2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } - Education (10)

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2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } - Education (10) - Nairaland

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Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Ennie123(f): 7:15pm On Feb 24, 2016

Please guys help me solve this;the magnification of an object 2cm tall when placed 10cm in front of a plane mirror is?

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by mathefaro(m): 7:40pm On Feb 24, 2016

Ennie123:
Please guys help me solve this;the magnification of an object 2cm tall when placed 10cm in front of a plane mirror is?

The magnification of any object placed in front of a plane mirror is 1 irrespective of the height of the object or its distance from the mirror since the images formed by a plane mirror are always the same size as their respective objects

1 Like

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Ennie123(f): 8:42pm On Feb 24, 2016

mathefaro:
The magnification of any object placed in front of a plane mirror is 1 irrespective of the height of the object or its distance from the mirror since the images formed by a plane mirror are always the same size as their respective objects

Okay...thanks

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 11:37am On Feb 25, 2016

mathefaro:
The magnification of any object placed in front of a plane mirror is 1 irrespective of the height of the object or its distance from the mirror since the images formed by a plane mirror are always the same size as their respective objects

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by freshkid144: 11:40am On Feb 25, 2016

help me solve ds question. the pressure of a given mass of gas changes from 200nm to 100nm, while its temperature drops from 400k to 346k. calculate the ratio of the final
volume of the gas to its initial volume

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 2:58pm On Feb 25, 2016

freshkid144:
help me solve ds question. the pressure of a given mass of gas changes from 200nm to 100nm, while its temperature drops from 400k to 346k. calculate the ratio of the final
volume of the gas to its initial volume

not totally sure, but here,

V1 = initial volume. V2 = final volume

from the question:

P1 = 200nm = (760mmhg x 200)/101325 = 1.5mmhg.

Similarly,
P2 = 100nm = (760mmhg x 100)/101325 = 0.75mmhg

T1 = 400k, T2 = 346K

(P1V1)/T1 = (P2V2)/T2

making V2 and V1 the subjects. I.e rearranging the equation to make ratio P2 to P1 the subject of the formula:

V2/V1 = (P1T2)/(P2T1)

inserting the values

V2/V1 = (1.5 x 346)/( 0.75 x 400)

V2/V1 = 519/300

519 : 300

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by freshkid144: 3:49pm On Feb 25, 2016

Geofavor:
not totally sure, but here,

V1 = initial volume. V2 = final volume

from the question:

P1 = 200nm = (760mmhg x 200)/101325 = 1.5mmhg.

Similarly,
P2 = 100nm = (760mmhg x 100)/101325 = 0.75mmhg

T1 = 400k, T2 = 346K

(P1V1)/T1 = (P2V2)/T2

making V2 and V1 the subjects. I.e rearranging the equation to make ratio P2 to P1 the subject of the formula:

V2/V1 = (P1T2)/(P2T1)

inserting the values

V2/V1 = (1.5 x 346)/( 0.75 x 400)

V2/V1 = 519/300

519 : 300

ur wrong

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Ennie123(f): 3:55pm On Feb 25, 2016

Please help me solve this:what quantity of aluminium is deposited when a current of 10A is passed through a solution of an aluminium salt for 1930s?

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Orezy5(m): 4:43pm On Feb 25, 2016

Ennie123:
Please help me solve this:what quantity of aluminium is deposited when a current of 10A is passed through a solution of an aluminium salt for 1930s?

Solution

Al_(aq)--->Al³⁺ + 3e^-

M=Eit

M=(27 x 10 x 1930)/(96500 x 3)

M=521100/289500

M= 1.80g

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Ennie123(f): 5:07pm On Feb 25, 2016

Orezy5:
Solution
Al_(aq)--->Al³⁺ + 3e^-
M=Eit
M=(27 x 10 x 1930)/(96500 x 3)
M=521100/289500
M= 1.80g

Thanks

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Orezy5(m): 6:50pm On Feb 25, 2016

Ennie123:
Thanks

You are welcome

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by freshkid144: 7:41pm On Feb 25, 2016

freshkid144:
help me solve ds question. the pressure of a given mass of gas changes from 200nm to 100nm, while its temperature drops from 400k to 346k. calculate the ratio of the final
volume of the gas to its initial volume

the answer, using the formula: PV=RT. where, R=0.082, T1=400k, T2=346k, P1=200Nm, P2=100Nm. solve for V=volume in both Equation(1) n (2) n dn find dia ratio

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 8:50pm On Feb 25, 2016

freshkid144:
ur wrong

ooops! What does "nm" mean? Type the question correctly.

