₦airaland Forum

labodinho: Residential too gud o if u re fully loaded,u go teach us too yur O.Y.O reading too.

labodinho: Me dey hide for Ladipo,oshodi.U'r based on personal reading or tutorial tinz?i dey start tutor tomm.

Mr Calculus: Tnx chief

labodinho: @ Mr Calculus,aw u dey nah,hope u kuming to stay wif us here?? @ortarico,i've seen d solution n tanx o.*LGT* whr do u resyd specifically? @all,una well done o.

@farano:
u got it right but after my 2nd question i will give u an award lol. Wat of #200

@farano:
Name the personalities immortalized on these currencies.$1, $2, $10, $100

@farano:
Simple morning questions. Name the personalities immortalized in nigeria currencies. #5 #10, #20, #50, #100, #500, #1000

donedy: Your calculation is right, per say. But next time try to state the condition under which the solution is valid. You cannot just divide both sides of the equation by an algebraic expression without some conditions.

Basically, when you divided both sides 2y - 4, you should have explicitly stated "for y != 2", for deduction to be valid.

labodinho: Wadup peeps,aw's tinz in here? I've wasnt chanced to come on here through out yestrdy.@ ortarico n oladoya,u guyz r jst superb out thr n in here.tanx for yur attempts n ma No 2 still pend sha.@ lurve,aurora and yemmy,i wonder whr dos guyz r,i've nt seen der post,mayb busy.Morning...more medic shuld kum o.

echibuzor: .
.


When u hear in maths that A is a function of b then it means that A is the subject of the formular... , I hope that is a major hint to solve no 2.. Workings loading, I am mobile at the moment...

Ajani2010: mehn afta i killed that question...well i didnt observed the rule....@oladoya if i catch u @ortarico this guy don turn me to mumu ooo...

oladoya: Here comes the aswer, first of all let us understand one thing....
No in base two should be from 0-2, No in base three= 0,1,2.
Meaning the highest number in base X= x-1.
I said 1234 in base 3
already i have gone wrong with the rule, no in base 3 should not be bigger than 2 and here we have 3 and 4. Its just a question to test how careful we are in answerin questions

Edis4christ: 3). dy/dx=6x^2 + 15x^4
dy=(6x^2 + 15x^4)dx
Integrating both sides, you will have
note:integratind dy=y
So y=6x^3/3 + 15x^5/5
y=2x^3 + 3x^5
But y=7 nd x=2
So 2x^3 + 3x^5 - y=0
2(2)^3 + 3(2)^5 - 7=0
All=105
Therefore y= 2x^3 + 3x^5 +105

oladoya: miss farano, i told u to becareful but u were not. @ no2 answer u got it right but no1 u missed it try again. Perhaps i should say nobody here can solve that question, no be pride ooo but fact

labodinho: yea,i jst got dah,kan u n @ all check on these....(1)solve the equation _/x+7=x-5 (2).....Let Y=4x+3/2x-5,write x as a function of y. (3).....If dy/dx=6xrtp2 + 15xrtp4 and y=7 when x=2.Find y N.B:rtp=rays to power....tanx

doubleDx: Greetings Chief Ortarico!

I do not have a 2go or whatsapp ID, perhaps we could chat on yahoo messenger or skype sometime?

@farano:
1. Ist of all cnvert 1234.233 base 3 to base 10 .: (1*3^3)+(2*3^2)+(3*3^1)+(4*3^0)+(2*3^-1)+(3*3^-2)+(3*3^-3) =27+18+9+4+2/3+3/9+3/27=58+10/9 which is 58+1.1111=59.12base10. Then convert 59.12base10 to base 5 which is 214.03base5. The only number which is both even & prime is 2

doubleDx: Question 1

√(x+7) = x - 5

Square both sides to get rid of the square root=>

√(x+7)² = (x - 5)²
(x+7) = x² - 10x + 25

x² - 11x + 18 = 0
x² - 9x - 2x + 18 = 0
x(x - 9) - 2(x - 9) = 0
(x - 9)(x - 2) = 0

:. x - 9 = 0 or x - 2 = 0

x = 9 or x = 2

Others loading......

oladoya: well done jawe my oga, am already dizzy dats why i made a mis(c)ake in no2

oladoya: for number 1...
Average age=mean
ifthe mean age of 6children = 23.5
their total age will be 6*23.5=141;
also the mean age of their parent is 29.5
the sum of their age is 29.5*2=59
the total age of the whole family = 59+141=200
here now we have number 8 persons
then mean age of the total family= 200/8=25yrs..... As for number two answer equals 2y/x-y..

