₦airaland Forum

TeflonBlixx:
The answers

Eben331:
A rope 5m long is fastened to two hooks 4m apart on a horizontal ceiling. To the rope is attached a 10kg mass so that the segments of the rope are 3m and 2m. Compute the tension in each segment. PLS SHOW YOUR WORKINGS!!

Sofia01:
ummmm this question... but I think the answer is rain water rain water contains caco3

micskales:
rain water is nt hard, if river is correct lake is also correct. river and lake are hard but not compare to borehole. borehole water contains dissolve air and minerals e.g Ca jand Mg, limestone,chalk from underground deposit. and u knw hard water is very good for the body, moreover soft water attack lead pipe because it leads to lead poisoning, so borehole water is the hardest.

Probity567:
Lake water has the highest degree of hardness,bcus of its stationary nature. It accumulate more soluble calcium,magnesium and iron(iii)salts. The other source are soft, bcus they are exposed to these salts.

Aceed:
how do you check after going there? By clicking on the admission status tile?

BiafranDel:
ok. How soon will they start for mbbs

Eben331:
Which of the following has the highest degree of hardness? (A) rain water (B) lake water (C) borehole water (D) river water PLS EXPLANATIONS WILL BE NEEDED!!

micskales:
it should lake, because it does not flow. lol!

TeflonBlixx:
1. C6H12O6 + 12O2 -- 6CO2 + 6H2O

Molar mass of the carbohydrate = 180g

Using first principle..

180g --- 264g
180000-- y

y = 180000 x 264/ 180

y - 264kg

2. still on it

3. Volume = 50cm^3
1cm^3 - 1g
T1 -- 293K
T2 -- 307K

H = Mc * change in theta
= 50 x 4.2 x (307 - 293)
= 2940J

Find the amount of Hcl that will liberate 2940J

Molar concentration = Amount/Volume

2 = a/ 0.05
a = 0.1

Therefore. .

0.1 mole liberate 2940J of energy
1 mole will liberate

1 x 2940/ 0.1

-- 29400J x 2
58800j or so
... I'm not sure about this one, will check later..

4. From the second law of electrolysis...

m/M x c = m/M xc

0.16/64 x 2 = m/32 x 4

5 x 10^-3 = 4m/32

4m = 0.16
m = 0.04
Therefore. . 32g---- 22.4
--------- 0.04 --- p
22.4 x 0.04/32 = p
p -- 0.028dm^3

Sulegee:
Guys I heard that "market women calculator" (not scientific calculator) is allowed for post utme, please how true is dis?

Eben331:
Pls bosses in the house, help me with these questions. CHEMISTRY (1) As a supplification, adult human can be considered to have a daily diet of 180kg of carbohydrates with empirical formula CH20. What mass of CO2 does a person produce each day if all the carbohydrates eaten is digested and oxidized? (C=12, H=1, O=16) (2) The solubility of AgCl at 50^oC is 1.024 per 100g of solvent, and at 10^oC, it is 2.15g. Calculate the mass of silver chloride precipitated when saturated solution of 50g AgCl was cooled from 50^oC to 10^oC. (Ag=108, Cl=35.5) (3) In an insulated container, 50cm^3 of 2M of HCl is at 293K. After reaction, the temperature of the mixture rose to 307K. Calculate the enthalpy change of reaction. (c=4.2J/g/K) (4) During the electrolysis of CuSO4 solution using platinum electrode, 0.16g of copper was deposited on the cathode. Calculate the volume of oxygen gas liberated at stp (Cu=64, O=16) PLS SHOW YOUR WORKINGS!!

Eben331:
Which of the following has the highest degree of hardness? (A) rain water (B) lake water (C) borehole water (D) river water PLS EXPLANATIONS WILL BE NEEDED!!

TeflonBlixx:
Are you not on facebook or whatsapp??

Becalina:
Hello, please has the post utme date been released?

micskales:
LET me explain the two calculations. firstly imagine a ladder 3m long laid down flat. Its weight 200N which is effective is 1.2m away from its bottom when u want to raise this ladder u have to raise it at the 1.2m i.e at the centre G. Now when u raise there, the force 200N has moved a distance of 1.2m so, W=f*s =240j.......but another force of 50N is acting at the top end, so if that also is raised vertically a distance of 3m has been moved by the force so..w =f*s =150J. Now total work =390j


*** F-fr=ma
10-fr=10*0.2
fr=10-2, =8
But Coeff.fr = fr/mg
=8/100 =0.08
fr = frictional force
mg =normal reaction i.e mass * gravity

TeflonBlixx:
0.063m is very correct

TeflonBlixx:
The question is from College physics. .

Workdone = 3 * 50 + 1.2 * 200

= 150 + 240
= 390J

Workdone required to lift the ladder through its length plus workdone required to raise it through its center of gravity

The last question is also patterned after Newtonian law calculations in college physics. .

Net Force = Ma

Applied F - Frictional force= Ma

10 - Fr= 10 * 0.2

Fr = 8N

U = Frictional force/Mg
U= 8/100

U = 0.08

TeflonBlixx:
1. 10^-15
2. A
3. 390Joules
4. A
5. 0.08

TeflonBlixx:
1. 10^-15
2. A
3. 390Joules
4. A
5. 0.08

TeflonBlixx:
Equation of reaction
4P + 5O2 --- 2P2O5
Using first principle. .
5 x 22.4dm3 of O2 ---- 284 of P2O5 y --- 35g
Cross multiply..
35 x 5 x 22.4= 284y
3920 = 284y
y = 13.80dm3
Since oxygen contains 20cm3 by 100cm3 of air
20 --- 100 13800 --- x
20x = 1380000
x = 69dm3 or 69000cm3

Gracy3535:
I need help on this The first stable product formed during photosynthesis is_____(a)starch (b)lipids(c)glucose(d)oxgyen

overcomer90:
The intensity of light falling on the film in a camera depend on the i. brightness of the object. ii. diameter of the aperture stop. iii. speed of the shutter. Which of the statements is/are correct/

A. i, ii and iii
B. i and ii only
C. i and ii only
D. ii and iii only
E. iii only

Gracy3535:
Calculate the volume of air required to produce 35g of phosphorus (v) oxide during the combustion of n excess of phosphorus.[O=16,P=31.All gas volumes measured at the same temperature & pressure.Air is about 20& oxygen by volume]

Dellybanky:
The length of a displaced pendulum bob which passes lowest point twice every second, assuming g is 10m/s is

Dellybanky:
A machine gun with a mass of 5kg fires a 50g bullet at a speed of 100ms*1: The recoil speed of the machine gun is (a) 0.5m/s (b) 3.5m/s (c) | m/s .(d) 2mls (e) 4 m/s

Dellybanky:
1.A lead bullet of mass 0.05kg is fired with a velocity of 200m8’1 into a lead block of mass 0.95kg.Given that the lead block can move freely, the final kinetic after impact is

Gracy3535:
Calculate the volume of air required to produce 35g of phosphorus (v) oxide during the combustion of n excess of phosphorus.[O=16,P=31.All gas volumes measured at the same temperature & pressure.Air is about 20& oxygen by volume]

Gracy3535:
Y did you minus 4 the. p.e=k.e
learning tho

OyedejiIfedayo:
yov did great but for number 10 the answer is cortex as stele means central part of vascular plant especially containing xylem and phloem so it is cortex in roots and parenchyma in dicot stem

so the answer is cortex