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by freshkid144: 9:05pm On Feb 25, 2016

Geofavor:

ooops! What does "nm" mean? Type the question correctly.

it means NEWTON PER METRE SQUARE

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 11:04pm On Feb 25, 2016

A load is pulled at a uniform speed along a horizontal floor by a rope at 45^¤ to the floor. If the force in the rope is 1500N, what is the frictional force on the load?

Thankyoujesus, shyneptune, mathefaro, oxytocin, orezy5, etc.

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Nobody: 11:12pm On Feb 25, 2016

Geofavor:
A load is pulled at a uniform speed along a horizontal floor by a rope at 45^¤ to the floor. If the force in the rope is 1500N, what is the frictional force on the load?

.

Resolving to the horizontal
F=fcos $
F=1500 cos 45
F=1060.66
Velocity is constant therefore acceleration =0
And since acceleration is 0 that means that the body did not move... Therefore the applied force must have been counterbalanced by an equal and opposite force called friction.
This makes the friction to be equal to the horizontal force.
1060.66N

1 Like

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Oxytocin(m): 6:43pm On Feb 26, 2016

Only God knows what I did that the crazy bot banned me from education section yesterday sad

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Nobody: 7:23pm On Feb 26, 2016

Oxytocin:
Only God knows what I did that the crazy bot banned me from education section yesterday

the 'bot' was scared of your 'Physics prowess' grin

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Oxytocin(m): 12:47am On Feb 27, 2016

ShyNeptune:

the 'bot' was scared of your 'Physics prowess'

Lolz

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Nobody: 1:54pm On Feb 27, 2016

Geofavor come and tell us how your exam went oh grin

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Geofavor(m): 3:57pm On Feb 27, 2016

ShyNeptune:
Geofavor come and tell us how your exam went oh

yo! Go and marry your past questions cool

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Nobody: 5:23pm On Feb 27, 2016

Geofavor:

yo! Go and marry your past questions

seems you had a good time in the hall cheesy

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Orezy5(m): 7:36pm On Feb 27, 2016

Geofavor how was ur exam? Especially physics and chemistry?

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Oxytocin(m): 9:54pm On Feb 27, 2016

Lol
Geofavor.. Gist us how this thing went.. cheesy

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by druxy(m): 10:10am On Feb 28, 2016

A cell can supply currents of 0.4A and 0.2A through a 4.0 Ohms and 10.0 Ohms resistors respectively. The internal resistance of the cell is

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by druxy(m): 10:11am On Feb 28, 2016

A cell can supply currents of 0.4A and 0.2A through a 4.0 Ohms and 10.0 Ohms resistors respectively. The internal resistance of the cell is

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by druxy(m): 10:13am On Feb 28, 2016

A cell can supply currents of 0.4A and 0.2A through a 4.0 Ohms and 10.0 Ohms resistors respectively. The internal resistance of the cell is

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by druxy(m): 10:14am On Feb 28, 2016

A cell can supply currents of 0.4A and 0.2A through a 4.0 Ohms and 10.0 Ohms resistors respectively. The internal resistance of the cell is

Re: 2016 NAIRALAND JAMB TUTORIAL {the Physics Thread } by Nobody: 10:44am On Feb 28, 2016

druxy:
A cell can supply currents of 0.4A and 0.2A through a 4.0
Ohms and 10.0 Ohms resistors respectively. The internal
resistance of the cell is

2 ohms

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