labodinho: Eehn eehnn!!!......Ortarico,na so una dey do ham abi? U don go gada all yur brova frm ministry of maths guru shey?? Una b wicked guru's o,dat ma own numba two don hang here o,i neva finish..mai c yur numba one working too.

oyestephen: @labodinho thanx for the advice. God'll teach me what to do
@oladayo welcome and success...
Make una no vex, please help me solve this;
In a family, the average age of 6 children is 23 1/2 yeaers. If the average age of the father and mother is 29 1/2 years. Find the average age of the family
A)28 years b)22 years c)24 years d)26 years e)25 years
2. X+y/x-y - x-y/x+y

Mr Calculus: plz guyz need ur help:::Convert 1111.100110 base 2 to base
12 and 123.X4 base 12 to base 2 without converting first to base 10

oladoya: Here comes the workings....
The first term of the AP plus that of the GP= 3 and remember the both has the same first term so....
AP: a=3/2
GP:a=3/2
AP:2nd term = a+d and the 3rd term = a+2d
GP:2nd term= ar and 3rd term = ar^2.
if the sum of their 2nd term is = 3/2 then...... a + d +(ar) = 3/2
since we know the value of (a) then sub a = 3/2.
3/2+d+(3r/2)=3/2, multiply trough by 2: 3+2d+3r=3, collect like terms
2d+3r=0...(1) also if the sum of their 3rd term is = 6, then a+2d+ar^2=6, then 3/2+2d+3r^2/2=6 this gives 3+4d+3r^2=12
4d+3r^2=9.....(2)
now we have
2d+3r=0...(1)
4d+3r^2=9...(2)
from equ. 1
d=-3r/2....(3) sub. This for d in equ. 2
4d+3r^2=9
4(-3r/2)+3r^2=9
-6r+3r^2=9
3r^2-6r-9=0
solving quadratically we have
r= 3 or r= -1
since we were told that the GP has positive values then the commom ratio should be positive which is 3, now sub r=3 in equ. 3
d=-3r/2
d=-3(3)/2
d=-9/2
now the fifth term both
AP:a+4d
3/2+4(-9/2)=3/2-18=-33/2
GP:ar^4
3/2(3)^4=3/2(81)=243/2
243/2+(-33/2)=243/2-33/2=210/2 = 105.

oladoya: Here comes the workings....
The first term of the AP plus that of the GP= 3 and remember the both has the same first term so....
AP: a=3/2
GP:a=3/2
AP:2nd term = a+d and the 3rd term = a+2d
GP:2nd term= ar and 3rd term = ar^2.
if the sum of their 2nd term is = 3/2 then...... a + d +(ar) = 3/2
since we know the value of (a) then sub a = 3/2.
3/2+d+(3r/2)=3/2, multiply trough by 2: 3+2d+3r=3, collect like terms
2d+3r=0...(1) also if the sum of their 3rd term is = 6, then a+2d+ar^2=6, then 3/2+2d+3r^2/2=6 this gives 3+4d+3r^2=12
4d+3r^2=9.....(2)
now we have
2d+3r=0...(1)
4d+3r^2=9...(2)
from equ. 1
d=-3r/2....(3) sub. This for d in equ. 2
4d+3r^2=9
4(-3r/2)+3r^2=9
-6r+3r^2=9
3r^2-6r-9=0
solving quadratically we have
r= 3 or r= -1
since we were told that the GP has positive values then the commom ratio should be positive which is 3, now sub r=3 in equ. 3
d=-3r/2
d=-3(3)/2
d=-9/2
now the fifth term both
AP:a+4d
3/2+4(-9/2)=3/2-18=-33/2
GP:ar^4
3/2(3)^4=3/2(81)=243/2
243/2+(-33/2)=243/2-33/2=210/2 = 105.

oladoya: yea i was given 203 and now i think i have the lowest mark in here.

yemmytcm: youre welcome mr.AY,whats ya jamb score ? Oga Ortarcio,you don av another person join una o....physiotherapist where are you pple na

oladoya: God pls am beging you i dont want to stay at home this year ooo. Going for economics had 203 i think am still gonna have 90 for post ume, may God help. Any econs aspirant from oyo shuld add me on 2go olalere310 lets reaf together