=-1.8m/s^2 Deceleration=1.8m/s^2sliding force=25*1.8=45N Recall:F=mu*R F=mu*m*g mu=F/mg mu=45/25*10 mu=45/250 mu=0.18 (no unit) |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 5:48pm On Apr 12, 2018 |
Aceed: I know say e simple for una me still dey learn...
A body of mass 25kg, moving at 3ms¹ on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. Calculate the coefficient of sliding friction [g=10ms²]
The density of mercury is 1.36×10⁴kgm³ at 0°C. Calculate its value at 100°C and at 22°C. Take cubic expansivity of mercury as equal to 180×10^–6 K-¹.
A brass measuring tape is correct at 20°C. The value obtained when the length of a field is measured with the rule at 50°C appears to be 70.5m. What is the true length of the field? Linear expansivity of brass = 1.8×10^-5 K-¹.
PLEASE SHOW WORKINGS (1) 0.18 (2) I dont know what you use the symbol 'box' to represent. Try to use dis formula: d1=d2(1+gamma*tita) use d1 to represent density of mercury at 0 degree celsius, d2 to rep density of mercury at 22 and 100 degrees celsius, where gamma=cubic expansivity (3) 70.46m |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 5:43pm On Apr 12, 2018 |
Aceed: Omo na so I see the question ooo...
no box Look at question 2, the density of mercury is what? |
Education › Re: UI 2018/2019 Admission Thread by Eben331: 5:28pm On Apr 12, 2018 |
Aceed: I know say e simple for una me still dey learn...
A body of mass 25kg, moving at 3ms¹ on a rough horizontal floor is brought to rest after sliding through a distance of 2.5m on the floor. Calculate the coefficient of sliding friction [g=10ms²]
The density of mercury is 1.36×10⁴kgm³ at 0°C. Calculate its value at 100°C and at 22°C. Take cubic expansivity of mercury as equal to 180×10^–6 K-¹.
A brass measuring tape is correct at 20°C. The value obtained when the length of a field is measured with the rule at 50°C appears to be 70.5m. What is the true length of the field? Linear expansivity of brass = 1.8×10^-5 K-¹.
PLEASE SHOW WORKINGS In question 2, what does the box represent? |