₦airaland Forum

mathefaro:
I have pointed out an anomaly in your work in the post above. Check it out

mathefaro:
Oh Oh, my bad, I just saw what he did. I feel so embarrassed right now. Although I've spotted an error in his work

mathefaro:
like I said earlier, you've made a lot of assumptions which you ought not to including the fact that those sides you labelled K are equal. I could also make some assumptions totally different from yours and get another answer. I still believe there's a piece missing from the question

dejt4u:
here I got x to be 20°

dejt4u:
here I got x to be 20°

MrEDUCATION:
Please and please, I need a clear and detailed explanation to these questions...

1) Which of the following is not a factor of 12⁴ - 5⁴

A. 7
B. 13
C. 49
D. 169
E. 216
Difference of two squares
(12²-5²)(12²+5²)
(12+5)(12-5)(169)
(17)(7)(169)
The answer is 216 because it can't divide the product of 17x7x169 without remainder


2) A quadrant of a circle of radius 6cm is cut away from each corner of a rectangle 25cm long and 18cm wide. Find the perimeter of the remaining figure.
A) 38
B) 38+12π
C) 86 -12π
D) 86 -6π
Area of rectangle=25x2+18×2=86cm
4quadrant =one circle=2πx6=12π
Perimeter=86+12π-(4x2radius)
=86-8x6+12π
=38+12π


3) ln root 216 - ln root 125 - ln root 8 divided by
2(ln 5 - ln 3)
.
A. -3/2
B. 3
C. 3/4
D. -3/2
E. ln6 - 2ln5

TYPE THIS WELL
4) Find dy/dx,
if y=6x × 3 -5x × 2+1/3x × 2
TYPE THUS WELL

HellVictorinho:
X is 40°
AEB =180-(70+60+20)=30°
BDE=90°
X=180-(90+30+20)=40°
You can't use sine rule without any given side.

mathefaro:
can you kindly explain how?

mathefaro:
Sine rule? With no side at all? I'll really love to learn that o.

jackpot:
Please, kindly snap workings and post

chatinent:
Life like a mist, appears for a day and disappears the next day.

oyatz:
Ans= 30°

stanisbaratheon:
The major triangle and the smaller one up top.

mathefaro:
Sine rule? With no side at all? I'll really love to learn that o.

stanisbaratheon:
Is that not an equilateral triangle??

Martinez39s:
I will start working on it.

Rexmy:
What does the S stand for?
Is it that the radius of the circles are equivalent to the length of the square

stanisbaratheon:
120°

Rexmy:
Biko define your TRG

Rexmy:
The area is 394.24 square cm

Rexmy:
The area is 394.24 square cm

BrutusOj:
You did a nice sketch to solve the problem, but missed the workings at a point. If you look well again, it would have been better to do this, "from the center the of the big semi circle to the tip of the shaded circle is radius of the big semi circle which is 28 cm, and the radius of the small semi circle is 7cm, hence ur FC is also 7cm, there diameter of the shaded circle is = 28-7
=21cm
Hence, the radius of the shaded circle is 10.5 cm".

NB: I choose FC to represent the distance from F to the circumference of the shaded circle (the line joining F to the tip of the shaded circle)

mathefaro:
can you kindly explain how?

Kylekent59:
How I got my answer @ Mrshape

oyatz:
Mr Shape,i have a question for you sir.




Can we do it this way?

1) Calculate the area of the biggest semi circle.

2) Calculate the areas of each small semi-circles.

3) Add the areas of the four semi circles.

4) Subtract the summation from the
area of the biggestt semi-circle

Rezos017:
You are absolutely correct on the point u made dat the shaded circle is not really inscribed in the semi-circle and so the shaded circle cannot have its center where OF and ON become equal and that automatically OF and ON cannot be 14cm. It escaped my notice. Thumbs up! So d search for d solution continues, Mr Shape!

stanisbaratheon:
Cc: Mrshape

Having seen your solution, I want to bring your attention to this question I asked earlier about the line you said was a chord to the shaded circle.

The question is, if it's a chord to the shaded circle, why did you take your reference point at the center of the shaded circle?? You even went as far as designating it "R+7". That means you recognised that line going through both shapes as radii.