₦airaland Forum

shymexx: It isn't about living your life on nl - it's about having fun and checking if people can guess right, or whether the norm always work...

The girl you just met and the subsequent story went against the norm - it'll be fun to gauge more encounters vis-a-vis the norm...

The thing is a gentleman is not really supposed to talk about his dates. It would be pretty douchey of me to date girls then blog about it on Nairaland. And nobody wants to date a douche with loose lips.

[quote author=raynold17 ]what. do u expect to happen when dem niggas look at each others as**s 5 times a day.[/quote]

lmao...you guys are funny

shymexx: Ekt_bear

Bro, we can turn this thread into an interesting thread by making it a "Reality" chirpsing adventure thread...

You just need to change the title to "Girlist Adventures" and we'll update it every week with every new chic we meet and ask Nlers about what they think the next step should be lol...

Haha honestly I'm not trying to live my life on NL

Besides, usually things are pretty straightforward. You meet a chick, she is feeling you, she gives you her #, you hang out and take things from there.

It is only when deviations from this norm happen that I think it important to get some advice.

[quote author=Ileke-IdI]ekt_bear and his problems lol.

Dude sounds so soft and sensitive. I'm beginning to think that all Ekiti men are like this.[/quote]Baby I'm hard as a rock

On a serious note though, I'm a bit introspective...I like to analyze and think about things. Even dating/relationship stuff

Tiwa looks ok still

With that said, what reason has the fg given for changing its mind?

The fg is under no obligation to guarantee the loan.

Lagos may simply have to look for a loan with no fg guarantee and pay higher interest rates as a result.

scary.

very sad.

Not sure what to say here...the boy wanted to save his dog, the father wanted to save his son, the mother her husband and child.

If I were the father I'd probably have done the same thing.

a list I hope to one day be on

let me collection my share of the national cake joor

The term "point of intersection" never showed up in the original post.

The original question asks, "is there a time at which he crosses the same spot?"

Or using math symbols, if you use x(t) to denote his position as a function of time on Monday, and y(t) to denote his position on Tuesday, then the problem can be restated as,
"is there a time T for which x(T)=y(T)?"

1. The two men ONLY came into place because I transformed from the original problem into one of two different men. Do you not get how the two men problem is equivalent to the original? This is the key to the whole matter. So clarify if it doesn't make sense to you.

2. Regarding the intersection of the two men, given that you are told in the original problem that the man uses the same path, necessarily then in the two man problem they must eventually run into each other.

anyway i got to get some work done. talk to you guys later

Well, the hill doesn't have a height of zero.

If you weren't sure whether values of 0 for the height of the hill are alowed, just ask.

And assuming that the hill has height greater than zero, then 9am won't be the answer (again, also assuming no juju or teleportation devices).

The only thing you need to know is that the hill doesn't have height zero.

shymexx: The distance to and from the hill to his house is irrelevant, since it's not defined...

Only the constant(9am) is relevant - that's how mathematical tricks work..

The answer is either 0((his house) or 1(point of entry/exit at the hill)..

And since "9am" is the constant in both "0" and "1", then that should be the answer...

Bros.

Suppose the hill is 1000 miles high. He left his house 9am on Monday. He leaves the top of the hill 9am Tuesday to go back home. Are you really saying that at 9am on Tuesday he is back home? 0 seconds after he decided to leave the top of the hill?

This Ijebu man, unless he has a teleportation device or strong juju will not be able to do that

Sybellah: no but here it was a reading mistakes, but the method was the same

the mistakes were at this level

5= d*(0.25/4) + d*(0.5/2) + d*(0.25/6)

correcting this would be

0.25*d/2 + 0.50*d/4 + 0.25*d/6 = 5

which is the same as this

0.25x/2 + 0.50x/4 + 0.25/6 = 5

no?

You are correct.

shymexx: Ekt

Do you now agree that I got the answer to your puzzle?

no, your answer of 9am is flat out wrong. it doesn't even make any sense, unless the ijebu man has some sort of teleportation device

Sybellah: but this is the same method Shymmex used right?

