₦airaland Forum

Strawberry001:
thanks Eben331

DrBESTJC:
Yes...but the formula I discovered does not give the exact value....only the approximate value..

Strawberry001:
Is this thread only for science students?

Strawberry001:
help, please, I need ui past questions. I applied for psychology

Eben331:
(1) A swimmer is capable of swimming at 1.4m/s in still water. (a) how far downstream will be land if he swims directly across a 180m wide river? (b) how long will it take him to reach the other side? (2) A man can row at 6km/hr in still water and wants to cross a river to a position exactly opposite his starting point. If the river is 5km wide and is flowing at 4km/hr eastwards, find the direction in which he must set off in order to accomplish his objective. How long will it take to cross the river?

DrBESTJC:
HOT CHEMISTRY.

Hydrogen Sulphide is prepared at one end of a laboratory. It takes 5 seconds for a student at the other end to smell it. How long will it take to smell sulphur dioxide from the same position?
(A) 5 seconds also.
(B) 2.5 seconds.
(C) 3.6 seconds.
(D) 9.4 seconds.
(E) 2.7 seconds.

Please SHOW FULL WORKINGS!

DrBESTJC:
Volume of the hydrometer when floating in water,V1 = Volume of the weighted bulb + Volume of the cylindrical stem.....
Volume of the wighted bulb = 30cm^3.
Volume of the cylindrical stem = §(pie) * r^2(radius squared) * L1.
.: V1 = 30cm^3 + §r^2h1.
But Cross-sectional area of the cylinder = §r^2 = 1cm^2 (given in the question).
Length of the stem immersed when the hydrometer is floating in water,L1 = 3cm.
.: volume of the hydrometer when floating in water,V1 = 30cm^3 + (1cm^2 * 3cm) = 30cm^3 + 3cm^3 = 33cm^3.

Secondly,

Volume of the hydrometer when floating in the Liquid,V2 = Volume of the weighted bulb + volume of the cylindrical stem....
Volume of the weighted bulb = 30cm^3 ........... and
Volume of the cylindrical stem = §(pie) * r^2(r squared) * L2
.: V2 = 30cm^3 + §r^2L2.
But, cross-sectional area of the cylinder = §r^2 = 1cm^2....

Obakenny01:
And are they taking new students for 2018/2019?

TeflonBlixx:
Density is inversely proportional to height. .

Density of water x height in water = Density of liquid x height in liquid..

Where density of water is 1gcm^3
Height in water is 3cm
Density of liquid is 0.89gcm^3
Height in liquid is unknown

3 x 1 = 0.89 x h

3 = 0.89h

3/0.89 = h

h =3.37cm

Eben331:
A hydrometer has a weighted bulb of volume 30cm^3 and a uniform stem with a cross-sectional area of 1cm^2. When floating in water 3cm of the stem is immersed. What length of this stem will be immersed when the hydrometer floats in a liquid of density 0.89gcm^-3. PLS SHOW FULL WORKINGS! CC: DrBESTJC, TeflonBlixx and others.

Obakenny01:
Does UI still offer Pharmacy?

Nltaliban:
Yes..
Late September or early October if all goes well

Nltaliban:
If you ask me, you stand a good chance in Ui but it's up to you to take the risk.


Think we'll, it's your decision. There's every probably that the time that will be given to you to accept Oou's admission would have elapsed before Ui will conduct postume.

Think well, if you think you're ready to take the challenge and Prove yourself as a champion.

abiolamitodun:
Pls I need help does anyone know if the neco internal certificate for 2015 is ready pls I need ur help

Damayogenius18:
...bro longest tym....u r right
to some extent....polarity is a property of both inter atomic and intermolecular bond... Hydrogen bond is a type of polar bond.... We also permanent dipole which is a polar bond.......we av two type of covalent bond...... Ordinary covalent and dative or coordinate covalent bond...

Aceed:

Calculate the velocity of the wave represented by the following wave equation
y =20sin(60(pie)x - 0.5(pie)x) ,
if all the distances are in metres.

DrBESTJC:
Please Maths gurus here:
How can you solve for the squareroot of 2 or 13 or 2225 without calculator?

emmanuelog090:
i need ui putme past question

TeflonBlixx:
Initial horizontal Velocity= 1, 000m/s. .
Initial vertical velocity = 0..

V^2 = U^2 + 2gh.. .Since a projectile has no initial component in the vertical direction.. U =0. . Vx=Vy= 1000m/s..

1000^2 = 2 x 10 x h

1 x 10^6 = 20h..

h = 50km

b. The time taken

V = U - gt

0 = 1000 - 10t
t = 100s..

c. Instantaneous velocity is velocity at any instant. . U is 0..

V = gt
V = 10 * 20
V = 200m/s

V = gt
V = 10 * 50
V = 500m/s

TeflonBlixx:
Initial horizontal Velocity= 1, 000m/s. .
Initial vertical velocity = 0..

V^2 = U^2 + 2gh.. .Since a projectile has no initial component in the vertical direction.. U =0. . Vx=Vy= 1000m/s..

1000^2 = 2 x 10 x h

1 x 10^6 = 20h..

h = 50km

b. The time taken

V = U - gt

0 = 1000 - 10t
t = 100s..

c. Instantaneous velocity is velocity at any instant. . U is 0..

V = gt
V = 10 * 20
V = 200m/s

V = gt
V = 10 * 50
V = 500m/s

oyejide06:
Pls. Some one should help me with Unibadan past questions @ oyejide06@gmail.com; subject combination: Eng, Bio, Chemistry and physics

oyejide06:
Pls. Some one should help me with Unibadan past questions @ oyejide06@gmail.com; subject combination: Eng, Bio, Chemistry and physics

Aceed:
Na so I see am for answer booklet but how una take dey get am na im I wan know

dannyboii1:
what happens to the voltage...

ChiomaMee:
I got admitted for the 2017/2018 session Sir

Aceed:
Two resistors, 40 ohms each are connected in parallel in a circuit of 1.2A and 12V. Calculate the total energy developed in 5 minutes.


cc TeflonBlixx