₦airaland Forum

burafato:
Hello,
pls i want to register my small scale company under coperate affairs;
how do i go about it? help me.

Burafato

Small scale then you need to register a business name.
Visit the nearest CAC office nearest to you.
You are going to obtain some forms you will be required to fill.
Give them your business name for availability.
Once the name you want is available,you will be required to pay for the name.
Then,

Covenant University.

Let me wrap up,

Let Alpha = & and beta = $
Therefore from the equation
X*2 +5x – 2 = 0
We will have a= 1, b = 5, c = -2
Sum of roots, & + $ = b = 5 = 5
a 1

Product of roots &$ = c = -2 = -2
a 1

1. (&*2 + $*2) =[ No factors or maybe it is supposed to be
( & + $ )*2].
If it is (& + $)*2 then (& + $) = 5
Then (& + $)*2 = 5*2 = 25.

2. 1 + 1 = & + $ = 5 = -2.5
& $ &$ -2


3. FROM DIFFERENTIATIONSOLVE Y = (X SQURE + 4) 9X RAISE TO POWER 3 + 4)
Soln

Y = (x*2 + 4) (9x*2 + 4) if I got you right
Let’s go……….
Let (x*2 + 4) = U
And (9x*2 + 4) = V
Therefore Y = UV

If (x*2 + 4) = U ;then du = 2x
dx
And (9x*2 + 4) = V; then dv = 18x
dx

Product rule = dy = Udv / + Vdu
dx dx dx


Putting parameters we have
dy = (x*2 + 4)18x + (9x*2 + 4)2x
dx

Expanding dy = 18x*3 +56x +18x*3 + 8x
dx

dy = 36x*3 + 64x
dx

dy = 4x [9x*2 + 16]
dx

Let me see if I can simplify further.
Ditto!

Why not visit the school to confirm yourself.

I am lurking.

C2H5OH:
use what you have to get what you want. i heard it works like a charm, though i haven't tried it.

simple: apply, fill in stats, write an outstanding personal statement, leave the rest to God.

It works like Real charm no be small.

Dclique:
I knew some1,who knew som1,that knows som1,

There must always be som1 when making progress in life.

pongwa:
i entered the way it should be entered, writ and pass the exams in flyin colours and the cache was God

Shot! Simply the best.Having the G- Factor in all endeavours of life,

Oh Yes!
You only something special to gain admission with a score less than 180.

kool919:
hi nairalanders, i applied 2 study p.admin and scored 178 in the jst concluded
ume. is there any hope of getting admission cos i heared dat the cutt_off mark
is 180. nairalanders should pls reach me on 07032757919 or jim.west92@yahoo.com.

Hi,
Sure there is hope of getting admission in Ksu.Do want to know how?
Do you know anybody there?
Let me know how far you have gone about
securing the admission so that I can advice you.

Cheers.

bilms:
1.SOLVE WITHOUT TABLE: log27 1/2 + log 8 1/2 - log 125 1/2
DIVIDE BY
log 6 - log 5

= 3/2

Soln

log27 1/2 + log 8 1/2 - log 125 1/2/
log6 – log5

log3 3/2 + log2 3/2 – log 5 3/2/
log 6- log5

3/2 log 3 + 3/2 log 2 – 3/2 log 5/
Log 6 – log5

3/2 { log3 + log2 – log5}/
Log6 – log5

3/2 ( log 6 – log5)/
Log6 – log5

= 3/2


2. IF ALPHA AND BETA ARE D ROOTS OF THE EQUATION, X SQUARE + 5X-2=0

THEN FIND THE VALUE OF (I)ALPHA SQUARE+ BETA SQUARE (II) 1/BETA + 1/ALPHA
[quote][/quote]Soln

X*2 +5x – 2 = 0

X*2 + 5x = 2

Add the square of half the quoficient of x to both sides;
This is what you get;

X*2 + [5]*2 + 5x = 2 + (5)*2
(2) (2)


(X + 5)*2 = 2 + 25
2 4

Am I on course?
Busy now to finish it up soon.

Catch ya.

blackspade:
In my class we're going over the pythagorean therom, I'm not totally lost, but I know if I don't do anything now, I'm not going to get an A on the test.

Okay, I know the basics like: a^2 + b^2 = c^2 . . . . but I get confused when I come across a question asking me to find the missing lengths (eg. solve for x), or even worse, the word problems.

Are there any good mathematicians who can help me a bit, please?

Soln

a c



b


considering the right angled triangle above

Pythagoras theorem has it that
a*2 + b*2 = c*2

a = opp
b = adj
c = hyp

Then it is very easy to substitute any of the letters with
Other ones e.g.
You could have x,y,z
X = opp
Y = adj
Z = hyp

So finding missing length is very easy.
If a = 3 ,c = 5 find b
We know that a*2 + b*2 = c*2
Therefore b*2 = c*2 – a*2
So b = square root of c*2 – a*2
B = the square root of 5*2 - 3*2
B = the square root of 25 – 9 =16
B = square root of 16
B = 4
In a like manner you solve equation concerning right angled triangles

You can solve this type of problems with these simple steps.

Read the question.
Get a pictorial impression of the question.
I.e. draw the diagram
3. Identify which is the opp,adj and hyp from the question and label
Them accordingly.
With the general rule or formula a*2 + b*2 = c*2.Fill in the gaps.
Smash the problem. And get the answer.

Cheers.

okusaga:
By Hook and crook,
it wasnt easy but we thank God ,,,

Ha ha ha! By Hook and crook? Real thanks to Jah,But let us know how you did it.

Hi Forumites,

I am a little bothered that despite how easy it is to gain admission into higher institution of learning these days. Many candidates that apply for these institutions do not get admitted even into their local Universities.
Why is it so?

Any way I am a graduate, but frankly speaking it was not easier getting admission in the 90s as it is now.
How did I get admission? You may ask me.
My getting admission then was a function of knowing exactly the right person and using my ability to get  what I wanted.
Simply put, I used what I had to secure admission.

Tell us how you got your own admission in your own time.

Cheers