₦airaland Forum

dolapo74:
Please ,where did get this questions from?

is dat important?

Gracy3535:
dat ansa was 4 the hint u gave me

but image distance is supposed to be in cm or m, you mistake ve for velocity. The ans is not correct ooo

Gracy3535:
when u r through wit them come and collect ur cane

That's true. He needs it. Lol

Hardebaryor:
1. K.E= mv²/2. P.E=Mgh
But P.E=K.E. Hence K.E=mgh
Loss in K.E = mg(H-h) = 1×9.8(5-1) =9.8×4 =39.2J Not really sure of this answer
2. Landa(wavelength)= h/mv v=h/landa×velocity v=6.6×10^–34/9.4×10^–31× 1.3×10^–10 v=5.4×10^6m/s 3. Hmm.. I no know am

big ups to u bro.

Gracy3535:
i got 30m/s. Pls about dat oscillation wat z d formular u use

I first used h=l(1-costita) and later use v=_/2gh I dnt knw weda it is correct. Can u show how u got 30m/s?

Damayogenius18:
...OK bro...only back to solve ur ques

If you leave us like dat next time, you will be sued...lol. Welcome back. You haven't show us the corrections to ur questions.

Gracy3535:
am i correct for the 3answers

Hint: First find vo(image of objective lens) nd ur new u will be vo, then find ve which is the final image.

Gracy3535:
1.V^2=2gh v^2=2*9.8*1 v^2={19.6} v=4.4m/s kE=1/2mv^2 kE=1/2*1*4.4^2 KE=9.68 2.V=Freq*Wavelength v=3.0*10^-8*1.3*10-10 v=3.0*1.3*10^-8-10 v=3.9*10-18 3. 1/f=1/u+1/v 1/5=1/2+1/v 1/v=1/5_1/2 1/v=2-5/10 1/v=-3/10 v=3.3cm

All is wrong.

Hardebaryor:
For the first 200km, the time spent is
200÷44=4.54hrs

For the next 220km, the average speed is 220/9-4.54hrs
This is because the total time spent is 9hrs
220/4.45 =49.43km/hr. Am I right?

You are correct

vicstiqs95:
A simple pendulum oscillate with an amplitude of 30° if the length of the string is 1.0m. calculate the velocity of the pendulum Bob at its lowest point.

I got 3.83m/s.

Gracy3535:
200=44
220=x
200x=9680
x=48.4km
which is correct

both are wrong. let give others the chance to solve, if nobody can't solve it, i will do the correction. Try the other questions.

Gracy3535:
Average speed = total distance /time =200 + 220/9 =420/9 =46.6km am i correct

wrong

vicstiqs95:
the car drives 200km initially and drives 220km in addition. 200km+220km= 420km.
total time=9hr
average speed= 420km÷9hr= 46.6km/hr.

wrong

1 A ball of mass 1kg is dropped from a height of 5m onto a floor and rebounds to a height of 1m. Find the loss of kinetic energy due to impact. (g=9.8m/s2) 2 An electron of mass 9.4*10^-31kg has a wavelength of 1.3*10^-10m. Calculate the velocity of the electron. (h=6.6*10^-34Js) 3 A compound microscope, with lenses of focal lengths of 3cm and 5cm for the objective and eyepiece respectively, has an object placed 2cm from the objective lens. If the first image formed 3cm from the eyepiece lens, calculate the distance of the final image from the eyepiece. Happy Weekend Bosses.

A man drives a car a distance of 200km at an average speed of 44km/h. What must be his average speed for the next 220km if he is to cover the total distance in 9 hours?

Damayogenius18:
Whenever I solve question which I consider little bit technical,I post it so DAT u guys can learn by trying to solve it.....b4,u guys wld atleast try to solve it bt now,I guess d enthusiasm as faded..our ogas are d one solving...m sure some days or a week to the exam,the thread will b lively...I will b back then...thanks guys...

We have to keep this thread active and lively, it must not be dormant like this. Everyone should visit dis thread often. It is nt dat our enthusiasm has faded.

Damayogenius18:
Whenever I solve question which I consider little bit technical,I post it so DAT u guys can learn by trying to solve it.....b4,u guys wld atleast try to solve it bt now,I guess d enthusiasm as faded..our ogas are d one solving...m sure some days or a week to the exam,the thread will b lively...I will b back then...thanks guys...

come back bro

Pls is oou putme cbt or ppt? what are the subject combinations to write in her putme? what is the time duration? how many questions? I need answers to dis questions. Thanks in anticipation.

