₦airaland Forum

Geofavor:
Anybody solve this simultaneously

a + c = 0 . . . . . (1)
a + c = 1 . . . . . .(2)
-2a = -1 . . . . . . (3)

the question is not correct

Segipaul:
A cone in unstable equilibrium has it's potential energy A. Decreased B. Increased C. Unchanged D. Oscillating
my textbuk and d jamb past questns answer contradicts each other.
Textbuk ans-A. Decreased.....reason is: potential energy decreases as the height decreases
jamb past questn ans- B. Increases....reason is: The height of the centre of gravity of a body in unstable equilibrium is usually raised. Hence P.E increases.
Pls which is the right ans?

one thing I know for sure is that P.E increases with height while K.E increases with velocity. However, The cone with unstable equilibrium has a high potential(stored energy waiting to be released) to move farther from it's initial position when released/tilted/displaced

Vibra:
no

Kk thanks, just looking for enough info to know if one is safe to apply for both the DE and UTME.

Vibra:
go on

Did you meet the cutoff mark for the course you chose for UTME?

Vibra:
I don't know,I applied through d.e n jamb...that's what it also telling me when I tried checking for jamb but they can keep the jamb since the d.e worked

madam please do YOU mind me asking one or two questions from you?

A2J:
user review: I started using the earphone about two weeks ago. I tell you, the sound quality is mad, havent had any issues since and am using it with my tecno phantom Z.

NB: I didnt buy the earphone from initialize but the post counts suggest he's legit.

thanks

I already know about these, you and I know that these doesn't mean it can last long, none of the specs suggests that. I'm only asking for a user review

initialize:
Description

Model: Xiaomi Piston 2 Earphone with Remote & Mic

100% Brand New

Comfortable custom fit

Innovative design

Rich bass generated from powerful driver

High rated power and great sensitivity response

Resistance to pull by using Kevlar Fiber material

Double Damping Balance System to Make Sure the Pure Sound

Fit for all Phones, Tablets, Music Player and PC

Plug: 3.5MM standard plug

Line control key: Play Key(Can stop or start music)

Speaking key:Both Can Answer the calls and Hang up the call

Volume Control: Support Volume Up/Down

Style: In-Ear

Connectors: 3.5mm

Package: Yes

Use: Portable Media Player

Function: Noise Cancelling,Microphone

Communication: Wired

Model Number: xiaomi Piston 2

Earphone weight: 12g

Cable Length: 1.2M

Remote Control: Yes

Operative Manufacting Standard: EN50332-2

Cable Cell Mater: Enameled Copper wire

Speaker Resistance: 16 Ohm

Earphone Sensitive: 93 dB

Maximum Practical Power: 5 mW

Frequent range: 20-20,000Hz

initialize:
#2,000

I hope it'll last long sha, in tired of these 250 earphones per week

initialize:
Everything is for sale

Oga init, how much is the xiaomi piston 2 earphone.

Thewhizzkid1:
ALRIGHT SIR. THANK YOU VERY MUCH FOR THE EXPLANATION.WE LEARN EVERYDAY. PLEASE CHECK OUT THE INFORMATION IN THIS SITE http://www.grammar-monster.com/lessons/than_I_me_than_he_him.htm IT SAYS "THAN ME" IS ALSO CORRECT. BUT WHEN USING "THAN I", WE SHOULD PUT IT IN A FULL SENTENCE TO AVOID AMBIGUITY. e.g "John is taller than I am" instead of "John is taller than I"...Please check d site. Mathefaro please check d site also.

lol! Why do you want me to check it out? I actually decided not to post on the matter. The truth is that this is not the first time i've engaged in arguments on this same context and i've realised that people are only willing to stick to what they've read in a textbook or what their teacher taught them. I have LOTS of references that backs up the fact that the use of "me" in this context is very correct albeit for informal speech only. One of the references is the OALD. Just check out the USAGE section of the word "me" in the Oxford advanced Learners Dictionaries. It settles everything. We all need to know that the language evolve everyday and we must always update ourselves not for exam purposes only

In definitely in for this

tuwayz:
What is the locus of a dog tethered to a pole with a rope of 4m

the locus is the circumference of a circle if radius 4m. So just use 2pi*r

tuwayz:
Find the value of k if y-1 is a factor of y^3+4y^2+ky-6

since y - 1 is a factor if f(y), then f(1) = 0. Which means substituting 1 for y in the given function and equating it to 0. Thus, we have
1³ + 4(1)² + k(1) - 6 = 0
==> 1 + 4 + k - 6 = 0
==> k - 1 = 0
K = 1

Kuzaku:
still sorry to drag you back, I'm reading from page 0.

Can we say Seun Osewa had verified his account before the data loss incident occured

Thanks

yes, it's a correct statement

Destilo:
@mathfaro n other maths expert in d house help me solve dis...am not sure of My answers...
.
.
1. Find the distance between the point (4, 3) and the point common to the lines 2x - y = 4 and x + y = 2

Thank you

the point common to the lines 2x - y = 4 and x + y = 2 is (2, 0) which is a solution if the simultaneous equation.
Hence, the distance between the points (4,3) and (2,0) using the formula sqrt( (x2 - x1)² + (y2 - y1)²)
==> sqrt((2-4)² + (0-3)²)
==> sqrt((-2)² + (-3)²)
==> sqrt(4 + 9)
==> sqrt(13)
= 3.6 units

Destilo:
@mathfaro n other maths expert in d house help me solve dis...am not sure of My answers...
.
.
1. Find the distance between the point (4, 3) and the point common to the lines 2x - y = 4 and x + y = 2.

