Dollyak's Posts
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dokyOloye:lol spilled my drink ![]() |
ajepako:Muslim? |
UncleJudax:You cannot stop terrorist but you can make it harder to carry out their acts. |
[s]quote author=RagnarLodbrok post=35766867] Airhead? Here I was thinking I was intuitive. Oh! Just shut up about shariah already! What do you mean behind times? Shariah hasn't even taken full effect yet, but it will, Gods willing. Like I always say, Sharks>salmon. When the seagulls follow the trawler it's because sardines will be thrown into the sea. What happens when there are no sardines? Don't worry, sassenach. [/s] [Soon the south will be free of the north completely, [s]and the south can indulge in what ever brand of faggotry they want.[/quote][/s] Make this very snappy. Your elites seems to love money more than your religion, so I doubt they would leave the wealthy southern region to satisfy their backward brothers and sisters in the north. |
avalontony:That is the scary part isn't it? Someone's feeling about their religion shouldn't excuse rational thinking... oh well *shrugs*. |
RagnarLodbrok:I normally don't reply airheads, but I will take exception to you this time. If dealing with facts makes me a bigot, then so be it. Majority of northern Muslims are a still behind the times. The wide support for sharia law in the north gives away the psyche of an average northern Muslim. I don't give a damn too much, as long as you lots disease doesn't affect the south. So there.. |
lurther:There are not many people that shares his views I would imagine |
Talk about demotion. Wow. |
IsraeliAIRFORCE:This is one of Nigeria fundamental problem. Seriously, Nigerians needs to make it less powerful and unattractive because until then you won't see any significant changes in the country. |
Op do kegel. I heard it helps. |
Teempakguy:check https://www.khanacademy.org you can learn from there too. |
Teempakguy:[1] http://www.amazon.co.uk/Further-Pure-Mathematics-L-Bostock/dp/0859501035 [2] http://www.amazon.co.uk/Further-Pure-Mathematics-Brian-Gaulter/dp/0199147353 [3] http://www.amazon.co.uk/Mathematical-Methods-Physics-Engineering-Comprehensive/dp/0521679710 [4] http://www.amazon.co.uk/AS-Level-Maths-Core-Revision-Guide/dp/1841467634 [5] http://www.amazon.co.uk/Mathematical-Puzzles-Diversions-Penguin-Science/dp/0140136355/ You can download them for free online. The first one is really good and comprehensive. https://www.khanacademy.org |
freshdude99:hey fresh dude. I am good you know. Yourself? What is happening with you today. |
This is the solution for question 3. A quick explanation. Equality occurs by having equilateral triangle on the sphere and then 5 points at each vertex.
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Teempakguy:They are more like a brain teaser rather than a hard core math. |
Teempakguy:You are wrong. Anyways, check my subsequent answers |
This is just a further mathematics. Don't see anything hard in these to be honest. This ain't no advanced calculus that's for sure. |
Adultnextdoor come and present your answer for question 3. So that I can determine whether you are right. |
Slimzjoe:Do you understand conservation of energy principle? |
Adiwana:hope you understand?
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Adiwana:a is the alpha=30 degrees. It is very hard to type equations using phone. Can't be bothered to use Microsoft Word lol |
solla22:t is not 11.9. How did you solve it. |
Obinoscopy:Factoring the coeeficient of friction mean the net force on the skier on the ski jump parallel to the ski jump surface is a combination of the gravitation force and the frictional force, For simplicity F(net)= mg (sinθ -μcosθ) The net work done on the skier as he travels down the jump is W= FL where L is the length of the jump, L=50/sinθ By the work-energy theorem the skier launches horizontally from the bottom of the jump with a speed v(=(2gh(1-μcotθ))^2 After the skier launches (and treating the launch point as x,y=0), the horizontal and vertical position of the skier are and at the moment of impact, (x,y)=(0,0) x=vt, y=-1/2 (gt) The landing spot is on the line , so we have a system of equations we can solve for t=3.794 seconds. v=29.919m/s check attached pictures to see how I solved for v More detailed calculation using conservation energy. .. Using the conservation of energy principle, the work done by friction must be equal to the change in the mechanical energy of the system (h = 50m, alpha = 30°), (1/2mv^2)-mgh=-μmgcosθ(h/sin30) This implies v=sqrt (2gh (1-μcot30)) During the fall, using parallel (x axis pointing 'downwards') and perpendicular (y axis pointing 'upwards') axes in respect to the hill, we can write down the variation of y with time as y=y[size=4pt]0[/size]+vsin30t-(g cos at^2)/2) Setting y=0 and solving for t(h'=5m) t=vtana/g (1+sqrt (1+(2gh'/v^2 tana^2)))=3.795
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Adultnextdoor:Just an explanation, thus it's not even complete. Shows you don't even know what you are talking about. |
Adultnextdoor:Hence you are so good in maths, can you solve question three so that we know your level? Or give us theoretical background answer to the question. Bear in mind I have just solved it. |
Okay I will bite for 3. |
I need to dig out my further math A-level text book to solve 3. When I have time. |
Number 4 is quite easy too as well. If you think about this. The total amount spent in the air by the skier is the same as the time taken to slope down(starting from the horizontal position) the whole distance of 50meters. thus distance gives =1/2 at t^2 Therefore 50=1/2 × gt^2 = 1/2 (9.8 )t^2 =50 solve for t T= 3.2 seconds Very easy because time only depends on gravity in this case. |
Number 2. Attempts. The second easiest after 4
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I can attempt 2. |
UnknownT:In the North, yes. It's unfair on the SW Muslims for you guys to lump them together with their northern counterparts. Let's be sensitive please. Say no more. |
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