Damayogenius18:
...nice try bro...will solve it 2moro..got low bar now...m sure it wld av been solve by bosses b4 2moro...gud 9t bro...

I will like if u can give many examples as you can on surface tension calculation because i dnt knw its calculations. Good nyt bro.

psycho261:
looking at the new calendar I think post utme will be early this year last year's was affected by Nasu strike or what do think guys

Maybe

Damayogenius18:
M sori guys..today was just somehow...here is a question...A light square wire frame each side is of which is 10cm long held vertically in water in with one side touching the water surface...find the additional force necessary to pull the frame clear the water...(T= 0.07).. A..0.3N..B 0.015N C..0.04N..D0.4N
2..A thin wire is bent in the form of rectangle of length 4m and breadth 3m...what force due to surface tension does the side experience when a soap film is formed in the frame( ST of soap = 0.03N/m)...A..0.107...B...0.0026..C..0.0084...D..0.023..

1 C(0.04m) 2 D(0.023N) Dnt knw weda dey are correct.

Damayogenius18:
..not D...but will luv to see ur workings..

We can say dat surface tension=surface energy/area=Fd/A where let surface tension=T... since we av four sides d=4l... Surface Tension=F*4l/A. Making F subject of formula: F=TA/4l F=0.03*4*3/4*4=0.36/16=0.0225N approx 0.023N note: l=length. I dnt knw weda it is correct. I will need d correction of it.

Damayogenius18:
..not D...but will luv to see ur workings..

which option did they pick?

Damayogenius18:
...no bro...u don't attempt the question bro..

I will try bro. What did u use T to rep? As for question 2, i will pick D.

Xandre:
Please how much do they sell that Explicit Biology?

#1500

Damayogenius18:
...use both lamlad and science physics...don't say you can't get it or its not in ur side..do everything possible to get it...u can just use ur essential as reference...if you can get new school, u shld too...BT try and get science physics and lamlad physics..there is a phy book I still want u to get BT will send DAT to u 2ru mail...

pls guy, do u av any phy txtbook in pdf?

Ajet001:
If Pico = 10-¹² then Femto =? (a) 10-¹³ (b) 10-¹¹ (c) 10-¹5 (d) 10-¹4

C(10^-15)

thanks boss hope to expect more[quote author=samuelizz post=66709974]*PROJECTILES.*
I'm sure we are all familiar with the topic projectile.. But let's assume you don't know, now , what is projectile ?
Well, *projectile is the launching of a body into space which is under the influence of gravity.
From that definition, it can be said that , when dealing with the topic projectile, we are going to be dealing with *g* (acceleration due to gravity) a lo
Projectile is a 2 - dimensional motion, that is , it consists of the x , y components... Are you confused??... Just be calm, you will understand soo
The x components is always the horizontal components , in a better understanding, the component parallel to the ground while the y components is always the vertical component i.e it is always perpendicular to the ground. ...


y.
| /
| /
| /
| /
|/___________y
Now, you have an idea of what I've been saying
Let's say a body was projected with a velocity *U* and it makes an angle *B* wi

Damayogenius18:
...great sis....as simple as it is,I missed it...why? 2.2^ 2 for my mind is 8...dat's too know...

lol

samuelizz:
You can use lamlad, it is a very good text.

Thanks boss.

Damayogenius18:
...I remember av seen this formula b4 somewhere in maybe essential physics or new science...The formula for surface tension is force per unit effective length. F/ d..BT if the liquid has two film side base on the shape of the container...d= 2l....so surface tension will then equal F/2l..lemme use water as an example..a needle drop in a water experience total surface tension of F/d..but the water is exerting tension on two edge of the needle..the surface tension exerted at each edge is F/ 2l BT the total surface tension is F/2l + F/2l = F/ l...the formula u used is based on the length given to you..

Thanks Man

Damayogenius18:
The UI practise ques looks very simple bt technical esp phy ..Guy' s let's start solving it..u can post it if u don't understand the answer choosen( some of them are wrong)...

can we say the formula for surface tension=F/2l? i dnt undastand the '2' there.