₦airaland Forum

seuntosyn:
Help solve this log1.728 base1.2

log a base b = log a /log b
Therefore, log1.728 base1.2 = log1.728 /log1.2
= log(1.2)³/log 1.2
= 3log(1.2)/log1.2
= 3

chibuezewilliam:
av u done your medical?

I'm at the centre at the moment waiting to have it done.

cassyrooy:
Okay, i'll try to look it up again.

Hope no new trick in filling the form?

No New trick, the next page automatically loads when the present one is submitted and saved

chibuezewilliam:
did u do yours at the cafe?

I only printed at a cafe, I filled the 8 parts on my phone

cassyrooy:
I encountered same thing.

completed and printed now

cassyrooy:
There's been an update on

www.admissions.ui.edu.ng

log into your portal to submit your medical details

It's not going past the first part o

Temiel:
I paid for accommodation receipt says school fees. Is anyone experiencing same thing here?

It's general

Haryanfe7:
thank God have paid my fees.........used atm card..........it was kinda fast and easy..............................thanks to mathefaro 4 d advise

you're welcome

parkparky:
chai c me c maths..tanx sir

you're welcome

For inverse and identity elements in binary operation,

e = identity element
a' = inverse of a

For any operation,
a * e = a and a * a' = e

For instance, in addition operation, the identity element e = 0(zero) since
a + 0 = a (no other number can replace 0 here giving us the same result, a)
While the inverse of a is -a since a + (-a) = 0.

Check the attached picture for #3 and #5

parkparky:
1. X*Y=X^Y(X power y). Find X if X*2=12-X.

2. If M*N=N-(M+2). find 3*(-5)

3..find m*n=m+n+mn.find the inverse of 5.if the identity element is 0

4.x*y=x2-y2/2xy find -5*3.

5.If a*b=ab+2(a+b+1). Find the identity element

Binary operation is just all about following the definition of a particular operator *,¥ and so on. Just substitute the given values and you see how easy it is.
Check the attached solutions

parkparky:
tanxs sir, i get like 5 Binary operation questions..i nid xplanations

Bring it on

parkparky:
Solve ₹x2-9=x+1

₹ is square root.
X2 is x square

First and foremost, square both sides to get
x² - 9 = (x + 1)²
x² - 9 = x² + 2x + 1, if you collect like terms from here, you get
2x = -10
x = -5

Although, if you come across this in your UTME, I'll SUGGEST(just a mere suggestion) you don't bother solving it, just test each of the options.

ShyNeptune:
You couldn't have said it any better....... you just hit the nail on the head. ....
@The bolded. That's 100% true.... The best brains are not ready to reach. While those who are teaching are absolutely nonchalant about their teaching Jobs.
Most of my seniors in secondary who were not able to secure admission into higher institutions came back to the same secondary school as teachers just after their post utme. Some came back Teaching chemistry, some physics, some mathematics, some English etc

It's Pathetic!

We students are at the losing end!

You see, that's what we're talking about, One can only teach what one knows, you can't give what you don't have, no matter how good you were in physics and chemistry in secondary school, there are some aspects you can't teach students...

Bhuumhite:
gist us abeg..

It's actually not what you think, na UI matter the provide me with all these their dues here and there

ShyNeptune:
Lol. The educational System in Nigeria is really bad... These things right here are basic things our secondary school teachers ought to have taught us long before now. But nope. Most of our teachers Are SSCE and ND holders who know not what they teach. Ideally an average student is supposed to score at least 250 in jamb while the good students are to hit scores like 390, 380, 370 etc..... but nope! What we see today are brilliant students scoring 250 and are jubilating. While the average students score 180 and so on.

It's really Lugubrious.

I had to quit school just so i'll learn physics at my own pace at home. And today I'm very glad I did so. I wasn't taught by any teacher. Everything I know today is as a result of self study.

How I wish I could hit the like button for multiple number of time. Weldone bro, more power to your elbow.
Actually, the real problem is that nobody wants to become a teacher anymore, the best brains are always running after white collar jobs, engineering jobs, they all want to become doctors. Even most of the few ones presently in the field have their minds fixed on jobs with bigger and better pay elsewhere, as a result of these, majority of those we have there impacting the supposed future leaders are only there because of condition and not because of their passion for the job.
May God help us....

O ga o, this is going beyond my budget o...

Geofavor:
What force has to be exerted on a mass 60kg to give it an acceleration of 10ms^-2 vertically upwards?
(g=10ms^-2)

thankyoujesus, mathefaro, oxytocin, shyneptune.

F = ma - mg ( -mg because the weight of the body is acting downwards as opposed the acceleration of the body) and g will also be negative since we're going against gravity, so it becomes
F = ma - m(-g)
F = ma + mg
F = m(a + g)

Haryanfe7:
evening guys.....I wan to pay my accommodation fee in d bank on Monday with my RRR.no.....please will I use d same RRR.no to pay 4 my school fees which am probably paying on Wednesday o .....nd what up wit d barcode ??....wha ar we using it 4??

cc Cassrooy
prassey
zezeny
khan.......morayho......Michael.....

if you've not paid, I'll advice you not to pay in the bank so as to get automatic update of your portal. Use atm instead

Whaylecs:
we no get choice than to chilax

Issokay

This is getting really frustrating..
Why did the management decide to put bank payments as one of the payment methods when they know they can't manage it efficiently like paying through internet banking (atm)?
For how long are we going to wait for our portals to be updated?

Geofavor:
how do you differentiate x^1/2/cosx. Do you differentiate them individually or you use the quotient rule?

Since, they're 2 different functions of x, you'll use quotient rule unlike x^1/2/x which is still one function of x

Geofavor:
[ X² - sqrt(X)] / X

find dy/dx

thankyoujesus, mathefaro, shyneptune, oxytocin, etc.

Change the sqrt(x) to index form and split the numerator into two parts each taking x as the denominator then differentiate whatever you get wrtx

lurlay:
having the same problem which bank did you use to pay

first bank in front of UI

lurlay:
what did you use

Bank payment(Remita)

lurlay:
what did you use

Bank payment(Remitaj

ShyNeptune:
Lol. @ Lee mealone



W = mg
W=4.68×9.8
=45.86 N

F net = Ma
=4.68×0.815
=3.81 N

Frictional force = net force - applied force
= 3.81N – 9.13N
= 5.32N

μ = Frictional force /Reaction
= 5.32/45.86
= 0.116

It's actually applied force - net force in this case

Geofavor:
this will mean that the object remained stationary. But the question stated that the objected had a constant velocity.

Fnet = Fapp - Ffr and since acceleration is zero, Fnet = 0

Geofavor:
A rightward force is applied to a 6-kg object to move it across a rough surface at constant velocity. The object encounters 15 N of frictional force. Pls find F_app ( applied force).

Thankyoujesus, shyneptune, mathefaro

I think it's 15N since there's no acceleration

Hmmmm! For how long do I need to wait before I begin to panic about the school fees. It's over 24hrs now that I've paid and it's not reflected on my portal

bayino:
No, you dont request for pin.if ure paying in cash u get ur RRR number and take it to bank then 1ce they pay ur portal will be automatically updated.

I don't know why it's taking so long for my own portal to be updated o. Paid since around 3.30pm

Khan1993:
You can call it pin cos a token(OTP) was sent to my number. But i tink thatS bank dependent.

Thanks

Khan1993:
Thanks boss.

please were you given a pin when you paid through webpay?