.

2. A(5, 3) and B(2, -1) are two vertices of a square ABCD and D is on the x-axis. Find the coordinates of C and D.

.

3. A point P moves so that it is equidistant from points L(-2, 2) and M(5, 1).
a. Find the locus of P
b. Show that the locus of P is a perpendicular bisector of the line LM.

.

4. The vertices of a parallelogram PQRS are P(a, 7), Q(7, 5), R(0, 4) and S(6, 2). Calculate
a. the gradient of PQ
b. the value of a
c. the gradient of SR


Thank you

I've been busy lately but I'll see to the questions when I'm through for the day.

I'm not sure you guys are prepping for UTME with the kind of questions you're throwing in especially the mathematics. If you feel like flexing muscles with strong questions, you can move over to the nairaland maths clinic. Most of these questions you guys are posting are beyond the scope of UTME.

princessdebbby:
yea tnx a lot..

you're welcome, glad I could be of help.

princessdebbby:
although I understand all ur soln but for d no 1 I want to knw y u divided by 5/18 inorder to convert to m/s.

I believe you understand the fact that we had to convert the km/h to m/s, then You also need to understand that 1 km/h = 1000m/3600s and if you simplify that by cutting with 200, you'll get 5/18, I.E 1km/h = 5/18 m/s, hence to convert from km/h to m/s, just multiply by 5/18

For no 2 I want to knw y we can't just solve straight by usin d=vt cos if I use dz formular I wil get 180 rada dan 90.

you simply can't do that because the body is accelerating uniformly, so the velocity is constantly changing starting from 0(rest) until it finally gets to v, assuming, the body is moving with a uniform velocity v, then You can apply that formula of yours(s = vt) directly. I think you need to go through the velocity-time graph concept.

Nd 4 no 4 whr did u arrive at d formula v=u-gt..thanx

Any time a body moves Uber the influence of gravity(dropped from a height or thrown/projected vertically upwards) the S in the normal equations of linear motion changes to "h" while a changes to +g( dropping objects, since they're moving with/towards gravity) or -g(vertically projected objects, since they're moving against gravity) therefore, the normal equation v = u + at changes to v = u + gt for dropping objects or v = u - gt for objects projected vertically. Likewise V² = u² + 2as changes into V² = u² + 2gh and V² = u² - 2gh.
I hope you understand it now.

peacemaranatha:
pls forget about giayu and go 4 quality phones i give you umi c1 and doogee 550 you wil 4get giayu

you obviously haven't used jiayu, try g4s for a start before you make your conclusions.

deb6:
@Thewhizzkid1, ur answer is right but am confuse i thought the answer should be m=7 & n=3 from 21m=9n. pls explain

Divide both sides by 21n ( the 21 to remove the coefficient from m while the n to bring the unknown variables m and n together)

I'm very happy that people have started coming out to contribute, I can now sit back and relax. Keep up the good work guys..

smartdave1:
Thanks anyways, i think the bolded is a typographical error.

it isn't an error. It's actually the correct formula for average velocity. Use it in the question you posted earlier and compare the answer with the one you were given

Segipaul:
permit me to find acceleration ist
v=u+at, v=60m/s u=15m/s a=? t=20sec
60=15+20a, 45=20a, a=2.25m/s^2
c. Distance travelled: S= Ut+1/2at^2
S=15 X20 + 1/2 X 2.25 X (20)^2
S=300+450
S=750m....daz distance travelled
a. The average speed =distance/time taken
A.v=750/20
A.V=37.5m/s

Although, you can also get the average speed by using the formula (v + u)/2, it will save more time


NB: There's a difference between knowing the solution to a question and knowing the fastest method to use. so please always look for the fastest method. Also, i'll advice you guys to start practicing questions with timing

Segipaul:
permit me to find acceleration ist
v=u+at, v=60m/s u=15m/s a=? t=20sec
60=15+20a, 45=20a, a=2.25m/s^2
c. Distance travelled: S= Ut+1/2at^2
S=15 X20 + 1/2 X 2.25 X (20)^2
S=300+450
S=750m....daz distance travelled
a. The average speed =distance/time taken
A.v=750/20
A.V=37.5m/s

Thanks for filling in for me, i've been busy since mawnin

Benjaminbest:
displaying corrupted file on my fone

ok, download directly from here

http://campusportal.com.ng/files/JAMB-Syllabus/Biology.pdf

tuwayz:
. Thanks bro, I was kind of confuse on how to go about It, I took the reciprocal of the left hand side because of the negative power but got it wrong, thanks a lot

you're welcome

tuwayz:
Please can somebody help me out on this? Find x, 8x^-2=2/25

8x^-2 = 2/25 (Note that the power(-2) is meant for x alone since there's no bracket)
==> 8/x² = 2/25
So by cross multiplication,
==> 2x² = 25*8
==> 2x² = 200
Divide both sides by 2
==>x² = 100
Find the square root of both sides
==> x = 10

Biology syllabus in pdf format

Thewhizzkid1:
"I" is a singular pronoun but it does not attract singular verbs...It only attracts plural verb...U can't say "I eats" but "I eat"...Ur information on has, have and had is wrong also...Has and have are used in d present perfect tense not present tense..Wondering why someone didn't correct dix guy earlier..Look at how he's giving wrong information in an insulting way..

check the previous pages, it has been corrected.

Benjaminbest:
does any one here have any idea on biology jamb syllabus

I'll provide that later in the day, duty calls for now