5= if u multiply the d by every term in the parenthesis...u probably made some algebra mistake

let say x=d

5= d*(0.25/s1) + d*(0.5/s2) + d*(0.25/s3)
5= d*(0.25/4) + d*(0.5/2) + d*(0.25/6)

put it at the same denom 12....u find a similar answer

He stated uphill, level ground, then downhill, then stated level ground, uphill, downhill in the second part. So if you assume the same order like I did and don't read very carefully, you'll use wrong #s.

Ah, you are right.

I didn't read this sentence carefully:
"hey spend one-quarter of the total distance walking uphill, one-half walking on level ground, and one-quarter walking downhill. if their speed is 4mph on level ground, 2 mph uphill, and 6 mph downhill,approximately how far did they walk?"


I assumed that you were using the same ordering when reporting the numbers...didn't notice that you changed it.

None, I believe.

If you let s1 = 4, s2=2, s3=6, and D denote the unknown distance they travel, we need for:

(2pm-9am) = 5 = D*(0.25/s1 + 0.5/s2 + 0.25/s3).

Plugging in and solving, this gives D=14.117. So unless I've made a dumb algebra mistake, then the answer is none.

oyb: what happened? do we now have more street lights than enugu?

op knows exactly what i'm taking about

Rossike is not one of your typical Igbo tribalists, at least from what I have observed. Seems like a straight shooter in that respect (though I could be wrong).

My beef with him his approach to pan-Africanism...but aside from that he seems like a well-meaning fellow.

Goldieluks: Lol@ the daft clicking 'like' as if he/she is not 'Nigerian'

Ektbear I was only been sacarstic. No need to get yourself all worked up.

Peace!

I know you are being sarcastic. My parents are both Nigerian after all, they both take playful shots at me ('ekt_bear when are you going to get a serious girlfriend na?') and I fire right back too

Not worked up at all, we are good

Sybellah: If:
x(t) = t^2, y(t) = 1-t

x(t)=y(t)

t^2=1-t
t^2+t-1=0

t= (-1-sqrt(1+4))/2 impossible since time cannot be negative
t= (-1+sqrt(1+4))/2 = 0.618 ?

Yes ma'am.

You clearly remember your high school mathematics well

Hmm. I'm now intrigued more by you...

Has Ajimobi been sniffing glue?

6 steps forward, half a dozen steps backwards

shymexx: Lmao... Can you provide the intersection point, bro?

1. For the specific choice I gave, yes. But of course, where exactly the point is will depend on his position.
2. Keep in mind that the problem doesn't ask you to provide the intersection point (i.e., where on the hill this event happens). It just asks, "Does there exist such a time?"

Idowuogbo: i tire o..

We Nigerians are very stubborn people I guess

Sometimes a picture speaks more clearly than words do:

https://i49.tinypic.com/29x6xzr.png

The blue line is Monday. The green line is Tuesday.

No matter how you choose the velocities, his position is bound to intersect.

(In this plot I chose x(t) = t, so constant speed on Monday. For Tuesday, y(t) = 1-t^2, so he is accelerating down the hill).

Sybellah: We can try the mathematical approach, sure.

How about we call his position as a function of time on Monday x(t). So:

x(9am)=0 (bottom of hill)
x(whenever he finishes) = 1 (bottom of hill)

Let's use y(t) to denote his position as a function of time on Tuesday. So:

y(9am) = 1
y(whenever he finishes on Tuesday) = 0

So, we are looking for a time T where:

x(T) = y(T)

Or in other words, a time T such that:

x(T)-y(T)= 0

Intuitively, no matter how one reasonably chooses x(t) or y(t), there will always exist a time T for which the above equation is zero....it is impossible for x(t)-y(t) to be -1 for t=9am
and then +1 for some other value t without at some point crossing zero [size=2pt](if you want to get technical, this is something called the intermediate value theorem from calculus. But no need to bother yourself with it, we can solve this problem with just intuitive reasoning )[/size].

For example, I might choose x(t) = t^2, y(t) = 1-t. A little bit of algebra will show you that you can find a value T so that x(T)=y(T). Similarly, for any choices of x(t) and y(t) you'll be able to find a value T.